testing to see if a number has a decimal point

[gish]

hi everyone,

 

I have a script that will sometimes post a number that has a decimal point. But the script below only wants whole numbers. In the code below how do i get to $testwholenumber if to check to see it is a decimal point and test it properly.

 

       if ($testwholenumber <= $testwholenumber.1){	
                     echo "Sorry all numbers have be whole for example 12.3 will not be accepted";
}elseif{
           				
	#myscript						

        }

 

gish

[cyrixware]

substr

[markjoe]

Would it be acceptable to round the number and just take the integer part of it?

floor(12.3) gets converted to 12

 

Or you can test it as a string with strpos().

 

[gish]

thankyou for your help everyone I chose strpos(). It is so simple all i have to do is tell the function to find "." .

[gish]

I having trouble with this piece of code can someone tell me  please. If a decimal point is found in $testwholenumber it will make the $falseortrue == true and the if statement won't work.

 

Is this right

 

	        $testwholenumber = $NumOne / $NumTwo;
	        echo $testwholenumber;
	        $findme = '.';
                        $falseortrue = strpos($testwholenumber, $findme);
                       if ($falseortrue == false){
                            #mycode
                         }

 

gish

[gish]

sorry I found the error $numtwo  was a always 0  which always caused a whole number. the above script works fine