goldenbrown21 Posted March 22, 2008 Share Posted March 22, 2008 Hey all! I've been stuck getting my exporting php script to display the results correctly. At the moment, when I use the export sheet, it only displays the results for table 1 ???, whereas I want it to display table 1 and table 2. See my script below: <?php $host = 'localhost'; $user = 'root'; $pass = '******'; $db = 'nsc'; $table1 = 'customerdetails'; $table2 = 'callout'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table1.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row["Field"].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * From ".$table1.",".$table2." WHERE ".$table1.".custcode = ".$table2.".custcode ORDER BY ".$table1.".custcode ASC"); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= $rowr[$j].", "; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d_H-i",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> Any assistance with this would be greatly appreciated!!! Link to comment https://forums.phpfreaks.com/topic/97350-combine-two-tables-from-mysql-into-a-single-csv-file/ Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.