Retrieving images from the database

[rekha]

Hi

 

I have inserted images to the database.Now i want to display the image when i saw the tag in the entry.I have used the str_replace function.But it is not working.

 

$entry = str_replace('[img]','<img src=image.php?id=$id>',$entry);

 

Please solve this immediately.....

 

 

 

Regards

Rekha

http://hiox.org

[Sulman]

Please solve this immediately.....

We'll put that down to bad english 

 

What error are you getting if any?

 

Try this:

<?php
$entry = str_replace("[img]","<img src=image.php?id=$id>",$entry);
?>

 

I replaced single quotes with double so that $id is treated as a variable.

[burtybob]

<?php
$entry = str_replace('[img]','<img src=image.php?id='.$id.'>',$entry);
?>

 

I just added the 2 full stops and a quote around the $id so it does a similiar job or at least it does for me.

[Chris92]

You can also use {'s

<?php
$entry = str_replace('[img]','<img src=image.php?id={$id}>',$entry);
?>

[drisate]

i think i prefer the good old ways lol '..' breaks the ' string and every php editors colors the var out for easy finding. Just my opinion.

[burtybob]

i think i prefer the good old ways lol '..' breaks the ' string and every php editors colors the var out for easy finding. Just my opinion.

 

Wow someone agrees with me *recovers from fainting*, im so rarely agreed with.

[rekha]

Hi all,

 

Thanks for your reply.I got the image using the below code

 

<?php
$entry = str_replace('[img]','<img src=image.php?id='.$id.'>',$entry);
?>

 

 

Regards

Rekha

http://hiox.org

[aschk]

Just a quick note to correct Chris92's post.

<?php

$entry = str_replace('','<img src=image.php?id={$id}>',$entry);

?>

You CAN'T use variable substitution inside a string with single quotes (').

 

If you want to use the {} syntax then you have to use double quotes (").

e.g.

<?php
$entry = str_replace('[img]',"<img src=image.php?id={$id}>",$entry);
?>