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gazapo

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Everything posted by gazapo

  1. Wow, nevermind. I ended up not needing to use that function in that case anyway so I just dropped the table since it was only used for that. Thanks for taking a look.
  2. This is the weirdest thing ever. I've been programming php for years yet I have been pulling my hair out for hours over something that seems so simple! I have a table in my db named last_num_used with 2 fields: id, num which are both type int. It only has one row, so I don't need to use WHERE to update when I execute the command via php: $sql = "UPDATE last_num SET num='4'"; echo $sql; if (!mysql_query($sql)) {die('Error: ' . mysql_error());} everything works fine and I see the echoed command UPDATE last_num SET num='4' But, when I have a variable $var and try to update it, it will only update properly if $var=1 or $var=2. If $var equals a value greater than 2, then for some reason it updates the column so that num=1. Note the exact problem in example 3 below. Example 1: $var=1; $sql = "UPDATE last_num SET num='$var'"; echo $sql; if (!mysql_query($sql)) {die('Error: ' . mysql_error());} Result: echoed to screen: UPDATE last_num SET num='1' database updated and num=1 Example 2: $var=2; $sql = "UPDATE last_num SET num='$var'"; echo $sql; if (!mysql_query($sql)) {die('Error: ' . mysql_error());} Result: echoed to screen: UPDATE last_num SET num='2' database updated and num=2 Example 3: $var=3; $sql = "UPDATE last_num SET num='$var'"; echo $sql; if (!mysql_query($sql)) {die('Error: ' . mysql_error());} Result: echoed to screen: UPDATE last_num SET num='3' database updated and num=1
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