Wedgewood85

I get it now, because it's not set it's therefore empty. I will look into isset Thanks

I get it now, it because the $img isn't being set. Thanks heaps.

No $img=... in query string but have different values: e.g. the following $img1=$row1['img1']; $imglt = $row1['img1']; $imgpr = $row1['img1']; What's interesting to note is that on my index pages all images are loaded correctly and I only get this warning on the index page.

The code is below: <?php //header ("Content-type: image/jpeg"); /* JPEG / PNG Image Resizer Parameters (passed via URL): img = path / url of jpeg or png image file percent = if this is defined, image is resized by it's value in percent (i.e. 50 to divide by 50 percent) w = image width h = image height constrain = if this is parameter is passed and w and h are set to a size value then the size of the resulting image is constrained by whichever dimension is smaller Requires the PHP GD Extension Outputs the resulting image in JPEG Format Filename : imgsize.php */ $img = $_GET['img']; $percent = $_GET['percent']; $constrain = $_GET['constrain']; $w = $_GET['w']; $h = $_GET['h']; // get image size of img $x = @getimagesize($img); // image width $sw = $x[0]; // image height $sh = $x[1]; if ($percent > 0) { // calculate resized height and width if percent is defined $percent = $percent * 0.01; $w = $sw * $percent; $h = $sh * $percent; } else { if (isset ($w) AND !isset ($h)) { // autocompute height if only width is set $h = (100 / ($sw / $w)) * .01; $h = @round ($sh * $h); } elseif (isset ($h) AND !isset ($w)) { // autocompute width if only height is set $w = (100 / ($sh / $h)) * .01; $w = @round ($sw * $w); } elseif (isset ($h) AND isset ($w) AND isset ($constrain)) { // get the smaller resulting image dimension if both height // and width are set and $constrain is also set $hx = (100 / ($sw / $w)) * .01; $hx = @round ($sh * $hx); $wx = (100 / ($sh / $h)) * .01; $wx = @round ($sw * $wx); if ($hx < $h) { $h = (100 / ($sw / $w)) * .01; $h = @round ($sh * $h); } else { $w = (100 / ($sh / $h)) * .01; $w = @round ($sw * $w); } } } $im = @ImageCreateFromJPEG ($img) or // Read JPEG Image $im = @ImageCreateFromPNG ($img) or // or PNG Image $im = @ImageCreateFromGIF ($img) or // or GIF Image $im = false; // If image is not JPEG, PNG, or GIF if (!$im) { // We get errors from PHP's ImageCreate functions... // So let's echo back the contents of the actual image. readfile ($img); } else { // Create the resized image destination $thumb = @ImageCreateTrueColor ($w, $h); // Copy from image source, resize it, and paste to image destination @ImageCopyResampled ($thumb, $im, 0, 0, 0, 0, $w, $h, $sw, $sh); // Output resized image @ImageJPEG ($thumb); } ?>

what exactly does this mean? Thanks for help. A number of times I have replaced the imgsize.php with the one from my working host. But still get this message. So should I be looking somewhere else to out work why the $img is empty?

Hi Scootstah, Thanks mate, I a little new to this. Is the $img one particular files that I need to replace?

Hi all, Yesterday I transferred my hosting to a new provider. Everything is up and running apart from the following message I get on my index page Warning: readfile() [function.readfile]: Filename cannot be empty in /home/XXXX/public_html/imgsize.php on line 64 . This error is only on the index page. When I look at line 64 it states the following: readfile ($img); I have tried replacing the imgsize.php file but that still does not work. And on my old hosting this error does not occur. If you could please help, I would appericate it. Cheers Steve