cool_techie

June 4, 2011

.topdiv {

box-shadow:0px 8px 8px #000000;//choose pixels according 2 ur wish

-moz-box-shadow:0px 8px 8px #000000;

-webkit-box-shadow:0px 8px 8px #000000;

-o-box-shadow:0px 8px 8px #000000;

}

where topdiv is the class name of a div.

u can also create other effects using .topdiv:hover in place of .topdiv

June 4, 2011

hey i've attached my page minus the code..

btw appreciate the ur time

[attachment deleted by admin]

June 2, 2011

guys i m using chrome 11.0.696.71 doc type

<!DOCTYPE html PUBtdC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

and the code

.nit {

position:absolute;

left:70px;

top:30px;

height:30px;

width:230px;

color:#ffffff;

text-shadow:0px 1px 1px #000000;

-ms-text-shadow:0px 1px 1px #000000;

letter-spacing:1px;

font-family: "Trebuchet MS", Arial, Helvetica, sans-serif;

transition: width 2s;

-moz-transition: width 2s;

-webkit-transition: width 2s;

-o-transition: width 2s;

}

where nit is class name of a div ..

this code is not working at all.

sos

February 17, 2011

I have a php script wihich updates data in mysql db named 'trial' and table named 'tab'

I am using jquery and ajax to update the db. but the script is not working.

edit-profile.php


<?php
session_start();
$img=$_SESSION['img'];
?>
<html>
<head>
<title>Tgmc</title>


<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta name="keywords" content="" />
<meta name="description" content="" />
<link href="default.css" rel="stylesheet" type="text/css" media="screen" />
<script type="text/javascript" src="jquery-1.5.min.js">
</script>
<script type="text/javascript">
  $(function(){
      $('#submit').click(function(){
     $('#load').append('<img src="ajax-loader.gif" id="loading" alt="image" />');
     var about= $('#about').val();
	 var contact= $('#contact').val();
	 var present= $('#present').val();
	 var inter= $('#inter').val();
	 var high= $('#high').val();
	 var books= $('#books').val();
	 var sports= $('#sports').val();
	 var pastime= $('#pastime').val();
	 var interest= $('#interest').val();
	 console.log (about);

  $.ajax({
        url:'update-profile.php',
		type:'POST',
		data: 'contact=' + contact + '&about=' + about + '&present=' + present + '&inter=' + inter + '&high=' + high + '&books=' + books + '&sports=' + sports + '&pastime=' + pastime + '&interest=' +interest,
		success: function(result){
		    $('#response').remove();
		    $('#load').append('<p id="response">' + result + '</p>');
		    $('#loading').fadeOut(500,function(){
		    $(this).remove();
		      });
	        }
    
	});
	return false;
  
  });
   
   });
  
</script>

</head>
<body>
<!-- start header -->
<div id="wrapper">
<div id="header">
<div id="logo">
	<h1><a href="#">ABC</a></h1>
	<p><a href="#">cinemas</a></p>
</div>
        
<?php
{
if(isset($_SESSION['name'])){
echo "<p id=\"welcome\">";
echo "Welcome ".$_SESSION['name'];
echo "                 ";
echo "<a href=\"logout.php\">";
echo "Logout";
echo "</a>";
echo "</p>";
}
}?>



</div>
</div>
<!-- end header -->
<!-- star menu -->
<div id="menu">
<ul>
	<li class="current_page_item">
	 <?php
           {
            if(isset($_SESSION['name'])){
		echo "<a href=\"index1.php\">Home</a></li>";
		}
		else{
		echo "<a href=\"index.html\">Home</a></li>";}}
		?>
	<li><a href="shows.php">Shows</a></li>
	<li><a href="umovies.php">Upcoming Movies</a></li>
	<li><a href="#">Reviews</a></li>
                <li><a href="#">Book Tickets</a></li>
	<li><a href="contact.html">Contact</a></li>
</ul>
</div>
<!-- end menu -->
<!-- start page -->
<div id="page">
<!-- start ads -->

<!-- end ads -->
<!-- start content -->
<div id="content">
	<div class="post">
		<div class="title">

			<h2>My Profile            <a href="edit-profile.php">Edit Profile</h2></a>
		</div>
		<div class="entry">
		<form action="update-profile.php" method="post">


			<p style="color:white"><a href="upload.php">Change photo</a><br/>

            <img src=<?php echo $_SESSION['img'] ?> width='120px' height='140px' class='left' alt='image' />
		 <strong>Contact:-</strong><input type="text" name="contact" id="contact" value="<?php echo $_SESSION['contact']; ?>" /><br/>
		 About:-<textarea  name="about" id="about" rows="5" cols="38" ><?php echo $_SESSION['about']; ?> </textarea><br/>
		</p>

		</div>


            <p style="color:white">Education:<br/>
               <strong>Present:-</strong>      <input type="text" id="present" name="present" size="25" value="<?php echo $_SESSION['present']; ?>" /> <br/>
               <strong>Inter:-          </strong><input type="text" id="inter" name="inter" size="25"value="<?php echo $_SESSION['inter']; ?>" /><br/>
                <strong>High School:-</strong><input type="text" id="high" name="high" size="25" value="<?php echo $_SESSION['high']; ?>" /><br/>
                <br><br>
                 <strong>Favourite Books:-</strong><input type="text" id="books" name="books" size="30" value="<?php echo $_SESSION['books']; ?>" /><br/>
                 <strong>Favourite Sport:-</strong><input type="text" id="sports" name="sports" size="30" value="<?php echo $_SESSION['sports']; ?>" /><br/>
                 <br/><br/>
                 <strong>Pastimes:-</strong><input type="text" name="pastime" id="pastime" size="25" value="<?php echo $_SESSION['pastime']; ?>" /><br/>
                 <strong>Interests:-</strong><input type="text" name="interest" id="interest" size="25" value="<?php echo $_SESSION['interests']; ?>" /><br/><br/>
			 <input type="submit" id="submit" value="Update" />
			 <div id="load></div>
			 </form>



	</div>


<!-- end page -->
<!-- start footer -->
<div id="footer">
<p class="legal">
	©2010ABC Cinemas. All Rights Reserved.
	  •  
	Design by <a href="#/">Pulkit</a>
	    
	 </p>
<p class="links">
	<a href="http://validator.w3.org/check/referer" class="xhtml" title="This page validates as XHTML">Valid <abbr title="eXtensible HyperText Markup Language">XHTML</abbr></a>
	 • 
	<a href="http://jigsaw.w3.org/css-validator/check/referer" class="css" title="This page validates as CSS">Valid <abbr title="Cascading Style Sheets">CSS</abbr></a>
</p>
</div>
</div>
<!-- end footer -->
</body>
</html>

update-profile.php


<?php
session_start();
$connection=mysql_connect("localhost","root","");
mysql_select_db("TRIAL",$connection);

if(mysql_query("UPDATE tab SET about='$_POST[about]',contact='$_POST[contact]',present='$_POST[present]',inter='$_POST[inter]',high='$_POST[high]',books='$_POST[books]',sports='$_POST[sports]',pastime='$_POST[pastime]',interests='$_POST[interest]' WHERE name='$_SESSION[name]'")){
  echo "Successfully uploaded the data.<a href='index.php'>Click here</a> to return back.";
  }
  else
  echo "Unable to upload";
  ?>

February 17, 2011

It had to update the user information in the database but it shows unable to upload when i remove the jquery there but shows no message when i use jquery.

February 17, 2011

I have a php script wihich updates data in mysql db named 'trial' and table named 'tab'

I am using jquery and ajax to update the db. but the script is not working.

edit-profile.php

<code>

<?php

session_start();

$img=$_SESSION['img'];

?>

<html>

<head>

</script>

$(function(){

$('#submit').click(function(){

$('#load').append('<img src="ajax-loader.gif" id="loading" alt="image" />');

var about= $('#about').val();

var contact= $('#contact').val();

var present= $('#present').val();

var inter= $('#inter').val();

var high= $('#high').val();

var books= $('#books').val();

var sports= $('#sports').val();

var pastime= $('#pastime').val();

var interest= $('#interest').val();

console.log (about);

$.ajax({

url:'update-profile.php',

type:'POST',

data: 'contact=' + contact + '&about=' + about + '&present=' + present + '&inter=' + inter + '&high=' + high + '&books=' + books + '&sports=' + sports + '&pastime=' + pastime + '&interest=' +interest,

success: function(result){

$('#response').remove();

$('#load').append('<p id="response">' + result + '</p>');

$('#loading').fadeOut(500,function(){

$(this).remove();

});

}

});

return false;

});

</script>

</head>

<body>

<p><a href="#">cinemas</a></p>

</div>

<?php

{

if(isset($_SESSION['name'])){

echo "<p id=\"welcome\">";

echo "Welcome ".$_SESSION['name'];

echo " ";

echo "<a href=\"logout.php\">";

echo "Logout";

echo "</a>";

echo "</p>";

}

}?>

</div>

<ul>

<?php

{

if(isset($_SESSION['name'])){

echo "<a href=\"index1.php\">Home</a></li>";

}

else{

echo "<a href=\"index.html\">Home</a></li>";}}

?>

<li><a href="shows.php">Shows</a></li>

<li><a href="umovies.php">Upcoming Movies</a></li>

<li><a href="#">Reviews</a></li>

<li><a href="#">Book Tickets</a></li>

<li><a href="contact.html">Contact</a></li>

</ul>

</div>

<h2>My Profile <a href="edit-profile.php">Edit Profile</h2></a>

</div>

<p style="color:white"><a href="upload.php">Change photo</a><br/>

<img src=<?php echo $_SESSION['img'] ?> width='120px' height='140px' class='left' alt='image' />

<strong>Contact:-</strong><input type="text" name="contact" id="contact" value="<?php echo $_SESSION['contact']; ?>" /><br/>

About:-<textarea name="about" id="about" rows="5" cols="38" ><?php echo $_SESSION['about']; ?> </textarea><br/>

</p>

</div>

<p style="color:white">Education:<br/>

<strong>Present:-</strong> <input type="text" id="present" name="present" size="25" value="<?php echo $_SESSION['present']; ?>" /> <br/>

<strong>Inter:- </strong><input type="text" id="inter" name="inter" size="25"value="<?php echo $_SESSION['inter']; ?>" /><br/>

<strong>High School:-</strong><input type="text" id="high" name="high" size="25" value="<?php echo $_SESSION['high']; ?>" /><br/>

<strong>Favourite Books:-</strong><input type="text" id="books" name="books" size="30" value="<?php echo $_SESSION['books']; ?>" /><br/>

<strong>Favourite Sport:-</strong><input type="text" id="sports" name="sports" size="30" value="<?php echo $_SESSION['sports']; ?>" /><br/>

<strong>Pastimes:-</strong><input type="text" name="pastime" id="pastime" size="25" value="<?php echo $_SESSION['pastime']; ?>" /><br/>

<strong>Interests:-</strong><input type="text" name="interest" id="interest" size="25" value="<?php echo $_SESSION['interests']; ?>" /><br/><br/>

</form>

</div>

•

Design by <a href="#/">Pulkit</a>

</p>

<a href="http://validator.w3.org/check/referer" class="xhtml" title="This page validates as XHTML">Valid <abbr title="eXtensible HyperText Markup Language">XHTML</abbr></a>

•

<a href="http://jigsaw.w3.org/css-validator/check/referer" class="css" title="This page validates as CSS">Valid <abbr title="Cascading Style Sheets">CSS</abbr></a>

</p>

</div>

</body>

</html>

</code>

update-profile.php

<code>

<?php

session_start();

$connection=mysql_connect("localhost","root","");

mysql_select_db("TRIAL",$connection);

if(mysql_query("UPDATE tab SET about='$_POST[about]',contact='$_POST[contact]',present='$_POST[present]',inter='$_POST[inter]',high='$_POST[high]',books='$_POST[books]',sports='$_POST[sports]',pastime='$_POST[pastime]',interests='$_POST[interest]' WHERE name='$_SESSION[name]'")){

echo "Successfully uploaded the data.<a href='index.php'>Click here</a> to return back.";

}

else

echo "Unable to upload";

?>

</code>

February 13, 2011

I have a login script which is showing problem.

The problem is that when my username and password are correct it directs to index.php page and displays the correct username there.

But if the password is wrong it still directs to the same page instead of different(err-login.php) page,but this time no username is displayed.

index.php:

the password verifying code is as follows(the whole code of index.php is not mentioned since it is too long and a bit messy)

<code>

<?php

$connection=mysql_connect("localhost","root","");

mysql_select_db("forum",$connection);

$select=mysql_query("SELECT * FROM user_id WHERE uname='$_REQUEST[uname]'",$connection);

$row=mysql_fetch_array($select);

if($row['password']==$_REQUEST['password']){

session_start();

$_SESSION['name']=$_REQUEST['uname'];

}

else{

header("Location:err-login.php");

}

?>

</code>

NOTE:-The name of my db and table are correct.

I have referred to username as uname.

February 13, 2011

Thnx,

I just changed 'add' to 'adds' and now it is working.!

February 13, 2011

can u just clarify the use of backticks.. a little more.!

February 13, 2011

When i use

mysql_error($conns);

the output is:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'add,phone) VALUES ('pulkit',pulkit@gmail.com','26','3','1991','lucknow','9000463' at line 1

I am still unable to find out the error.

NOTE:-All my table entries are VARCHAR

February 13, 2011

Hello....I am using ajax,jquery with php to insert data in db.....but the script is not working.

form.html:


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<style type="text/css">
label{
display:block;
}
</style>
<script type="text/javascript" src="jquery-1.5.min.js">
</script>
<script type="text/javascript">
$(function()
{
   $('#submit').click(function(){
   $('#container').append('<img src="ajax-loader.gif" id="loading" alt="image" />');
   
   var name=$('#name').val();
   var email=$('#email').val();
   var d=$('#d').val();
   var m=$('#m').val();
   var y=$('#y').val();
   var add=$('#add').val();
   var phone=$('#phone').val();
   $.ajax({
      url: 'process.php',
      type: 'POST',
      data: 'name=' + name + '&email=' + email + '&d=' + d + '&m=' + m + '&y=' + y + '&add=' + add + '&phone=' + phone,
      success: function(result){
         $('#response').remove();
         $('#container').append('<p id="response">' + result + '</p>');
         $('#loading').fadeOut(500,function(){
         $(this).remove();
         });
      }
      });
      return false;
   
      
   });
      
   
});

</script>

</head>

<body>
<h2>User Registeration</h2>
<form action="process.php" method="POST">
    <div id="container">

     Name:<br>
   <input type="text" name="name" id="name" /><br>
   Email:<br>
   <input type="text" name="email" id="email" /><br>
   Date Of Birth:<br>
   <input type="text" id="d" name="d" size="2" />
   <input type="text" id="m" name="m" size="2" />
   <input type="text" id="y" name="y" size="4" /><br>
   Address:<br>
   <input type="text" id="add" name="add" /><br>
   Phone:<br>
   <input type="text" id="phone" name="phone" /><br>
   
   <input type="submit" name="submit" id="submit" value="GO!" />
   </div>
</form>

</body>
</html>

process.php

My db id named "jquery" and table is "tab"


<?php
$conns=mysql_connect("localhost","root","");
if(!$conns)
echo "error in connection";
mysql_select_db("jquery", $conns);

$name=$_POST['name'];
$email=$_POST['email'];
$m=$_POST['m'];
$d=$_POST['d'];
$y=$_POST['y'];
$add=$_POST['add'];
$phone=$_POST['phone'];


echo $name,"<br>";
echo $email,"<br>";
echo $m, "<br>";
echo $d,"<br>";
echo $y,"<br>";
echo $add, "<br>";
echo $phone,"<br>";

$query="INSERT INTO tab (name,email,d,m,y,add,phone) VALUES ('$name',$email','$d','$m','$y','$add','$phone')";
if(!mysql_query($query,$conns))
echo "Error";
else
echo "DATA inserted";
?>

The output shown is:

pulkit

pulkit@gmail.com

1

26

1991

lucknow

987576787

Error

For some values i entered.

February 12, 2011

I dont know whether the statement is correct.....i just tried it.....and it didn't work.

$stmt->bind_param('ssiiiss',$_POST['name'],$_POST['email'],$_POST['d'],$_POST['m'],$_POST['y'],$_POST['add'],$_POST['phone']);

here my first two values are strings and next 2 tiny int's next is int and last 2 again strings.

February 11, 2011

my script is not working.I wanted to insert data from a form to db

using ajax and jquery...showing a loading icon as data is passed.

It shows that data inserted but does not insert.

form.html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.0/jquery.min.js">
</script>
<script type="text/javascript">
$(function()
{
$('#submit').click(function(){
$('#container').append('<img src="ajax-loader.gif" id="loading" />');

var name=$('#name').val();
var email=$('#email').val();
var comments=$('#comments').val();

$.ajax({
	url: 'process.php',
	type: 'POST',
	data: 'name=' + name + '&email=' + email + '&comments=' + comments,
	success: function(result){
		$('#response').remove();
		$('#container').append('<p id="response">' + result + '</p>');
		$('#loading').fadeOut(500);
	}
	});


});


});

</script>
</head>

<body>
<form action="process.php" method="post">
    <div id="container">

Name:<br />
<input type="text" name="name" id="name" /><br>
Email:<br />
<input type="text" name="email" id="email" /><br>
Comments:<br>
<textarea rows="5" cols="30" name="comments" id="comments">
</textarea><br>
<input type="submit" name="submit" id="submit" value="GO!" />
</div>
</form>

</body>
</html>

process.php:

<?php
$conns=new mysqli('localhost','root','','jquery_ex');
$query="INSERT into tab1 (name, email, comments) VALUES (?,?,?)";
$stmt=$conns->stmt_init();
if($stmt->prepare($query)){
$stmt->bind_param('sss','$_POST[name]','$_POST[email]','$_POST[comments]');
$stmt->execute();
}

if($stmt){
echo "Successfully inserted the data";
}else{
echo "Error";
}
?>

February 2, 2011

can u provide me with some links wherein i can find some good stuff about working with files....?

January 30, 2011

I am unable to upload image to db,

I get a message "No image selected/uploaded" after every trial,

My HTML form is:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form enctype="multipart/form-data" action="insert.php" method="post">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>
</body>
</html>

and my php script "insert.php" is-

<?php
// Create MySQL login values and 
// set them to your login information.
$username = "root";
$password = "";
$host = "localhost";
$database = "test";

// Make the connect to MySQL or die
// and display an error.
$link = mysql_connect($host, $username, $password);
if (!$link) {
    die('Could not connect: ' . mysql_error());
}

// Select your database
mysql_select_db ($database); 

// Make sure the user actually 
// selected and uploaded a file
if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) { 

      // Temporary file name stored on the server
      $tmpName  = $_FILES['image']['tmp_name'];  
       
      // Read the file 
      $fp      = fopen($tmpName, 'r');
      $data = fread($fp, filesize($tmpName));
      $data = addslashes($data);
      fclose($fp);
      

      // Create the query and insert
      // into our database.
      $query = "INSERT INTO tbl_images ";
      $query .= "(image) VALUES ('$data')";
      $results = mysql_query($query, $link);
      
      // Print results
      print "Thank you, your file has been uploaded.";
      
}else{
   print "No image selected/uploaded";
}

// Close our MySQL Link
mysql_close($link);
?>

my table consists if an "id" and an "image" of type "blob".

January 30, 2011

Can you brief me on MyISAM engine.

January 30, 2011

Can't understand what "TYPE=MyISAM AUTO_INCREMENT=1 ;" means in this code:

CREATE TABLE `web_members` (

`id` int(4) NOT NULL auto_increment,

`name` varchar(65) NOT NULL default '',

`lastname` varchar(65) NOT NULL default '',

`email` varchar(65) NOT NULL default '',

PRIMARY KEY (`id`)

) TYPE=MyISAM AUTO_INCREMENT=1 ;

January 29, 2011

Yeah I got it...but still when we modify scripts we use it:

Consider this code

$x="INSERT INTO user_id (name,uname,password,email,contact) VALUES ('$_POST[name]','$_POST[uname]','$_POST[password]','$_POST','$_POST[contact]')";

It is working fine.....

whereas when i changed it to $_POST['name'] it was giving error.

January 29, 2011

@doddsey_65

Sorry for the messy code....

It was because my friend handles all the html+css and I handle the php..So i did not try to make any efforts there...!

I have some problems here:

like what is the difference b/w $row['name'] and '$row[name]'

...??

I always had trouble in this quoting stuff..

January 29, 2011

Somehow I was able to manage the problem.

What i did was that my earlier script was:

<h2><?php

{

if(isset($_SESSION['name']))

echo "Welcome ".$_SESSION['name'];

}

?></h2>

I only removed that h2 element and inserted in echo like this:

if(isset($_SESSION['name']))

echo "<h2>Welcome ".$_SESSION['name'],"</h2>";

And now it is working fine..!

January 29, 2011

I have written my index.php script where after verifying the password the script displays the user's name.

But the user name is not displayed by it.

Here is my script

[attachment deleted by admin]

January 21, 2011

Sir I know how to make Http request objects but not more than that.But i can understand the scripts.

I am presently working with ajax(studying it)

January 21, 2011

I am new to ajax and i am unable to implement ajax form validation.

I want to validate username before submission of from by the user.

Can anyone provide me with a sample script.

regards,

Pulkit

November 24, 2010

Hello sir,

I am working on ajax..and i m new to it....so my script is not working properly.......my ajax script is as under:

<html>

<head>

<title>Using ajax</title>

var request = false;

try {

request = new XMLHttpRequest();alert("object created");

} catch (trymicrosoft) {

try {

request = new ActiveXObject("Msxml2.XMLHTTP");

} catch (othermicrosoft) {

try {

request = new ActiveXObject("Microsoft.XMLHTTP");

} catch (failed) {

request = false;

}

if (!request)

alert("Error initializing XMLHttpRequest!");

function process() {

var name = document.getElementById("name").value;

var password=document.getElementById("passwd").value;

alert(name);

var url = "process-form.php?name=" + escape(name);

request.open("GET", url, true);

request.onreadystatechange = updatePage;

request.send(null);

}

function updatePage() {

alert("Server is done!");

}

</script>

</head>

<body>

<h2><p align="center">Please fill the form</p></h2>

Name:

Password:

</form>

</body>

</html>

and my php script is:

<html>

</head>

<body>

<?php

$connection=mysql_connect("localhost","root","");

if(!$connection)

{

die('unable to connect '.mysql_error());

}

echo"$name<br/>";

?>

</body>

</html>

only it is popping an alert box.....that says "object created"

then after pressing enter...it again shows the form

pls help me out here..

November 7, 2010

yes sir,i am using it on xampp via http://localhost

and my form is on index.html.....which uses php script login.php

now when i tried header("location:index1.html")

there was no effect............the redirected page is blank.....and in address bar contains address of login.php

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cool_techie

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