[SOLVED] Pagination HELP!!!

[almystersv]

Hi Guys,

 

So far I have come up with this code which does display the first 10 products in my database but the links to the Next 10, PREV etc are not showing up as links.

 

Here is my code

<?php 
require "connect.php";

    $limit          = 10;                
    $query_count    = "SELECT count(*) FROM product";     
    $result_count   = mysql_query($query_count);     
    $totalrows      = mysql_num_rows($result_count);  

    if(empty($page)){ 
        $page = 1; 
    } 
         

    $limitvalue = $page * $limit - ($limit);  
    $query  = "SELECT * FROM product LIMIT $limitvalue, $limit";         
    $result = mysql_query($query) or die("Error: " . mysql_error());  

    if(mysql_num_rows($result) == 0){ 
        echo("Nothing to Display!"); 
    } 

    $bgcolor = "#E0E0E0"; // light gray 

?>
<table width ="100%" border="1">
<?php 
     
    while($row = mysql_fetch_array($result)){ 
        if ($bgcolor == "#E0E0E0"){ 
            $bgcolor = "#FFFFFF"; 
        }else{ 
            $bgcolor = "#E0E0E0"; 
        } 

    echo("<tr bgcolor=".$bgcolor.">\n<td>"); 
    echo($row["URN"]); 
    echo("</td>\n<td>"); 
    echo($row["productName"]); 
    echo("</td>\n</tr>"); 
    }

    echo("</table>"); 

    if($page != 1)
{  
        $pageprev = $page-1;  
        ?>
	<a href="StationaryOrdersTEST.php&page=$pageprev">PREV".$limit."</a>
<?php  }
else
{ 
        echo("PREV".$limit." "); 
    } 

    $numofpages = $totalrows / $limit;  
     
    for($i = 1; $i <= $numofpages; $i++){ 
        if($i == $page){ 
            echo($i." "); 
        }else{ 
         ?>
	 <a href="StationaryOrdersTEST.php?page=$i">$i</a>
	 <?php 
        } 
    } 


    if(($totalrows % $limit) != 0){ 
        if($i == $page)
	{ 
            echo($i." "); 
        }
	else{ 
	?>
	 <a href="StationaryOrdersTEST.php?page=$i">$i</a>
	 <?php
        } 
    } 

    if(($totalrows - ($limit * $page)) > 0){ 
        $pagenext = ++$page; 
          
        ?>
	<a href="StationaryOrdersTEST.php?page=$pagenext">NEXT".$limit."</a>
	<?php
    }else{ 
        echo("NEXT".$limit);  
    } 
     
    mysql_free_result($result); 

?> 

 

Any help would be grand.

 

cheers

[pocobueno1388]

There is a bug in the PHPfreaks pagination tutorial, here is a revised version of the tutorial

 

<?php

$limit          = 10;
$query_count    = "SELECT count(*) FROM table";
$result_count   = mysql_query($query_count) or die("Error: " . mysql_error());
$totalrows      = mysql_result($result_count, 0, 0);
$numofpages     = ceil($totalrows/$limit);

if (isset($_GET['page'])) $page = $_GET['page'];
else $page = 1;

$offset = ($page - 1) * $limit;
$query  = "SELECT * FROM table LIMIT $offset, $limit";

echo  $query .'<br>';
$result = mysql_query($query) or die("Error: " . mysql_error());

//Exit if no records to display
if (mysql_num_rows($result) == 0) {
    exit("Nothing to Display!");
}

while ($row = mysql_fetch_array($result)) {
    echo $row['col']."</br>";
}


//Enable the Prev link if not first page
if ($page > 1) {
    echo("<a href=\"index.php?page=".($page-1)."\">PREV</a> ");
} else {
    echo("PREV ");
}

//Create links for each page in report
for ($i=1; $i<=$numofpages; $i++) {
    if ($i == $page) {
        echo "$i ";
    } else {
        echo "<a href=\"index.php?page=$i\">$i</a> ";
    }
}

//Enable the Next link if not last page
if ($page < $numofpages) {
    echo("<a href=\"index.php?page=".($page+1)."\">NEXT</a>");
} else {
    echo("NEXT");
} 

?>