richiejones24
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Everything posted by richiejones24
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Getting individual data from an array
richiejones24 replied to richiejones24's topic in PHP Coding Help
if i use $filename by itself i can everything in the array is i know it is working but when i use $filename[0] i get nothing -
Getting individual data from an array
richiejones24 replied to richiejones24's topic in PHP Coding Help
yes it is -
I am having problems displaying individual data I am using $filename[0] to display the first data, any ideas where i am going wrong. <?php $active_keys = array(); foreach($_POST['img'] as $key => $filename) { if(!empty($filename)) { $active_keys[] = $key; } echo "". $filename[1]; } ?>
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I've tried changing my form to this, but its still not working <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action="testd.php"> <p> <label> <input type="text" name="img[]"><br> <input type="text" name="img[]"><br> <input type="text" name="img[]"><br> <input type="text" name="img[]"><br> <input type="text" name="img[]"><br> <label> <input type="submit" name="Submit" id="Submit" value="Submit" /> </label> </p> </form> </body> </html> but i still keep getting the following error: Warning: Invalid argument supplied for foreach() in /homepages/22/d378569747/htdocs/testd.php on line 4
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the array is just one part of a bigger script, how would i fix the form so it works?
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ye this is the form i am going to use <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <p> <label> <input type="text" name="img[]" id="img[]" /> </label> </p> <p> <input type="text" name="img2[]" id="img2[]" /> </p> <p> <input type="text" name="img3[]" id="img3[] " /> <label> <input type="submit" name="Submit" id="Submit" value="Submit" /> </label> </p> </form> </body> </html>
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yes its 6 values
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how do i put it in an array?
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I am trying my hand at using an array i have never done it before, and I am having some problems getting it work work. if someone could point me in the right direction? Thanks <?php $active_keys = array(); foreach($_GET['img'] as $key => $filename) { if(!empty($filename)) { $active_keys[] = $key; } } ?>
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The script below used to work fine but the HTTP_REFERER was unreliable so i added a re-direct if the HTTP_REFERER was unavailable and now nothing is being added to the MySQL BD, the script runs ok ie it sends the user back to where they come from, any ideas what could be wrong? <?php require("../include/mysqldb.php"); $uinwish = $_GET['uinwish']; $wishrefer = $_SERVER['HTTP_REFERER']; $wishdate = mktime(0, 0, 0, date("m"), date("d")+3, date("Y")); $rand_wish_cookie = $_COOKIE["wishtracking"]; $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); //DB Stuff start code below //check if the uin and cookie have already been stored together. $sql = "select * from Wish_list_guest where usercookie='$rand_wish_cookie' and uinwish='$uinwish'"; $result = mysql_query($sql); $row = mysql_fetch_row($result); if (mysql_num_rows($result)!= 1) { $issetvar = "1"; if (!isset ($wishrefer)){ $host = $_SERVER['HTTP_HOST']; $extra = 'profile.php?uin='; header("Location: http://$host/$extra$uinwish"); exit; } if (isset ($wishrefer)){ header("Location: $wishrefer"); exit; } } if ($issetvar = 1) { mysql_query("INSERT INTO Wish_list_guest (usercookie, date_delete, uinwish, referwish) VALUES ('$rand_wish_cookie', '$wishdate', '$uinwish', '$wishrefer')"); mysql_close($con); if (!isset ($wishrefer)){ $host = $_SERVER['HTTP_HOST']; $extra = 'profile.php?uin='; header("Location: http://$host/$extra$uinwish"); exit; } if (isset ($wishrefer)){ header("Location: $wishrefer"); exit; } } ?>
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hello, might be a stupid question but can you put an if and else inside of if brackets like i have done in this script? <?php require("../include/mysqldb.php"); $uinwish = $_GET['uinwish']; $wishrefer = $_SERVER["HTTP_referer"]; $wishdate = mktime(0, 0, 0, date("m"), date("d")+3, date("Y")); $rand_wish_cookie = $_COOKIE["wishtracking"]; $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); $sql = "select * from Wish_list_guest where usercookie='$rand_wish_cookie' and uinwish='$uinwish'"; //search db has the profile already been added to favorites $result = mysql_query($sql); $row = mysql_fetch_row($result); if (mysql_num_rows($result)!= 1) { //if 1 of more results found profile already added redirect back! //Re-direct back script!! if (!isset ($wishrefer)){ $host = $_SERVER['HTTP_HOST']; $uri = rtrim(dirname($_SERVER['PHP_SELF']), '/\\'); $extra = 'profile.php?uin='; header("Location: http://$host/$extra$uinwish"); exit; } else { header("Location: $wishrefer"); exit; } //end redirect script else { mysql_query("INSERT INTO Wish_list_guest (usercookie, date_delete, uinwish, referwish) VALUES ('$rand_wish_cookie', '$wishdate', '$uinwish', '$wishrefer')"); mysql_close($con); } if (!isset ($wishrefer)){ $host = $_SERVER['HTTP_HOST']; $uri = rtrim(dirname($_SERVER['PHP_SELF']), '/\\'); $extra = 'profile.php?uin='; header("Location: http://$host/$extra$uinwish"); exit; } else { header('Location: $wishrefer'); exit; } ?>
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Displaying MySql Results table side by side
richiejones24 replied to richiejones24's topic in PHP Coding Help
Sorry for not being more clear at the moment the script displays images like this and i need it to display images like this 8) 8) 8) 8) 8) -
need a little help guys! I use the script below to display profile images, trouble is it shows 1 on top of the other, and i need it to double up 2 profile images on top of 2 profile images ect any ideas how i can do this. require("./include/mysqldb.php"); $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); $result = mysql_query("SELECT * FROM Search_profiles_up WHERE upgrade_one ='1' ORDER BY RAND() LIMIT 40"); print "<table width=\"293\" height=\"111\" border=\"0\"> <tr>\n"; while($row = mysql_fetch_array($result)) { print "<td width=\"142\"><img src=" . $row['search_small_image'] . " width=\"144\" height=\"169\" /></td>\n"; print " </tr>\n"; print " <tr> \n"; print "<td>" . $row['star'] . "</td>\n"; print " </tr>\n"; print " <tr>\n"; print "<td>" . $row['username_search'] . "</td>\n"; print " </tr>\n"; print " <tr> \n"; print "<td>" . $row['phone_search'] . "</td>\n"; print " </tr> \n"; } print "</table>"; mysql_close($con); ?>
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I am looking to create a Wish List using cookies without using MySql and without the user having to register but i don't use cookie very often and i am not sure where to start, Any ideas or help would be appreciated?
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Its complicated but i cant do that it has to run on its own table. What exactly is complicated? The User profiles are spread over 5 tables and i use MySql Join and the username to pull all the information from the tables to make the profile. If i added the upgrade option to one of the tables all i would be able to to is get the information from that table which would be useless i need the username to get the rest of the profile from the different tables.
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Its complicated but i cant do that it has to run on its own table.
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yes that's correct but the user names of the upgraded users are in a separate table
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Thanks For the Reply! This is not exactly what i need as the original search will bring multiple results (user names) so the second search I need it to do something like this ("SELECT key FROM db2 WHERE something = '$searchKey' OR something = '$searchKey' OR something = '$searchKey' OR something = '$searchKey' ") in some kind of array ive tried using "WHILE" and "FOREACH" but i cant figure out how to do it or whether it can be done.
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Thanks for your reply's, let me clarify what i am trying to do, I have a dating site and i have added the option to upgrade your profile so it is displayed on the homepage so I have created a new MySql table with the users username and the upgrade options they have selected. so what i won't to do is search the upgrade table (SELECT * FROM upgrade WHERE upgrade_one = '1') which will give me all the user names of all the user who have upgraded, then i won't to search the user table with the username (i got from the first search) to pull there profiles of the upgraded users.
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Need some help I have 2 tables in a database and I need to search the first table and use the results from that search, to search another table, can this be done? and if it can how would you recommend that I go about it? Thanks For Your Help Guys!
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I am trying to get the code at the bottom of the script to print just once during the loop but it either doesn't print at all or repeats with the loop im am using if (!$i++) to print once and i works the first time i use it. foreach($uploadFilename as $key => $myvar) { if (!$i++) print "<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> <html xmlns=\"http://www.w3.org/1999/xhtml\"> <head> <meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" /> <title>Upload Complete....</title> </head> <body> <body onload=\"document.forms.formname.submit);\"> <form id=\"formname\" name=\"form1\" method=\"post\" action=\"reg5.php\">\n"; echo "<input type=\"hidden\" name=\"image$key\" value=\""; echo end(explode('/',$myvar)); echo "\">\n"; if (!$i++) print "</form> </body> </html>\n"; }
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I am trying to write a script to handle multiple image uploads however i cant get it to work i am a total novice in php so please be kind in your replys :-) <?php $allowed_filetypes = array('.jpg','.gif','.bmp','.png','.JPG','.PNG','.BMP','.GIF'); //These will be the types of file that will pass the validation. $upload_path = '../pic_upload/'; // The place the files will be uploaded to. foreach ($_FILES["pictures"]["error"] as $key => $error) { $filename = $_FILES['pictures']['name'][$key]; $ext = substr($filename, strpos($filename,'.'), strlen($filename)-1); if(!empty($filename)) //is it empty { if ($_FILES["pictures"]["size"][$key] >= 9000000) die ('Sorry the picture is too Big!'); } if(!empty($filename)) //Is it empty { if(!in_array($ext,$allowed_filetypes)) //Is the file Allowed die('The file you attempted to upload is not allowed! Pictures only!.'); } if ($error == UPLOAD_ERR_OK) { $tmp_name = $_FILES["pictures"]["tmp_name"][$key]; $name = $_FILES["pictures"]["name"][$key]; move_uploaded_file($tmp_name, "$upload_path/$ran$name"); if (!$i++) print "<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> <html xmlns=\"http://www.w3.org/1999/xhtml\"> <head> <meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" /> <title>Untitled Document</title> </head> <body> <div align=\"center\"><img src=\".../image/8-1.gif\" width=\"100\" height=\"100\" /></div> <form id=\"form1\" name=\"form1\" method=\"get\" action=\"reg.php\"> <div align=\"center\"> <input type=\"submit\" name=\"button\" id=\"button\" value=\"Submit\" /> <input type=\"hidden\" name=\"reg\" value=\"6\"> <p>\n"; print "<input type=\"hidden\" name=\"pic$key\" value=\"$ran$name\">\n"; if (!$i++) print "</p> <p> <label> </div> </label> </p> </form> <p> </p> </body> </html>\n"; } } ?> [code=php:0]