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cool_techie

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About cool_techie

  • Birthday 03/26/1991

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    NIT srinagar

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  1. cool_techie
    .topdiv { box-shadow:0px 8px 8px #000000;//choose pixels according 2 ur wish -moz-box-shadow:0px 8px 8px #000000; -webkit-box-shadow:0px 8px 8px #000000; -o-box-shadow:0px 8px 8px #000000; } where topdiv is the class name of a div. u can also create other effects using .topdiv:hover in place of .topdiv
  2. cool_techie
    hey i've attached my page minus the code.. btw appreciate the ur time [attachment deleted by admin]
  3. cool_techie
    guys i m using chrome 11.0.696.71 doc type <!DOCTYPE html PUBtdC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> and the code .nit { position:absolute; left:70px; top:30px; height:30px; width:230px; color:#ffffff; text-shadow:0px 1px 1px #000000; -ms-text-shadow:0px 1px 1px #000000; letter-spacing:1px; font-family: "Trebuchet MS", Arial, Helvetica, sans-serif; transition: width 2s; -moz-transition: width 2s; -webkit-transition: width 2s; -o-transition: width 2s; } where nit is class name of a div .. this code is not working at all. sos
  4. cool_techie
  5. cool_techie
    It had to update the user information in the database but it shows unable to upload when i remove the jquery there but shows no message when i use jquery.
  6. cool_techie
    I have a php script wihich updates data in mysql db named 'trial' and table named 'tab' I am using jquery and ajax to update the db. but the script is not working. edit-profile.php <code> <?php session_start(); $img=$_SESSION['img']; ?> <html> <head> <title>Tgmc</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <meta name="keywords" content="" /> <meta name="description" content="" /> <link href="default.css" rel="stylesheet" type="text/css" media="screen" /> <script type="text/javascript" src="jquery-1.5.min.js"> </script> <script type="text/javascript"> $(function(){ $('#submit').click(function(){ $('#load').append('<img src="ajax-loader.gif" id="loading" alt="image" />'); var about= $('#about').val(); var contact= $('#contact').val(); var present= $('#present').val(); var inter= $('#inter').val(); var high= $('#high').val(); var books= $('#books').val(); var sports= $('#sports').val(); var pastime= $('#pastime').val(); var interest= $('#interest').val(); console.log (about); $.ajax({ url:'update-profile.php', type:'POST', data: 'contact=' + contact + '&about=' + about + '&present=' + present + '&inter=' + inter + '&high=' + high + '&books=' + books + '&sports=' + sports + '&pastime=' + pastime + '&interest=' +interest, success: function(result){ $('#response').remove(); $('#load').append('<p id="response">' + result + '</p>'); $('#loading').fadeOut(500,function(){ $(this).remove(); }); } }); return false; }); }); </script> </head> <body> <!-- start header --> <div id="wrapper"> <div id="header"> <div id="logo"> <h1><a href="#">ABC</a></h1> <p><a href="#">cinemas</a></p> </div> <?php { if(isset($_SESSION['name'])){ echo "<p id=\"welcome\">"; echo "Welcome ".$_SESSION['name']; echo " "; echo "<a href=\"logout.php\">"; echo "Logout"; echo "</a>"; echo "</p>"; } }?> </div> </div> <!-- end header --> <!-- star menu --> <div id="menu"> <ul> <li class="current_page_item"> <?php { if(isset($_SESSION['name'])){ echo "<a href=\"index1.php\">Home</a></li>"; } else{ echo "<a href=\"index.html\">Home</a></li>";}} ?> <li><a href="shows.php">Shows</a></li> <li><a href="umovies.php">Upcoming Movies</a></li> <li><a href="#">Reviews</a></li> <li><a href="#">Book Tickets</a></li> <li><a href="contact.html">Contact</a></li> </ul> </div> <!-- end menu --> <!-- start page --> <div id="page"> <!-- start ads --> <!-- end ads --> <!-- start content --> <div id="content"> <div class="post"> <div class="title"> <h2>My Profile <a href="edit-profile.php">Edit Profile</h2></a> </div> <div class="entry"> <form action="update-profile.php" method="post"> <p style="color:white"><a href="upload.php">Change photo</a><br/> <img src=<?php echo $_SESSION['img'] ?> width='120px' height='140px' class='left' alt='image' /> <strong>Contact:-</strong><input type="text" name="contact" id="contact" value="<?php echo $_SESSION['contact']; ?>" /><br/> About:-<textarea name="about" id="about" rows="5" cols="38" ><?php echo $_SESSION['about']; ?> </textarea><br/> </p> </div> <p style="color:white">Education:<br/> <strong>Present:-</strong> <input type="text" id="present" name="present" size="25" value="<?php echo $_SESSION['present']; ?>" /> <br/> <strong>Inter:- </strong><input type="text" id="inter" name="inter" size="25"value="<?php echo $_SESSION['inter']; ?>" /><br/> <strong>High School:-</strong><input type="text" id="high" name="high" size="25" value="<?php echo $_SESSION['high']; ?>" /><br/> <br><br> <strong>Favourite Books:-</strong><input type="text" id="books" name="books" size="30" value="<?php echo $_SESSION['books']; ?>" /><br/> <strong>Favourite Sport:-</strong><input type="text" id="sports" name="sports" size="30" value="<?php echo $_SESSION['sports']; ?>" /><br/> <br/><br/> <strong>Pastimes:-</strong><input type="text" name="pastime" id="pastime" size="25" value="<?php echo $_SESSION['pastime']; ?>" /><br/> <strong>Interests:-</strong><input type="text" name="interest" id="interest" size="25" value="<?php echo $_SESSION['interests']; ?>" /><br/><br/> <input type="submit" id="submit" value="Update" /> <div id="load></div> </form> </div> <!-- end page --> <!-- start footer --> <div id="footer"> <p class="legal"> ©2010ABC Cinemas. All Rights Reserved. • Design by <a href="#/">Pulkit</a> </p> <p class="links"> <a href="http://validator.w3.org/check/referer" class="xhtml" title="This page validates as XHTML">Valid <abbr title="eXtensible HyperText Markup Language">XHTML</abbr></a> • <a href="http://jigsaw.w3.org/css-validator/check/referer" class="css" title="This page validates as CSS">Valid <abbr title="Cascading Style Sheets">CSS</abbr></a> </p> </div> </div> <!-- end footer --> </body> </html> </code> update-profile.php <code> <?php session_start(); $connection=mysql_connect("localhost","root",""); mysql_select_db("TRIAL",$connection); if(mysql_query("UPDATE tab SET about='$_POST[about]',contact='$_POST[contact]',present='$_POST[present]',inter='$_POST[inter]',high='$_POST[high]',books='$_POST[books]',sports='$_POST[sports]',pastime='$_POST[pastime]',interests='$_POST[interest]' WHERE name='$_SESSION[name]'")){ echo "Successfully uploaded the data.<a href='index.php'>Click here</a> to return back."; } else echo "Unable to upload"; ?> </code>
  7. cool_techie
    I have a login script which is showing problem. The problem is that when my username and password are correct it directs to index.php page and displays the correct username there. But if the password is wrong it still directs to the same page instead of different(err-login.php) page,but this time no username is displayed. index.php: the password verifying code is as follows(the whole code of index.php is not mentioned since it is too long and a bit messy) <code> <?php $connection=mysql_connect("localhost","root",""); mysql_select_db("forum",$connection); $select=mysql_query("SELECT * FROM user_id WHERE uname='$_REQUEST[uname]'",$connection); $row=mysql_fetch_array($select); if($row['password']==$_REQUEST['password']){ session_start(); $_SESSION['name']=$_REQUEST['uname']; } else{ header("Location:err-login.php"); } ?> </code> NOTE:-The name of my db and table are correct. I have referred to username as uname.
  8. cool_techie
    Thnx, I just changed 'add' to 'adds' and now it is working.!
  9. cool_techie
    can u just clarify the use of backticks.. a little more.!
  10. cool_techie
    When i use mysql_error($conns); the output is: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'add,phone) VALUES ('pulkit',pulkit@gmail.com','26','3','1991','lucknow','9000463' at line 1 I am still unable to find out the error. NOTE:-All my table entries are VARCHAR
  11. cool_techie
    Hello....I am using ajax,jquery with php to insert data in db.....but the script is not working. form.html: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <style type="text/css"> label{ display:block; } </style> <script type="text/javascript" src="jquery-1.5.min.js"> </script> <script type="text/javascript"> $(function() { $('#submit').click(function(){ $('#container').append('<img src="ajax-loader.gif" id="loading" alt="image" />'); var name=$('#name').val(); var email=$('#email').val(); var d=$('#d').val(); var m=$('#m').val(); var y=$('#y').val(); var add=$('#add').val(); var phone=$('#phone').val(); $.ajax({ url: 'process.php', type: 'POST', data: 'name=' + name + '&email=' + email + '&d=' + d + '&m=' + m + '&y=' + y + '&add=' + add + '&phone=' + phone, success: function(result){ $('#response').remove(); $('#container').append('<p id="response">' + result + '</p>'); $('#loading').fadeOut(500,function(){ $(this).remove(); }); } }); return false; }); }); </script> </head> <body> <h2>User Registeration</h2> <form action="process.php" method="POST"> <div id="container"> Name:<br> <input type="text" name="name" id="name" /><br> Email:<br> <input type="text" name="email" id="email" /><br> Date Of Birth:<br> <input type="text" id="d" name="d" size="2" /> <input type="text" id="m" name="m" size="2" /> <input type="text" id="y" name="y" size="4" /><br> Address:<br> <input type="text" id="add" name="add" /><br> Phone:<br> <input type="text" id="phone" name="phone" /><br> <input type="submit" name="submit" id="submit" value="GO!" /> </div> </form> </body> </html> process.php My db id named "jquery" and table is "tab" <?php $conns=mysql_connect("localhost","root",""); if(!$conns) echo "error in connection"; mysql_select_db("jquery", $conns); $name=$_POST['name']; $email=$_POST['email']; $m=$_POST['m']; $d=$_POST['d']; $y=$_POST['y']; $add=$_POST['add']; $phone=$_POST['phone']; echo $name,"<br>"; echo $email,"<br>"; echo $m, "<br>"; echo $d,"<br>"; echo $y,"<br>"; echo $add, "<br>"; echo $phone,"<br>"; $query="INSERT INTO tab (name,email,d,m,y,add,phone) VALUES ('$name',$email','$d','$m','$y','$add','$phone')"; if(!mysql_query($query,$conns)) echo "Error"; else echo "DATA inserted"; ?> The output shown is: pulkit pulkit@gmail.com 1 26 1991 lucknow 987576787 Error For some values i entered.
  12. cool_techie
    I dont know whether the statement is correct.....i just tried it.....and it didn't work. $stmt->bind_param('ssiiiss',$_POST['name'],$_POST['email'],$_POST['d'],$_POST['m'],$_POST['y'],$_POST['add'],$_POST['phone']); here my first two values are strings and next 2 tiny int's next is int and last 2 again strings.
  13. cool_techie
    my script is not working.I wanted to insert data from a form to db using ajax and jquery...showing a loading icon as data is passed. It shows that data inserted but does not insert. form.html <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.0/jquery.min.js"> </script> <script type="text/javascript"> $(function() { $('#submit').click(function(){ $('#container').append('<img src="ajax-loader.gif" id="loading" />'); var name=$('#name').val(); var email=$('#email').val(); var comments=$('#comments').val(); $.ajax({ url: 'process.php', type: 'POST', data: 'name=' + name + '&email=' + email + '&comments=' + comments, success: function(result){ $('#response').remove(); $('#container').append('<p id="response">' + result + '</p>'); $('#loading').fadeOut(500); } }); }); }); </script> </head> <body> <form action="process.php" method="post"> <div id="container"> Name:<br /> <input type="text" name="name" id="name" /><br> Email:<br /> <input type="text" name="email" id="email" /><br> Comments:<br> <textarea rows="5" cols="30" name="comments" id="comments"> </textarea><br> <input type="submit" name="submit" id="submit" value="GO!" /> </div> </form> </body> </html> process.php: <?php $conns=new mysqli('localhost','root','','jquery_ex'); $query="INSERT into tab1 (name, email, comments) VALUES (?,?,?)"; $stmt=$conns->stmt_init(); if($stmt->prepare($query)){ $stmt->bind_param('sss','$_POST[name]','$_POST[email]','$_POST[comments]'); $stmt->execute(); } if($stmt){ echo "Successfully inserted the data"; }else{ echo "Error"; } ?>
  14. cool_techie
    can u provide me with some links wherein i can find some good stuff about working with files....?
  15. cool_techie
    I am unable to upload image to db, I get a message "No image selected/uploaded" after every trial, My HTML form is: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form enctype="multipart/form-data" action="insert.php" method="post"> <input name="image" accept="image/jpeg" type="file"> <input value="Submit" type="submit"> </form> </body> </html> and my php script "insert.php" is- <?php // Create MySQL login values and // set them to your login information. $username = "root"; $password = ""; $host = "localhost"; $database = "test"; // Make the connect to MySQL or die // and display an error. $link = mysql_connect($host, $username, $password); if (!$link) { die('Could not connect: ' . mysql_error()); } // Select your database mysql_select_db ($database); // Make sure the user actually // selected and uploaded a file if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) { // Temporary file name stored on the server $tmpName = $_FILES['image']['tmp_name']; // Read the file $fp = fopen($tmpName, 'r'); $data = fread($fp, filesize($tmpName)); $data = addslashes($data); fclose($fp); // Create the query and insert // into our database. $query = "INSERT INTO tbl_images "; $query .= "(image) VALUES ('$data')"; $results = mysql_query($query, $link); // Print results print "Thank you, your file has been uploaded."; }else{ print "No image selected/uploaded"; } // Close our MySQL Link mysql_close($link); ?> my table consists if an "id" and an "image" of type "blob".
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