strtotime giving me the ole' 1969 error

[easyedy]

Hi all I'm trying to format some calendar dates for my site and since some of the calendar listings are way down the road in the future the time is "Call For Time" and when I try to format it I'm getting the 1969 error. Any thoughts on how I can change the code to work:

 

$datelisting = strftime("<b>%b. %d, %Y</b><br>%A %l:%M %P", strtotime($datelisting]));

echo $datelisting;

 

$datelisting before formatting is: 09/12/2008 Call For Time

 

Here is what my code spits at me:

 

Dec. 31, 1969

Wednesday 4:00 pm

 

What I want is:

 

Sept. 12, 2008

Call For Time

 

 

Any ideas? Thx.

 

-E

 

 

[soycharliente]

You've got some funky stuff going on. Like that random bracket at the end.

 

Try ...

<?php
echo date('<b>M d, Y</b><b\\r />l g:i A', strtotime($datelisting));
?>

 

And if that doesn't work, echo what $datelisting is and show us exactly what's being passed in.

[easyedy]

You've got some funky stuff going on. Like that random bracket at the end.

 

 

Yeah it was an array var I made it general for here and forgot to take out the bracket...

 

Unfortunately, you  code gave me the same things.

 

$datelisting gives me this: 09/12/2008 Call For Time

[soycharliente]

Where are you getting the data? From a database? What's the datatype?

 

Do an echo and show me what $datelisting is.

[easyedy]

Yes, a database.

 

echo $datelisting returns the date & timeas a string. ie:

 

09/12/2008 7:00pm

 

 

If there is notime it returns, ie:

 

09/12/2008 Call For Time

 

 

[soycharliente]

What's the datatype that you are using to store it? Maybe changing to DATETIME will solve that problem since it sounds like you're just storing it as a string.