digitalmartyr Posted February 12, 2008 Share Posted February 12, 2008 so whats going on here is that if i comment out the area where the limit is added onto the query the query works and my data gets displayed. if i try to add into the mysql query the limit statement, its goes wrong. what can i do? <?php require('dbconnect.php'); // if($_GET['page']) { $pagesection = $_GET['page']; } if(isset($_GET['cat'])) { $prodCat = $_GET['cat']; echo $prodCat; } // if(!(isset($pagenum))) { //no page number default to 1 $pagenum = 1; } //get sql results and count //see what cat is called if($prodCat == 'all') { $data = mysql_query("SELECT * FROM products"); } else { $data = mysql_query("SELECT product_name, product_price, product_dscrb, product_img FROM products WHERE category = '$prodCat'"); } // $rows = mysql_num_rows($data); //number of results per page $page_rows = 3; //tells the page number of our last page $last = ceil($rows/$page_rows); //make sure page number isnt below 1 or more than maxpages if($pagenum < 1) { $pagenum = 1; } elseif ($pagenum > $last) { $pagenum = $last; } //sets the range to display in our query //$max = ' LIMIT '.($pagenum-1) * $page_rows.','.$page_rows; //$maxquery = $data.$max; //echo $maxquery; //run query to display results *style for display* //add $max to it for limiting result //$data = mysql_query($maxquery); while($info = mysql_fetch_array($data)) { echo '<div id="productThumb">'; echo '<h3>product id: '.$info['product_id'].'</h3>'; echo '<h2>product name: '.$info['product_name'].'</h2>'; echo '<img height="140" width="100" src="'.$info['product_img'].'"</img>'; echo '<span>Product Describtion '.$info['product_dscrb'].'</span>'; echo '</div>'; } //shows user what page they are on and the total number of pages echo "<p>--page $pagenum of $last--<p>"; //check if on page 1, if so we dont need a link to the prev page or first page so do nothing //if we arent on page 1 we generate links to the first page and to the prev pages if($pagenum == 1) { } else { echo "<a href='{$_SERVER['PHP_SELF']}?page=$pagesection&pagenum=1'> <<-First</a>"; echo " "; $previous = $pagenum-1; echo "<a href='{$_SERVER['PHP_SELF']}?page=$pagesection&pagenum=$previous'> <-Previous</a>"; } //this does the same above, only checking to see if we are on the last page //and then generating the NExt and Last link if($pagenum == $last) { } else { $next = $pagenum+1; echo "<a href='{$_SERVER['PHP_SELF']}?page=$pagesection&pagenum=$next'>Next-></a>"; echo " "; echo "<a href='{$_SERVER['PHP_SELF']}?page=$pagesection&pagenum=$last'>Last->></a>"; } ?> Quote Link to comment https://forums.phpfreaks.com/topic/90642-it-will-say-pagination-and-sql-query-problem/ Share on other sites More sharing options...
nethnet Posted February 12, 2008 Share Posted February 12, 2008 You are setting your $data variable equal to the mysql function mysql_query(), which will return a resource handle to the database, not a string. When you try to concatenate your LIMIT clause onto your query you are attempting to add it onto the resource handle and it is returning an error. In your first if/else statement that sets the value of $data depending on the value of $prodCat, change it to this: <?php if($prodCat == 'all') { $data = "SELECT * FROM products"; } else { $data = "SELECT product_name, product_price, product_dscrb, product_img FROM products WHERE category = '$prodCat'"; } ?> That way you are appending your LIMIT clause onto the end of the $data string, and not the $data resource, so when you use it later in the mysql_query() function it is valid SQL syntax. Theo Quote Link to comment https://forums.phpfreaks.com/topic/90642-it-will-say-pagination-and-sql-query-problem/#findComment-464665 Share on other sites More sharing options...
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