Array help

[prudens]

OK, so I have something like

//ID of Dogs
10002,20120,28844,49223

 

How do I separate them and put them into an array Dog[] ?

 

Thanks!

[phpSensei]

<?php

$id_of_dogs = '10002,20120,28844,49223';
$dog = explode(',',$id_of_dogs);

  // Split Them 
for($i=0;$i<count($dog);$i++){ 
  
  echo $dog[$i] . '<br>';

       }

?>

[prudens]

thank u!

[prudens]

$conn = mysql_connect ($sql_host,$sql_user,$sql_pass);
$select = mysql_select_db ($sql_db,$conn);
$query = "SELECT * FROM " . $sql_table_legislation . " WHERE id = $id";
$results = mysql_query ($query);
$row = mysql_fetch_array($results);
mysql_close($conn);
//
//$row should be LIKE "0219209,2923989,585783,..."
$out = explode(',', $row);
for ($i=0; $i<count($out); $i++)
{
	echo $out[$i] . '<br>';
}

 

 

The output is "Array".... for some reason... could you help please???

[p2grace]

For echoing each value in the array try this instead:

 

foreach($out as $value){
echo $value."<br />";
}

[prudens]

still doesn't work >< Still "Array"

[p2grace]

can you post back what this gives you:

 

// right after this
$out = explode(',', $row);
// put
print_r($out);

 

[prudens]

Array ( [0] => Array )

[p2grace]

Try this instead:

 

<?php
conn = mysql_connect ($sql_host,$sql_user,$sql_pass);
$select = mysql_select_db ($sql_db,$conn);
$query = "SELECT * FROM " . $sql_table_legislation . " WHERE id = $id";
$results = mysql_query($query);
if($results){
  $arr = mysql_fetch_assoc($run);
  foreach($arr as $key => $value){
      echo "$key = $value <br />";
  }
}
?>

 

Let me know if that works.

[sasa]

change

$out = explode(',', $row);

to

$out = explode(',', $row['put_name_of_database_field_with_dogs_ID_here']);