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freemancomputer

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Posts posted by freemancomputer

    Moving from php 5.3 to 5.2

    in PHP Coding Help

    Posted

    Lines 1-3 are as follows

     

    1   <?php ini_set ("display_errors", "1");
2   error_reporting(E_ALL);
3   ?>

     

    removed line 13 so it is now as follows

     

    10  header("location:login.php");
11  }
13  ?>
14  <?php
15  $rank=$_SESSION['rank'];

     

    The errors are the same the last one being at line 14 now

     

    Thank you

    Moving from php 5.3 to 5.2

    in PHP Coding Help

    Posted

    I am moving to a different hosting site that is using php 5.2 from one that has 5.3. I am running into an error with my session_start() that worked just fine before. Was wondering if I could get some pointers.

     

    These are the errors that I get

     

    Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started atindex.php:10) in header.php on line 5

     

    Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at index.php:10) in header.php on line 5

     

    Notice: Undefined index: login in header.php on line 6

     

    Notice: Undefined index: rank in header.php on line 7

     

    Notice: Undefined variable: loggedinusername in header.php on line 8

     

    Notice: Undefined variable: loggedinuseremail in header.php on line 9

     

    Warning: Cannot modify header information - headers already sent by (output started at index.php:10) in header.php on line 10

     

    Notice: Undefined index: rank in header.php on line 15

     

     

    This is what I have in my header that is included in every page.

    4   <?
5   session_start();
6   if(!$_SESSION['login']){
7   $_SESSION['rank'];
8   $_SESSION['loggedinusername'] = $loggedinusername;
9   $_SESSION['loggedinuseremail'] = $loggedinuseremail;
10  header("location:login.php");
11  }
12  ?>
13
14  <?php
15  $rank=$_SESSION['rank'];
16  $loggedinusername=$_SESSION['loggedinusername'];
17  $loggedinuseremail=$_SESSION['loggedinuseremail'];
18  ?>

    user validation via email

    in PHP Coding Help

    Posted

    I am working on user validation through email and I am having some problems with it. I can get it to work but it gives me probloms some times.

     

    This is the link that is sent to the users after they sign up

    mydomain/confirm.php?id=".$id."&userkey=".$userkey

     

    and this is what i have for the confirm page

     

    <?php

//connection info

	$userquery = mysql_query("SELECT * FROM user");
	$active=mysql_result($userquery,  "active");
	$userid=mysql_result($userquery,  "id");
	$userkey=mysql_result($userquery, "userkey");


	if ($active == 1) {

		printf("This account has already been activated");
		echo "<br />";
	}

	elseif($userkey != $posteduserkey){
	printf("We are sorry but the data offered does not match data listed, plese contact system admin.");
	}

	else{
	$query="UPDATE user SET active='1' WHERE id='$id'";

	mysql_query($query) or die (mysql_error());  


	echo "You have activated your account";

	?>
	<div align="center"><br /><a href="login.php" class="nav">Back to the log in page</a></div>

	<?php
	}

?>

    This is the fun part. I checked that the id and userkey are correct in the link, and they are. I then replaced the & in the link with & it works in gmail but not yahoo email address. I'm not sure where else to look.

     

    Thanks in advance

     

    Adding a comment area to a dynamic page

    in PHP Coding Help

    Posted

    I am looking to add a comment area to pages that are created with data that is pulled off of a database. I am looking for something like the forums on this site, but not as complex. I was thinking about attempting to use a text file to hold the comments for each ID number that is in my database and then displaying those comments when the ID number is called. I'm not sure how I would go about making a function that would search if there was a text file for that ID number and if not to create one. I'm not even sure if this is the best way to go about it but I know if I put all the comments into a database it will get rather large rather quickly. Any pointers and good tutorials would be welcome.

     

    Sorry if it sounds as if this post is rambling, I think I need to step away from the computer for a bit.

     

    Thanks

    user privileges

    in PHP Coding Help

    Posted

    I am attempting to have some links show up on my page only if a user is an admin. The way I have the user data base is user name password and rank. rank is a 1 or 2, 2 for admin. This is what I have right now as a test bed, I think the rank variable is not being passed properly but I'm not sure.

     

    Thanks in advance.

     

    This is what i have for the log in page

    <?php
//connection stuff

$sql="SELECT * FROM user WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);


$count=mysql_num_rows($result);
$rank=mysql_num_rows('rank');


if($count==1){
session_start(); 
$_SESSION['login'] = "1"; 
$_SESSION['rank'] = $rank;
header ("Location:index.php");
} else { 
$errorMessage = "Invalid Login"; 
session_start(); 
$_SESSION['login'] = '';
} 
?>

     

    This is the header that will be on every page to keep the session.

    <?php ini_set ("display_errors", "1");
error_reporting(E_ALL);
?>
<?php
session_start();
if(!$_SESSION['login']){
$_SESSION['rank'];
header("location:login.php");
}
?>

<?php
$rank=$_SESSION['rank'];
?>

     

    And this is what I have to show the link.

    <?php
if($rank<=2){
?>
<tr>
<td><span class="nav"><a href="link">link</a></span><br /></td>
</tr>
<?php
}
?>

    Adding diffrent uer levels to a page

    in PHP Coding Help

    Posted

    I just added a user log on for a site I am building using PHP.  I used a simple session based system for this. I can log on just fine. What I am looking for is a way to pass on in ht session what rank a user is so some links/pages will only show for the admin or the super user but not the normal user. I rank the users as Admin 1, superuser 2, and user 3.

     

    This is what I have for the session in my header that allows you to be logged in.

    <?
session_start();
if(!session_is_registered(myusername)){
header("location:login.php");
}
?>

     

    Here is what I have that starts the session

    
//Connection stuff

$query="SELECT * FROM user WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($query);

$count=mysql_num_rows($result);

if($count==1){

session_register("myusername");
session_register("mypassword");
header("location:index.php");
}
else {
echo "Wrong Username or Password";
}

ob_end_flush();
?>

    Spliting data into colums

    in PHP Coding Help

    Posted

    I have been working on a way to split my data into 2 columns as a way to make the page shorter and easier to read. I have been able get it to split like this

     

    1 2

    3 4

    5 6

     

    But I would rather it go like this, because it would be easier on the eyes.

     

    1 4

    2 5

    3 6

     

    This is what I have now, I have no idea if I'm even on the right track.

      <?php
include"scripts/connect.php" ;

mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM movies WHERE type LIKE 'tv' ORDER BY title";
$result=mysql_query($query);

$num=mysql_numrows($result);

mysql_close();
?>
<table width="70%" align="left">

<?php
$i=0;
while ($i < $num/2)
{

$title=mysql_result($result,$i,"title");

?>
<tr>
<td><a class="nav" href=/show.php?title=<?php echo urlencode($title); ?>><?php echo $title; ?></td>



<?php
while ($i >= $num/2)
{
?>

<td><a class="nav" href=/show.php?title=<?php echo urlencode($title); ?>><?php echo $title; ?></td>
</tr>


<?php
}
$i++;

}

?>
</table>

     

    This will show only the first half of the titles.

     

    Thanks in advance.

    colums and links

    in PHP Coding Help

    Posted

    jcbones thanks for the reply. When I added that and go to the page I get the page, header, footer and the such just none of the data that should be there. Going to look at it to see if I can figure it out.

     

    Thanks again

    colums and links

    in PHP Coding Help

    Posted

    I am trying to get the output for a mysql query to be displayed in colums. I have it where it does this but it goes from left to right. I would rather it go from top to bottem, it would look better this way. I will also need it to brake into sevral pages when there are a certain amout of entrys shown. If you know of a  good how to on that let me know please.  The other problom that I am having is to make the output a link. I was able to do this before I attemped to devide everything but if I add in what I had before it comes back with no data.

     

    Here's what I have now that put shows the data from left to right in 2 colums.

     

     <?php
include"scripts/connect.php" ;

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM movies WHERE type LIKE 'movie' ORDER BY title";

if(mysql_query($query))
{
$result=mysql_query($query);

$num=mysql_numrows($result);

}


for($i=0; $i<$num; $i++)
{
if($i%2==0){
echo "<tr><td>";
} 
else{
echo "<td>";
}

print mysql_result($result,$i,"title");

if ($i%2==0){
echo "</td>";
}
else{
echo "</td>";
}
}
echo "</tr>";
?>

     

    Thanks in advance

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