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Sorry i just read the last part of what you said, so i wrote this.

 

Going to read the rest after i come back home...

so here...

<?php
for($x = 1; $x <= 10; $x++){

if($x == 1){
echo $x . "st<br>";
}
elseif($x == 2){

echo $x . "nd<br>";


}
elseif($x == 3){

echo $x . "rd<br>"; 


}
else
{

echo $x . "th<br>";

}
}

?>

 

With Mysql

 

<?php

$query = mysql_query("SELECT * FROM race ORDER BY place LIMIT 10");
$x = 1;

while($row = mysql_fetch_array($query)){

if($x == 1){
echo $x . "st" .$row['racer']. "<br>";
}
elseif($x == 2){

echo $x . "nd" .$row['racer']. "<br>";


}
elseif($x == 3){

echo $x . "rd" .$row['racer']. "<br>"; 


}
else
{

echo $x . "th " .$row['racer']. "<br>";

}




}
?>

If the number is between 1 and 31 (inclusive) you can use the date() function in conjunction with the strtotime() function:

<?php
$num = rand(1,31); // get a number
echo date('jS',strtotime('2007-01-' . $num);
?>

 

Ken

try

<?php
function ordSuffix($n) {
    $str = "$n";
    $t = $n > 9 ? substr($str,-2,1) : 0;
    $u = substr($str,-1);
    if ($t==1) return $str . 'th';
    else switch ($u) {
        case 1: return $str . 'st';
        case 2: return $str . 'nd';
        case 3: return $str . 'rd';
        default: return $str . 'th';
    }
}

echo ordSuffix(1).'<br>';
echo ordSuffix(11).'<br>';

Hi there,

 

I've been trying to use the following code, posted by Barand:

 

    					function ordSuffix($i) {
					   $str = "$i";
					   $t = $i > 9 ? substr($str,-2,1) : 0;
					   $u = substr($str,-1);
					   if ($t==1) return $str . 'th';
						   else switch ($u) {
						       case 1: return $str . 'st';
						       case 2: return $str . 'nd';
						       case 3: return $str . 'rd';
						       default: return $str . 'th';
							   }
						}

                                       echo orderSuffix(1).'<br>';

 

But I get the following error:

Call to undefined function orderSuffix()

 

Does anyone know how I can fix this?

 

Many thanks,

 

Katie

 

If the number is between 1 and 31 (inclusive) you can use the date() function in conjunction with the strtotime() function:

<?php
$num = rand(1,31); // get a number
echo date('jS',strtotime('2007-01-' . $num);
?>

 

Ken

 

What does this actually do?

If the number is between 1 and 31 (inclusive) you can use the date() function in conjunction with the strtotime() function:

<?php
$num = rand(1,31); // get a number
echo date('jS',strtotime('2007-01-' . $num);
?>

 

Ken

 

What does this actually do?

 

It makes use of the date function's format to add the suffix onto the end of the date.  The format jS is the day of the month, followed by the relevant suffix. The second parameter is to set a particular date for this. It uses strtotime to create the unix timestamp based on a date, which is an arbitary year and month (though, of course, you need to use a month with 31 days!) followed by the day of the month, which is the number we want.

 

Quite a clever approach if you only need to go up to 31.

If the number is between 1 and 31 (inclusive) you can use the date() function in conjunction with the strtotime() function:

<?php
$num = rand(1,31); // get a number
echo date('jS',strtotime('2007-01-' . $num);
?>

 

Ken

 

What does this actually do?

 

It makes use of the date function's format to add the suffix onto the end of the date.  The format jS is the day of the month, followed by the relevant suffix. The second parameter is to set a particular date for this. It uses strtotime to create the unix timestamp based on a date, which is an arbitary year and month (though, of course, you need to use a month with 31 days!) followed by the day of the month, which is the number we want.

 

Quite a clever approach if you only need to go up to 31.

 

Thats really neat.

 

*Saved Script*

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