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marain

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Everything posted by marain

  1. $oneday = strtotime("1 days"); $date = strval($post_e); while(abs( strtotime($post_e) - strtotime($post_f) ) / 86400 <= 1) { $post_e = strtotime($post_e) + $oneday; $date = $date + "," + strval(date('d/m/Y'),$post_e); } echo $date; maybe your question is wrong
  2. I dont know this answer if is your mean. im chinese . i understand your mean;
  3. $oneday = strtotime("1 days"); $date = strval($post_e); for(i=1;i<0;i++){ $post_e = $post_e + $oneday; if(abs($post_e - strtotime($post_f))/86400>0){ breakļ¼› }else{ $date = $date + "," + strval($post_e); } } echo $date;
  4. why insert into this date?? why not in select? sql = "select * from table where date between time1 and time2"
  5. marain

    Input image.

    I dont know ur mean. what's a corner of the input <input type="submit"> or other? and then I can answer u
  6. u can do it. but only use url to pass. site 1 code $value = $_post["name"]; and then use javascript open "site2.com/xxx.php?name="+$value site 2 code $value = $get["name"] but the values is not safe sorry, im english is not good im chinese
  7. the php is too difficult
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