PHP & MYSQL Problem

designedfree4u · March 18, 2008

I am slowly learning php and im try to combine two tutorials. The form is posting fine to the database ,but it creates two rows. one row for the blob and one for all the text. My goal is to place all the info in one single row.

Thanks for the help

Code:

<?
$username="";
$password="";
$database="jaybirdf_RealEstate";

$Address=$_POST['Address'];
$Picture=$_POST['Picture'];
$City=$_POST['City'];
$Map=$_POST['Map'];
$Bed=$_POST['Bed'];
$Bath=$_POST['Bath'];
$Terms=$_POST['Terms'];
$SQFT=$_POST['SQFT'];
$LSQFT=$_POST['LSQFT'];
$Price=$_POST['Price'];
$file=$_POST['Image'];
$type=$_POST['FileType'];

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");

$query = "INSERT INTO Listing (Address,City,Map,Bed,Bath,Terms,SQFT,LSQFT,Price,Picture,Image,FileType)
VALUES ('$Address','$City','$Map','$Bed','$Bath','$Terms','$SQFT','$LSQFT','$Price','$Picture','$file','$type')";
mysql_query($query);




//File upload Part


      if ($_POST['Submit']) {
        if ($_POST['MAX_FILE_SIZE'] >= $_FILES['file']['size']) {
          //print_r($_FILES);
          mysql_connect("localhost", "", "") or die(mysql_error());
          mysql_select_db("jaybirdf_RealEstate");
          $photo = addslashes(fread(fopen($_FILES['file']['tmp_name'], "r"),
$_FILES['file']['size']));
           $query = sprintf("INSERT INTO Listing(Image, FileType) VALUES
('%s', '%s')", $photo, $_FILES['file']['type']);
           if (mysql_query($query)) {
            $messages[] = "Your files is successfully store in database"; 
           } else {
            $messages[]= mysql_error();
           }
          } else {
           $messages[]="The file is bigger than the allowed size please resize";
          }
        }
      ?>
      <html>
      <head>
      <title>Add Image</title>
      </head>    
      <body>
      <? 
      if (isset($messages)) { 
        foreach ($messages as $message) {
         print $message ."<br>";
        } 
      }
  mysql_close();
      ?>

frijole · March 18, 2008

what do you mean by "the blob" I don't see it in your code?

bpops · March 18, 2008

You're saying the file posted is being submitted to a separate row? If this is what you're saying, you need to specify the row to put it in in your query. So

query = sprintf("INSERT INTO Listing(Image, FileType) VALUES

('%s', '%s')", $photo, $_FILES['file']['type']);

would become something like

query = sprintf("INSERT INTO Listing(Image, FileType) VALUES

('%s', '%s') WHERE Address='$Address' AND City='$City'", $photo, $_FILES['file']['type']);

.. but to even better specify a particular row, you should have the primary key for your table be an auto_increment to give it a unique ID.

Caberman · March 18, 2008

Inserts always create a new row. So you have an INSERT for the data you get posted, and then an INSERT for the blob down below.

Your second INSERT should probably be an UPDATE and you will have to make sure you get a way to know which row to UPDATE, ideally by selecting out the ID of the row you need to update.

Cheers.

designedfree4u · March 18, 2008

15 final test t t t t t t t t t [bLOB - 0 B]

16 final test t t t t t t t t [bLOB - 0 B]

30 testes w w w w w w w w w [bLOB - 0 B]

31 [bLOB - 4.5 KiB] image/pjpeg

When i upload it creates line 30 and line 31 what i want is

15 final test t t t t t t t t t [bLOB - 0 B]

16 final test t t t t t t t t [bLOB - 0 B]

30 testes w w w w w w w w w [bLOB - 4.5 KiB] image/pjpeg

GingerRobot · March 18, 2008

Yes, when you use the insert command, you will create a new row. You can either combine everything into one insert, or perform the first query as an insert and the second as an update query.

I would recommend combining the queries, since it is more efficent. This should work for you:

<?php
$username="jaybirdf_Admin";
$password="607101593";
$database="jaybirdf_RealEstate";
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");

     if ($_POST['Submit']) {
       if ($_POST['MAX_FILE_SIZE'] >= $_FILES['file']['size']) {
        $Address=$_POST['Address'];
           $Picture=$_POST['Picture'];
           $City=$_POST['City'];
           $Map=$_POST['Map'];
           $Bed=$_POST['Bed'];
           $Bath=$_POST['Bath'];
           $Terms=$_POST['Terms'];
           $SQFT=$_POST['SQFT'];
           $LSQFT=$_POST['LSQFT'];
           $Price=$_POST['Price'];
           $file=$_POST['Image'];
           $type=$_POST['FileType'];
         //print_r($_FILES);

         $photo = addslashes(fread(fopen($_FILES['file']['tmp_name'], "r"),
$_FILES['file']['size']));
           $query = "INSERT INTO Listing (Address,City,Map,Bed,Bath,Terms,SQFT,LSQFT,Price,Picture,Image,FileType)
VALUES ('$Address','$City','$Map','$Bed','$Bath','$Terms','$SQFT','$LSQFT','$Price','$Picture','$photo','".$_FILES['file']['type']."')";
          if (mysql_query($query)) {
           $messages[] = "Your files is successfully store in database"; 
          } else {
           $messages[]= mysql_error();
          }
         } else {
          $messages[]="The file is bigger than the allowed size please resize";
         }
       }
     ?>
     <html>
     <head>
     <title>Add Image</title>
     </head>    
     <body>
     <? 
     if (isset($messages)) { 
       foreach ($messages as $message) {
        print $message ."<br>";
       } 
     }
  mysql_close();
     ?>

designedfree4u · March 18, 2008

Wow that worked perfect,

Thank you to all

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