dc_jt Posted February 19, 2008 Share Posted February 19, 2008 Hi Im having a problem with the following: I have four images, a red image, vanilla, chocolate and caramel. These are in a form and upto two need to be selected, no more! I have created four hidden checkboxes to act for each colour and now need to somehow say if the red checkbox is checked then show a certain image else show a different image. How do I do this? Here is an example so far of the red button: function checkColour(myColour) { if (document.getElementById(myColour).checked == false){ document.getElementById(myColour).checked=true; } else { document.getElementById(myColour).checked=false; } } <li><a onclick="javascript:checkColour('red');"><img src="../assets/images/shop/flavour-red-off.gif" alt="red" width="30" height="30" border="0" /></a>Red</li> <div style="display:none"> <input name="red" type="checkbox" id="red">red </div> As you can see at the moment the checkColour function checks the hidden checkbox, however I now need to change the flavour-red-off.gif image to flavour-red-on.gif if its checked. Hope someone can help THanks Link to comment https://forums.phpfreaks.com/topic/91846-change-image-when-selected/ Share on other sites More sharing options...
dc_jt Posted February 19, 2008 Author Share Posted February 19, 2008 Its ok I have done it now. The only thing I need to do now is count how many have been selected. Any idea how I would do this? Thanks Link to comment https://forums.phpfreaks.com/topic/91846-change-image-when-selected/#findComment-470367 Share on other sites More sharing options...
phpQuestioner Posted February 19, 2008 Share Posted February 19, 2008 Where do you want the count to appear; in a textbox or in the page? Link to comment https://forums.phpfreaks.com/topic/91846-change-image-when-selected/#findComment-471142 Share on other sites More sharing options...
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