Lassie Posted March 6, 2008 Share Posted March 6, 2008 I want to show a secondary menu based on a user logging in and the current page he is on. I have a seession id to test fro and a check whether the current page is a page that should not display the secondary menu. The problem is it doesnt work for mutiple pages and seems a long way of going about it. The pages that I dont want the secondary menu to show on are all in a seprerate directory ./reg/xxx.php Is there a better way? <?php // Display links based upon the login status. // Show LOGIN links if this is the LOGOUT page. if (isset($_SESSION['user_id']) AND (substr($_SERVER['PHP_SELF'], -10) != 'logout.php')AND(substr($_SERVER['PHP_SELF'], -10) != 'register.php')AND(substr($_SERVER['PHP_SELF'], -10) != 'index.php')AND(substr($_SERVER['PHP_SELF'], -10) != 'forgot_password.php')AND(substr($_SERVER['PHP_SELF'], -10) != 'view_account2.php')) ) { ?> Quote Link to comment Share on other sites More sharing options...
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