slarson22

function CHECK_VIDEO(){ error_type = 1; VIDEO_URL = document.getElementById("YOUTUBE_URL").value; VIDEO_URL_INFO = youtube_get_code.exec(VIDEO_URL); ys.loadVideoById(VIDEO_URL_INFO[1], 0, "default"); } This function will run good, then error the second run, then run good the third time, then error the fourth. So it errors everyother time. Why? Heres the error in firebug: TypeError: VIDEO_URL_INFO is null ys.loadVideoById(VIDEO_URL_INFO[1], 0, "default");