[Proper way of using OR with two if commands]

Shadowing

Why it is empty ?

[Proper way of using OR with two if commands]

Why empty firs body of 'if' ???

 

if (isset($_POST['escape']) || (isset($_POST['suicide']))) {
        // Why here is nothing wrote ???
} else {
    if(empty($_POST['agree'])){
            echo "You need to check the box";
    }else{
        mysql_query("DELETE FROM `users` WHERE `id`= ".(int)($_SESSION['user_id']);
    }
}

[Separating size from id+size number]

asurfaceinbetween

Show all code from your php file.

[Proper way of using OR with two if commands]

You must write as

 

if(isset($_POST['escape']) || isset($_POST['suicide'])){
    // Do something
}
else {
    // Else do something
}

[Separating size from id+size number]

Try write it outside of the 'input' element

<?php echo '<pre>' . print_r($qty, true) . '</pre>'; ?>

What will on screen ?

[URL help]

That code is saying, if there is no cookie, then set one?

Yes.

 

 

The code was for example

[URL help]

melloorr

Your code is incorrect.

 

Below, my code, it is correct

error_reporting(E_ALL);
if(isset($_COOKIE))
{
    if (isset($_COOKIE['Key_my_site']) && $_COOKIE['Key_my_site'] == $cookiedbid)
        echo "Your cookie is okay.";

    elseif (isset($_COOKIE['Key_my_site']) && $_COOKIE['Key_my_site'] !== $cookiedbid)
    {
        header("refresh:5;url=index.php" );
        echo "You have been logged out because your cookie has been compromised";
        setcookie(Key_my_site, 0, $past);
    }

    else 
        echo "Your cookie is no longer there.";
}

[URL help]

(if there was originally no cookie, then i do not get these errors, as the variable is only defined if the cookie is present)

For this, you must do this

if(!isset($_COOKIE['name']))
    set_cookie('name', 'value');
else
    // Do something with existing COOKIE

[URL help]

Thank you. It worked perfectly

But you must understand, that hiding errors, also untreated variables is very very bad !

[URL help]

At the beginning of php file, write

error_reporting(0);

 

Or just write '@' before a variable

For example

@$var;
// Or
@$_COOKIE['name'];

[Separating size from id+size number]

Hmm...

Try replace it

<input type="text" name="qty<?php echo $id; ?>" value="<?php echo print_r($qty); ?>" size="3" maxlength="3" class="view_basket_qty" />

To this

<input type="text" name="qty<?php echo $id; ?>" value="<?php echo '<pre>' . print_r($qty, true) . '</pre>'; ?>" size="3" maxlength="3" class="view_basket_qty" />

What you see on the screen ?

[Separating size from id+size number]

This is wrong

<?php echo print_r($qty) ?>

You must write just

<?php print_r($qty); ?>

Or this

<?php echo print_r($qty, true); ?>

Last two examples is same.

[When inserting allot of text into a record breaks are not showing]

Try it

<?php echo nl2br(bbcode($results['post'])); ?>

[Separating size from id+size number]

Tell me, what shows to You

print_r($qtv);
// Or
print_r($rows);

And where or what, outputs to screen the 'array' ?

[Separating size from id+size number]

Write in body of 'foreach'

print_r($qtv);

And if You wrote

while ($rows = mysql_fetch_array($result)) {

extract($row);

?>

You must replace extract($row); to extract($rows);

[Separating size from id+size number]

Try replace it

$contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1;

To that

$contents[] = (isset($contents[$item])) ? $contents[$item] + 1 : 1;

[Separating size from id+size number]

Do you mean it ?

$basket = $_SESSION['basket'];
if ($basket) {
    $data = preg_split("#[s,]#", $basket);
    $data = array_chunk($data, 2);

    foreach($data as $key => $val)
        echo 'ID ' . $val[0] . '; Size: ' . $val[1] . '<br/>';
}

[Separating size from id+size number]

$str = '1s1,12s2,16s3,28s1';
$data = preg_split("#[s,]#", $str);
$data = array_chunk($data, 2);

foreach($data as $key => $val)
    echo 'ID ' . $val[0] . '; Size: ' . $val[1] . '<br/>';

[Separating size from id+size number]

Try it

$str = '1s1,12s2,16s3,28s1';
$data = preg_split("#[s,]#", $str);
$data = array_chunk($data, 2);
echo '<pre>'.(print_r($data, 1)).'</pre>';

After, you'll get multi-array, with elements id and size

[When inserting allot of text into a record breaks are not showing]

son.of.the.morning

Show your code.

 

SergeiSS

Hello from phpforum.ru by Winston

[php PCRE URL matching pattern]

www.goog isn't a complete url

www - is correct domain name

goog - goog, too, fits the pattern.

therefore believes it is right RegExp.

If you you want correct url get, you must to enumerate a list of domains

Try it

$str = '
www.google.com
http://google.com
https://google.com
http://www.google.com
https://www.google.com
google.co.uk
www.google.co.uk
http://google.co.uk
https://google.co.uk
http://www.google.co.uk
https://www.google.co.uk
www.goo
go.ru
google.lol
';
preg_match_all("#(?:https?://)?(?:www\.)?[-a-z\d]{2,9}\.(?(1)[-a-z\d]{2,5}|(?:co|com|uk|us|ru|org|net))(\.[-a-z\d]{2,4})?#is", $str, $match);
echo '<pre>'.(print_r($match, 1)).'</pre>';

[check first 2 digits]

thanks. how would one use that  if ? : statement in this context

The ternary operator ?

Do you mean it ?

$num = '07654';
$check = substr($num, 0, 2);
echo $check == '07' ? 'OK' : 'BAD';

[check first 2 digits]

Try that

$num = '07654';
$check = substr($num, 0, 2);
if($check == '07')
    echo 'OK';
else
    echo 'BAD';

[URL help]

Use the test by 'if'.

If all is OK, do redirect

[date.timezone setting error]

Try set

date_default_timezone_set('Europe/London');

At beginning your php file.