IEMC

Thats.... crazy... Putting that in made it echo the news.. lol thanks :P

This is a news system. Its one i made a while back, stopped doing stuff with websites for awhile, now im coming back to it. My code is: [code]<?php             $table = 'news';        $dbconnection = mysql_connect("$host", "$user", "$pass") or die ("MySQL Connection Attempt Failed: " . mysql_error());        mysql_select_db("$database",$dbconnection);                      $query="SELECT * FROM $table ORDER BY post_numb DESC LIMIT 1";             $result=mysql_query($query);             $num_rows=mysql_num_rows($result);              $i=0;             while($i<$num_rows) {             $title=mysql_result($result,$i,'news_title');             $time=mysql_result($result,$i,'time');             $article=mysql_result($result,$i,'news_text');                          echo "$title";               echo nl2br("$article");             $i=$i+1;             }             mysql_close( $dbconnection );         ?>[/code] I have news entered, its just whenever i try to see the news, i get this: [!--quoteo--][div class=\'quotetop\']QUOTE[/div][div class=\'quotemain\'][!--quotec--] Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/.invitation/lukepolito/mrfaxsender.be/index.php on line 30[/quote] Which makes no sense, because this used to work. Whats the problem?