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Displaying Info From 2 Tables


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#1 bamfon

bamfon

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Posted 19 November 2012 - 08:13 PM

Not good at explaning myself but I will try :P


$con = database_connect();
$sqs="SELECT *
FROM `11game`.`army_info`
LEFT JOIN `11game`.`armyinbase`
ON ( `army_info`.`type` = `armyinbase`.`type` )" ;

$res1=mysql_query($sqs,$con);
if(!$res1)
{
die('error in data'.mysql_error());

}
?>

while($row1=mysql_fetch_assoc($res1))
{



$name=$row1['name'];
$info=$row1['info'];


?>

$result2 = mysql_query($sql2)or exit(mysql_error());
while($row2 = mysql_fetch_array($result2))
{
$total = $row1['total'];




}






<td height="14" align="center"><?php echo $row1['name'];?></td>

<td height="30" rowspan="2" align="center"> <?php echo $total ?></td>
<td rowspan="2">&nbsp;</td>
<td rowspan="2">1</td>
</tr>
<tr>
<td height="14" align="center"><?php echo $info ;?></td>
</tr>
<?php
}
?>



What I am trying to do Is


The first table to recall up the the info and place it in the table (done that part its working )
But I was the 2nd table to recall up info and add it in the right place EG on the line where ID =1 on both tables


What should be shown is something like this




Table

Troops How many you own cost per a unit
tank 2 10gold



The troops and cost per a unit is from table one while the how many you own is from table 2

Right now its showing info info from table 1 how many times there are rows intable 2

Edited by bamfon, 19 November 2012 - 08:14 PM.


#2 Muddy_Funster

Muddy_Funster

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Posted 20 November 2012 - 04:42 AM

That's not all the code, where is the content of $sql2?
Your code here :-
$sqs="SELECT * FROM `11game`.`army_info` LEFT JOIN `11game`.`armyinbase` ON ( `army_info`.`type` = `armyinbase`.`type` )" ;
looks close to what I imagine you would want to be using to get the results you are looking for, but I'd like to see the full and actual table structures if you could.
A simple password hash :

function makePass($word=''){
  $dbSalt = '$2a$07$'.substr(hash('whirlpool',$word),0,22);
  $dbPass = crypt($word, $dbSalt);
 return substr($dbPass,12);
}



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