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shannont

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Everything posted by shannont

  1. Got it working. I had to move the code under where $item is defined. CASE CLOSED!
  2. I forgot to mention, when I uncomment this line: // print_r($unCountryPrice); and comment the line below instead, then it outputs the script correctly and also the variables correctly on top of the HTML page like this: Array ( [2084] => 1.00 [1903] => 2.00 ) Maybe that helps.
  3. Hello guys I'm pulling out my last remaining hairs with this PHP problem. I'm not really good at PHP but I'm trying to do some changes to a script as instructed by the developer, but apparently I got some wrong instructions. The error I get is: Fatal error: Call to a member function postage_country_display() on a non-object in file.php on line 34 I've been searching the web high and low and can't seem to find a solution. Does anyone have a hint at what might be wrong? Here is the code that's causing the problem and the class. Code: $template->set('items_id', intval($_REQUEST['items_id'])); $item_details = $db->get_sql_row("SELECT * FROM " . DB_PREFIX . "items WHERE items_id='" . intval($_REQUEST['items_id']) . "'"); $unCountryPrice = unserialize(stripslashes($db->add_special_chars($item_details['country_postage']))); // print_r($unCountryPrice); $postageCountry = $item->postage_country_display($unCountryPrice,$item_details['currency']); $template->set('postageCountry', $postageCountry); $template->set('item_details', $item_details); And here is the class: function postage_country_display($unCountryPrice,$currency) { if (is_array($unCountryPrice)) { $postageCountry = "<table border=\"0\" cellspacing=\"0\" cellpadding=\"0\"> "; $fees = new fees(); while (list($k,$v)= each($unCountryPrice)){ $cQueyr = $this->query("SELECT a.name as name1,b.name as name2 FROM " . DB_PREFIX . "countries a LEFT JOIN " . DB_PREFIX . "countries b ON (a.parent_id = b.id) WHERE a.id = '". $k ."'"); $cRow = $this->fetch_array($cQueyr); $postageCountry.="<tr><td>". ($cRow['name2']==""?$cRow['name1']:$cRow['name2'].' > '.$cRow['name1']) ."</td><td> ".$currency.' '.number_format($v,2)."</td></tr>"; } $postageCountry.="</table>"; } return $postageCountry;
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