stublackett Posted March 21, 2008 Share Posted March 21, 2008 Hi, I've got images inserted into my DB and its outputting the text no problem and even when I do echo $myrow['image']; its outputting the root string for the image in text i.e images/image.jpg But it just wont show the Image when I put it into the <img src="<?php echo $myrow['image]" /> Any ideas why? Heres my code <?php #news-index.php By Stuart Blackett include("dbconnect.php"); $result = mysql_query("SELECT *, DATE_FORMAT( time, '%D %M %Y @ %H:%i' )AS uk_date FROM $db_table ORDER BY time DESC LIMIT 2",$connect); //Limit news items to 3 while($myrow = mysql_fetch_assoc($result)) {//begin of loop //now print the results: echo "<hr>"; echo "<br>"; echo "<b> News Title:</b> "; echo $myrow['title']; echo "<br><br><b>News Posted On :</b> "; echo $myrow['uk_date']; echo "<br> <br>"; echo "<b><td>News Description :</b><br><br></td>"; echo $myrow['description']; echo "<br>"; echo "<hr>"; // Now print the options to (Read,Edit & Delete the news) echo "<br><a href=\"read_more.php?newsid=$myrow[newsid]\">Read More </a>"; if ($userlevel == "2" || $userlevel == "3"){ echo "|| <a href=\"add_news.php\">Add News </a>"; echo "|| <a href=\"edit_news.php?newsid=$myrow[newsid]\">Edit </a>"; echo "|| <a href=\"delete_news.php?newsid=$myrow[newsid]\">Delete </a><br><br>"; } } ?> </div> </div> <div id="footer"></div> <div id="left-menu"> <div id="side-nav"> <h1>Design & Technology</h1> <a href="dt_announcements.php">Announcements</a> <a href="#">Learning Materials</a> <h1>English</h1> <a href="english_announcements.php">Announcements</a> <a href="#">Learning Materials</a> <h1>Humanities</h1> <a href="humanities_announcements.php">Announcements</a> <a href="#">Learning Materials</a> <h1>ICT</h1> <a href="ict_announcements.php">Announcements</a> <a href="">Learning Materials</a> <h1>Mathematics</h1> <a href="maths_announcements.php">Announcements</a> <a href="#">Learning Materials</a> <h1>Modern Foreign Languages</h1> <a href="mfl_announcements.php">Announcements</a> <a href="#">Learning Materials</a> <h1>Physical Education</h1> <a href="pe_announcements.php">Announcements</a> <a href="#">Learning Materials</a> <h1>Science</h1> <a href="science_announcements.php">Announcements</a> <a href="#">Learning Materials</a> </div> </div> <div id="copyright"> Stuart Blackett</div> <img src="<?php echo $myrow['image'] ; ?>" alt="News" class="news1"/> </div> Link to comment https://forums.phpfreaks.com/topic/97244-echoing-an-image-from-a-db-table/ Share on other sites More sharing options...
rhodesa Posted March 21, 2008 Share Posted March 21, 2008 First thing I notice is that <img src="<?php echo $myrow['image'] ; ?>" alt="News" class="news1"/> isn't inside your WHILE loop... Link to comment https://forums.phpfreaks.com/topic/97244-echoing-an-image-from-a-db-table/#findComment-497599 Share on other sites More sharing options...
stublackett Posted March 21, 2008 Author Share Posted March 21, 2008 First thing I notice is that <img src="<?php echo $myrow['image'] ; ?>" alt="News" class="news1"/> isn't inside your WHILE loop... I've tried defining it in the WHILE loop as $img = $myrow['image']; Then I've done <img src="<?php echo $img ; ?>" /> But no joy, How on earth do I get that Image echo'ing into the area ??? Link to comment https://forums.phpfreaks.com/topic/97244-echoing-an-image-from-a-db-table/#findComment-497843 Share on other sites More sharing options...
stublackett Posted March 21, 2008 Author Share Posted March 21, 2008 Just an update I spotted my error was with the routing of the file in the database, I had it as /images/image.jpg One too many "/"'s My next issue is somewhat similar, The image is in the Database with its URL string as news/pic3.jpg The PHP is also echoing the variable $img; no problems, Its saying it is : news/pic3.jpg So when I try <img src="<?php echo $img ; ?>"/> It just doesnt load "news/pic3.jpg" If you change the img src to : <img src="news/pic3.jpg"> It loads the picture no problem, I just dont get it *Scratches head* ??? <?php #news-index.php By Stuart Blackett include("dbconnect.php"); $result = mysql_query("SELECT *, DATE_FORMAT( time, '%D %M %Y @ %H:%i' )AS uk_date FROM $db_table ORDER BY time DESC LIMIT 2",$connect); //Limit news items to 3 while($myrow = mysql_fetch_assoc($result)) {//begin of loop //now print the results: echo "<hr>"; echo "<br>"; echo "<b>Title:</b> "; echo $myrow['title']; echo "<br><br><b>News Added On :</b> "; echo $myrow['uk_date']; echo "<br> <br>"; echo "<b><td>News Description :</b><br><br></td>"; echo $myrow['description']; echo "<br>"; echo "<hr>"; $img = $myrow['image']; // Now print the options to (Read,Edit & Delete the news) echo "<br><a href=\"read_more.php?newsid=$myrow[newsid]\">Read More </a>"; if ($userlevel == "2" || $userlevel == "3"){ //Restrict Add, Edit & Delete from Students echo "|| <a href=\"add_news.php\">Add News </a>"; echo "|| <a href=\"edit_news.php?newsid=$myrow[newsid]\">Edit </a>"; echo "|| <a href=\"delete_news.php?newsid=$myrow[newsid]\">Delete </a><br><br>"; } } ?> <img src="<?php echo $img ; ?>" alt="News Image" class="news1"/> Link to comment https://forums.phpfreaks.com/topic/97244-echoing-an-image-from-a-db-table/#findComment-497936 Share on other sites More sharing options...
rhodesa Posted March 24, 2008 Share Posted March 24, 2008 Once again, the IMG is outside the loop. So, the loop will run, each time setting $img to what is in the DB. Then, after the loop, it will show 1 image and it should be the value of the last row from the loop. Try the code real quick and see if the image URLs are printing correctly: <?php #news-index.php By Stuart Blackett include("dbconnect.php"); $result = mysql_query("SELECT *, DATE_FORMAT( time, '%D %M %Y @ %H:%i' )AS uk_date FROM $db_table ORDER BY time DESC LIMIT 2",$connect); while($myrow = mysql_fetch_assoc($result)){//begin of loop echo "<hr>"; echo "<br>"; echo "<b>Title:</b> "; echo $myrow['title']; echo "<br><br><b>News Added On :</b> "; echo $myrow['uk_date']; echo "<br> <br>"; echo "<b><td>News Description :</b><br><br></td>"; echo $myrow['description']; echo "<br>"; echo "<b><td>Image URL:</b><br><br></td>"; echo $myrow['image']; echo "<br>"; echo "<b><td>Image:</b><br><br></td>"; echo "<img src=\"{$myrow['image']}\" />; echo "<br>"; echo "<hr>"; // $img = $myrow['image']; // Now print the options to (Read,Edit & Delete the news) echo "<br><a href=\"read_more.php?newsid=$myrow[newsid]\">Read More </a>"; if ($userlevel == "2" || $userlevel == "3"){ //Restrict Add, Edit & Delete from Students echo "|| <a href=\"add_news.php\">Add News </a>"; echo "|| <a href=\"edit_news.php?newsid=$myrow[newsid]\">Edit </a>"; echo "|| <a href=\"delete_news.php?newsid=$myrow[newsid]\">Delete </a><br><br>"; } } ?> Link to comment https://forums.phpfreaks.com/topic/97244-echoing-an-image-from-a-db-table/#findComment-499402 Share on other sites More sharing options...
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