Can some one help me on this

[jeet_0077]

Hi I am trying to read the contents of the following link:

 

$link = 'http://sports-ak.espn.go.com/broadband/espn360/upcomingEvents';

$content = file_get_contents($link);

$res = json_decode($content, true);

 

the link is returning json out put.

But when I use json_decode function its not returning anything.

 

Can you please tell me what went wrong.

Or can you  please suggest me what has to be done for that.

 

Thanks

[cooldude832]

first off is the json library loaded in your php server

 

secondly what specifically is happening because the function doesn't return anything in terms of output it runs a decode on that variable.

[jeet_0077]

Thanks for the reply..

 

Yes I have json installed on the server.

 

I just got the contents using file_get_contents(). Upto this it works fine.

 

Next I have to get the json return value in an array so that I have  all the values.

 

I used something like:

$var  = json_decode($contents, true);

 

tried to do

print_r($var); but showing nothing.

 

But is should return the array. In subsequent steps when I try to use any index saying that undefined array index.

[cooldude832]

and your error reporting is where?  $var is defined assuming jscon is working properly so print_r($var) should at least return an empty array as you stated

 

Thus this means yuor issue is in jscon

[rhodesa]

There are 2 issues:

 

1) You need to remove the "Events =" off the front of the data

2) There are some special chars in there that the json_decode function does like, specifically: ñ

 

This worked for me:

 

<?php
  $link = 'http://sports-ak.espn.go.com/broadband/espn360/upcomingEvents';
  $content = file_get_contents($link);
  $content = substr($content,strpos($content,'{'));
  $content = utf8_encode($content);
  $res = json_decode($content,true);
  var_export($res);
?>

[jeet_0077]

rhodesa,

 

Thanks it worked for me.