Plain Flailing Posted February 10, 2008 Share Posted February 10, 2008 I'm trying to code a simple webring using PHP and MySQL, but the following chunk of code... $con = mysql_connect($dbhost,$dbuser,$dbpass); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db($dbname,$con); $query = "SELECT id, name, url FROM webring_sites"; $result = mysql_query($query,$con); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $allSites[$row]['id'] = $row['id']; $allSites[$row]['name'] = $row['name']; $allSites[$row]['url'] = $row['url']; } mysql_free_result($result); mysql_close($con); ...is giving me these errors: <b>Warning</b>: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in <b>/home/####/public_html/webring/webring.php</b> on line <b>40</b><br /> <br /> <b>Warning</b>: mysql_free_result(): supplied argument is not a valid MySQL result resource in <b>/home/####/public_html/webring/webring.php</b> on line <b>47</b><br /> I don't understand what the problem is with $result. Can anyone help me out? Quote Link to comment Share on other sites More sharing options...
Barand Posted February 10, 2008 Share Posted February 10, 2008 Check for errors in query $result = mysql_query($query,$con) or die(mysql_error()); Quote Link to comment Share on other sites More sharing options...
Plain Flailing Posted February 10, 2008 Author Share Posted February 10, 2008 Thanks Barand. I'm almost too embarrassed to admit the cause of the problem, but just in case it helps another idiot searching the forum later: I'd simply forgotten to update a field name in my code after changing it in the database... :-X Quote Link to comment Share on other sites More sharing options...
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