error in 1st time visit - paging script

[Alexhoward]

Hi guys i've just modified a paging script, and i'm getting an error.

 

when you 1st visit the page you get the error:

 

Notice: Undefined index: start in *** on line 68

 

and,

 

Notice: Undefined index: p_f in *** on line 119

 

but when you press next, then back, it's gone..???

 

could someone please try and tell me why?

 

here's the code:

 

<?php

require "config2.php";           // All database details will be included here 

$page_name="index.php"; //  If you use this code with a different page ( or file ) name then change this 

$start= $_GET['start'];								// To take care global variable if OFF
if(!($start > 0)) {                         // This variable is set to zero for the first page
$start = 0;
}

$eu = ($start -0);                
$limit = 12;                                 // No of records to be shown per page.
$this1 = $eu + $limit; 
$back = $eu - $limit; 
$next = $eu + $limit; 


/////////////// WE have to find out the number of records in our table. We will use this to break the pages///////
$query2=" SELECT * FROM links  ";
$result2=mysql_query($query2);
echo mysql_error();
$nume=mysql_num_rows($result2);
/////// The variable nume above will store the total number of records in the table////


////////////// Now let us start executing the query with variables $eu and $limit  set at the top of the page///////////
$query=" SELECT * FROM links  limit $eu, $limit ";
$result=mysql_query($query);
echo mysql_error();


echo "<link href='Images/bkgrnd.css' rel='stylesheet' type='text/css'><table  width='100%' border='0'>";        // display the users in table

$c = 0;

while($row = mysql_fetch_array($result)) { 
    $user2 = html_entity_decode($row['link']);

  if($c%3 == 0) echo "<tr>"; // If the counter has ticked 5 times, start a new row.


echo "<td scope='row' height='150' width='25%' align='center' valign='middle' class='bkgrnd'>$user2</td>";

  if($c%3 == 2) echo "</tr>"; // If we're drawing the 6th pic, end this row.
  $c++;
}
if($c%5 != 4) echo "</tr>"; // If there isn't a number of pics divisible by 6, end the row
echo "</table>"; // end the table



////////////////////////////// End of displaying the table with records ////////////////////////

///// Variables set for advance paging///////////
$p_limit=12; // This should be more than $limit and set to a value for whick links to be breaked

$p_f= $_GET['p_f'];								// To take care global variable if OFF
if(!($p_f > 0)) {                         // This variable is set to zero for the first page
$p_f = 0;
}



$p_fwd=$p_f+$p_limit;
$p_back=$p_f-$p_limit;
//////////// End of variables for advance paging ///////////////
/////////////// Start the buttom links with Prev and next link with page numbers /////////////////
echo "<table align = 'center' width='80%'><tr><td  align='left' width='20%'>";
if($p_f<>0){print "<a href='$page_name?start=$p_back&p_f=$p_back'><font face='Verdana' size='2'>PREV</font></a>"; }
echo "</td><td  align='left' width='10%'>";
//// if our variable $back is equal to 0 or more then only we will display the link to move back ////////
if($back >=0 and ($back >=$p_f)) { 
print "<a href='$page_name?start=$back&p_f=$p_f'><font face='Verdana' size='2'>PREV</font></a>"; 
} 



echo "</td><td  align='right' width='10%'>";
///////////// If we are not in the last page then Next link will be displayed. Here we check that /////
if($this1 < $nume and $this1 <($p_f+$p_limit)) { 
print "<a href='$page_name?start=$next&p_f=$p_f'><font face='Verdana' size='2'>NEXT</font></a>";} 
echo "</td><td  align='right' width='20%'>";
if($p_fwd < $nume){
print "<a href='$page_name?start=$p_fwd&p_f=$p_fwd'><font face='Verdana' size='2'>NEXT</font></a>"; 
}
echo "</td></tr></table>";


?>

 

Thank in advance!!

 

p.s. here's the page if you wish to see the error in person

 

www.everyonlinestore.co.uk

 

[Jeremysr]

It looks like it happens when the start and p_f variables aren't in the URL. Try adding this code near the top of the script:

 

if (!isset($_GET['start'])) { $_GET['start'] = 0; }

if (!isset($_GET['p_f'])) { $_GET['p_f'] = 0; }

 

It'll check if those variables are set in the URL, and set them to default values if they're not set.

[cooldude832]

the site you are using is configed with a high level of error reporting thus when you try and use a variable undeclared ie. $_GET['start'] it produces a warning.

[Alexhoward]

Nice one!!

 

that seems to have done it

 

could you check from your end to see if you see the error...?

 

Thanks alot!!

[Alexhoward]

how do i configure the error reporting....?

 

sorry i'm new to this

[Jeremysr]

The server executes all PHP code instead of your computer, so if it doesn't show the error for you it won't show it for anyone.

 

Here's how you configure error reporting: http://ca3.php.net/error_reporting

[Alexhoward]

OK

 

Thanks Again!