Php Date help.

[Vivid Lust]

This code will not work properly, please help!

 

$dob = 28-08-92 
$today = date("d-m-Y");
$age= $dob-$today;

 

When echoed $today it displays 11 which is wrong.

 

Please help!

[wildteen88]

Could you explain what are you wanting to do with the code? Get the persons age?

[Vivid Lust]

yes, get a persons age.

[wildteen88]

Just subtract their brith year from the current year, eg:

$dob = '28-08-92';

$birthYear = date('Y', strtotime($dob));

$curYear = date("Y");

$age = $curYear - $birthYear;

echo 'Your age is: ' . $age . ' years old';

[Vivid Lust]

Could you modify to include month and day?

 

So that the age is accurate?

 

Thanks.

[spfoonnewb]

<?php
function birthday ($birthday) {
list($year,$month,$day) = explode("-",$birthday);
$year_diff = date("Y") - $year;
$month_diff = date("m") - $month;
$day_diff = date("d") - $day;
if ($month_diff < 0) $year_diff--;
elseif (($month_diff==0) && ($day_diff < 0)) $year_diff--;
return $year_diff;
}
echo birthday("1980-07-02");

?>

 

http://snipplr.com/view/1357/calculate-age/

 

http://www.google.com/search?hl=en&q=php+get+age&btnG=Search