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in_array() help?


drummer101

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<?php
while($row = mysql_fetch_array($user_id))
     if(in_array(19, $row)){
          echo "ADMIN<br>";
     } else {
  echo "NOT<br>";
     }
} else {
     echo "You have entered an invalid username/password combination";
}
?>

$row is a sql select statement that will return a quantity of results > 2

 

right now the php codeblock returns, "ADMIN NOT NOT". I can't figure out how to get the loop to stop when it returns true. and continue looping until END or TRUE.

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<?php
$res=mysql_query("SELECT * FROM users where username='$user' AND pass='$pass'");

if($row = mysql_fetch_array($user_id))
     if(in_array(19, $row)){
          echo "ADMIN<br>";
     } else {
  echo "NOT<br>";
     }
} else {
     echo "You have entered an invalid username/password combination";
}
?>

 

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One more question. Ran into a problem case checking. It appears that all of the results from $user_id aren't being returned, only the last one is.

 

user_id's are matched to group ID's, so you might have

 

User  Group ID

5        6

5        8

5        10

6        6

7        8

7        10

 

How would I go about assigning all the group ID's of user 5 to an array?

something like $this->sql->group_ids or am I way off base on that?

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try

...
$admin = 'NOT<br>';
while ($row = mysql_fetch_array($user_id)) if(in_array(19, $row)) $admin = "ADMIN<br>";
echo $admin;
} else {
     echo "You have entered an invalid username/password combination";
}

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would

<?php
while($row = mysql_fetch_array($user_id))
     if(in_array(19, $row)){
          echo "ADMIN<br>";
          break;
     } else {
  echo "NOT<br>";
     }
} else {
     echo "You have entered an invalid username/password combination";
}
?>

Work?

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