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zrodimel

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Everything posted by zrodimel

  1. you are the man! Thank you so much... i've been wrestling with this for hours.
  2. Hi, first of all thanks in advance for the help. I'm a newbie college student and am having a little problem with a project for a class that I can't figure out. I'm trying to construct a loop that creates an array for a javascript image gallery. First I call for the categories and I want to then pull all the images from that category into the array and then loop through all the categories in the database. The code below just cycles through the first category and then quits after pulling the images from that category. <?php // SQL Query for Categories $sql="SELECT CategoryID, CategoryName FROM pro2category"; $result = mysql_query($sql); if(empty($result)) { $num_results = 0; } else { $num_results = mysql_num_rows($result); } ?> <?php for($i=0; $i<$num_results; $i++) { $row = mysql_fetch_array($result); $CategoryID = $row["CategoryID"]; $CategoryName = $row["CategoryName"]; ?> var <?php echo $CategoryID ?> = new Array(); <!-- Images inside Array --> <!-- Images inside Array --> <!-- Images inside Array --> <!-- Images inside Array --> <?php $sql="SELECT ImageID, ImageName, ImageNumber, URL, CategoryID FROM pro2image WHERE CategoryID='$CategoryID'"; $result = mysql_query($sql); if(empty($result)) { $num_results = 0; } else { $num_results = mysql_num_rows($result); } ?> <?php for($i=0; $i<$num_results; $i++) { $row = mysql_fetch_array($result); $ImageID = $row["ImageID"]; ?> <?php echo $CategoryID ?>Array[<?php echo $i ?>] = "http://cgtweb2.tech.purdue.edu/356/zrodimel/Project2/admin/upload/<?php echo $ImageID ?>.jpg"; <?php } ?> <?php } ?> thanks for the help Zach
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