[SOLVED] Button

[westminster86]

Im using the isset function as follows.

 

if (isset($_POST['submit'])) {

  // check form fields

}

 

The problem im having is the call to the display_form_button() function doesnt have a input type, therefore the $_POST['submit'] is not set. If I were to add submit to the input type, the isset function works, but then it doesnt display the button ive created, it displays the html button.

 

function display_form_button($image, $alt)

{

  echo "<center><input type =  image src=\"$image".".gif\"

          alt=\"$alt\" border=0 height=32 width=100 name=\"submit\" ></center>";

}

 

 

[rhodesa]

Instead of changing your button, can you change your IF? I usually use this as my POST check:

 

if($_SERVER['REQUEST_METHOD'] == 'POST'){
  //check for fields
}

[westminster86]

I havent come across $_SERVER['REQUEST_METHOD'] before. Ill use it from now on. Thanks for that.