Jump to content

daruga

Members
  • Posts

    13
  • Joined

  • Last visited

daruga's Achievements

Newbie

Newbie (1/5)

0

Reputation

  1. <?php session_start(); unset($_SESSION['user_name']); header('Location: index.php'); ?> this my logout.php
  2. <?php session_start(); $username = $_POST['username']; $password = md5($_POST['password']); $connect_error = 'sorry we have downtime problem '; $connect1_error = 'database connection error '; mysql_connect('localhost','root','password')or die($connect_error); mysql_select_db('mkjb')or die($connect1_error); $con = mysql_connect($mysql_db_hostname, $mysql_db_user, $mysql_db_password) or die("Could not connect database"); mysql_select_db($mysql_db_database, $con) or die("Could not select database"); $query = "SELECT * FROM registered_users WHERE name='$username' AND password='$password'"; $result = mysql_query($query)or die(mysql_error()); $num_row = mysql_num_rows($result); $row=mysql_fetch_array($result); if( $num_row >=1 ) { echo 'true'; $_SESSION['user_name']=$row['name']; } else{ echo 'false'; } ?> login.php
  3. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <script type="text/javascript" src="jquery.js"></script> <link rel="stylesheet" href="styles.css" type="text/css" /> <title>Login Form</title> <script type="text/javascript"> $(document).ready(function(){ $("#login").click(function(){ username=$("#user_name").val(); password=$("#password").val(); $.ajax({ type: "POST", url: "login.php", data: "username="+username+"&password="+password, success: function(html){ if(html=='true') { $("#login_form").fadeOut("normal"); $("#shadow").fadeOut(); $("#profile").html("<a href='logout.php' class='red' id='logout'>Logout</a>"); // You can redirect to other page here.... } else { $("#add_err").html("Wrong username or password"); } }, beforeSend:function() { $("#add_err").html("Loading...") } }); return false; }); }); </script> </head> <body> <?php session_start(); ?> <div id="profile"> <?php if(isset($_SESSION['username'])){ ?> <a href='logout.php'>Logout</a> <?php } ?> </div> </body> <?php if(empty($_SESSION['username'])){?> <div class="container" id="login_form"> <section id="content"> <form action="login.php"> <h1>Login Form</h1> <div> <input type="text" placeholder="Username" required="" id="user_id" name="username"/> </div> <div> <input type="password" placeholder="Password" required="" id="password" name="password"/> </div> <div class="err" id="add_err"></div> <div> <input type="submit" value="Log in" id="login" /> <a href="#">Lost your password?</a> <a href="#">Register</a> </div> </form><!-- form --> <div class="button"> </div><!-- button --> </section><!-- content --> </div> <?php }?> <!-- container --> </html> index.php
  4. my problem....our login page not working...need help forum how to fix it and i neeed some advice on php..3 main page 1)index.php 2/login.php 3)logout.php the main problem is i dont know if my website connect with database phpmyadmin or not....it only give inccorect password/username
  5. <?php function logged_in() { return (isset($_SESSION['user_id'])) ? true : false; } function user_exists ($username) { $username = sanitize($username); return(mysql_result(mysql_query ("SELECT COUNT(user_id) FROM users WHERE username = '$username'"), 0) == 1) ? true : false; } function user_active($username){ $username = sanitize($username); return (mysql_result(mysql_query("SELECT COUNT(user_id) FROM users WHERE username = '$username' AND active = 1"), 0) == 1) ? true : false; } function user_id_from_username($username) { $username = sanitize($username); return mysql_result(mysql_query("SELECT user_id FROM users WHERE username ='$username'"), 0, 'user_id'); } function login ($username, $password) { $user_id = user_id_from_username($username); $username = sanitize($username); $password = md5($password); return (mysql_result(mysql_query("SELECT COUNT(user_id) From users WHERE username = '$username' AND password = '$password'"), 0) ==1) ? $user_id : false; } ?> <aside> <?php if (logged_in() === true) { include 'includes/widgets/loggedin.php'; } else { include "includes/widgets/login.php"; } ?> </aside> Fatal error: Call to undefined function logged_in() in C:\wamp\www\mkjb\includes\aside.php on line 4 Call Stack # Time Memory Function Location 1 0.0008 140912 {main}( ) ..\register.php:0 2 0.0011 142336 include('C:\wamp\www\mkjb\includes\overall\overallheader.php') ..\register.php:1 3 0.0020 144880 include( 'C:\wamp\www\mkjb\includes\aside.php' ) ..\overallheader.php:8 could u help me fix this...i try different method it give same result
  6. <?php if (logged_in)() === true { echo 'Logged in'; } else { is there a way to do if statement other than my....what we learn in school we been using more familiar with that statement. because i did confuse with java if statement
  7. <aside id="Just_A_Random_ID"> <?php if (logged_in)() === true { echo 'Logged in'; } else { include "includes/widgets/login.php"; } ?> </aside> Parse error: syntax error, unexpected ')' in C:\wamp\www\mkjb\includes\aside.php on line 4 Call Stack # Time Memory Function Location 1 0.0004 140960 {main}( ) ..\register.php:0 2 0.0008 142384 include( 'C:\wamp\www\mkjb\includes\overall\overallheader.php' ) ..\register.php:1 how to fix this error
  8. did i need to remove all the quotes around user_id
  9. <?php function user_exists ($username) { $username = sanitize($username); return(mysql_result(mysql_query("SELECT COUNT('user_id') FROM 'users' WHERE 'username' = '$username'"), 0) == 1) ? true : false; } function user_active($username){ $username = sanitize($username); return (mysql_result(mysql_query("SELECT COUNT('user_id') FROM 'users' WHERE 'username' = '$username' AND 'active' = 1"), 0) == 1) ? true : false; } function user_id_from_username($username) { $username = sanitize($username); return mysql_result(mysql_query("SELECT 'user_id' FROM 'users' WHERE 'username' ='$username'"), 0, 'user_id'); } function login ($username, $password) { $user_id = user_id_from_username($username); $username = sanitize($username); $password = md5($password); return (mysql_result(mysql_query("SELECT COUNT ('user_id') From 'users' WHERE 'username' = '$username' AND 'password' = '$password'"), 0) ==1) ? $user_id : false; } ?>
  10. Warning: mysql_result() expects parameter 1 to be resource, boolean given in C:\wamp\www\mkjb\core\functions\users.php on line 4 i need help how to fix this
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.