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barocky82

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  1. Thanks for the help Pikachu2000! I just need the rounded result.
  2. I stand corrected. It worked perfectly....I found a space in $average = $row[' my_avg']; . I removed the space before the 'M' and I'm all set. Thanks a bunch!!
  3. Thanks for the the quick response, Ken! Unfortunately, that didn't do the trick either. Here is what my code looks like now per your request: function avg_of($column_name) { global $connect_db; $query = "SELECT user_id, AVG($column_name)as my_avg FROM table GROUP BY user_id"; $result = mysql_query($query, $connect_db); $row = mysql_fetch_assoc($result); $average = $row[' my_avg']; $round_val = round($average, 1); return $row; I'm not getting a zero as the average when it should be '5'. If I return $row instead of $round_val, I get "Array ( [user_id] => 64 [my_avg] => 5.0000 )". For some reason it doesn't seem like the extraction of the 'my_avg' key from the $row array is working. Any other thoughts? Thanks again for you help!
  4. Hi Guys, I'm a PHP newbie and I'm having some trouble creating a function that I can call where I can perform a MYSQL SELECT querey which returns an associative array, and be able to pull a value from that array and return it to the call. My code is below. Everything seems to work up until where I try to set the $average variable. If I return $row instead of $round_val, I see me array as "Array ( [user_id] => 64 [AVG(twos_made)] => 5.0000 )" It seems as though my my functions arugment (twos_made - which is my $column_name var) is not getting passed through or something. Any help would be greatly appreciated! Thanks! function avg_of($column_name) { global $connect_db; $query = "SELECT user_id, AVG($column_name) FROM table GROUP BY user_id"; $result = mysql_query($query, $connect_db); $row = mysql_fetch_assoc($result); $average = $row['AVG($column_name)']; $round_val = round($average, 1); return $round_val; }
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