dweb

yep i did try your example but get Notice: Undefined index: myname and Notice: Undefined variable: query

Hi the full code looks like; <?php session_start(); $usr= '1'; include 'connect/db.php'; require 'connect/config.php'; ?> <?php if($_SERVER['REQUEST_METHOD'] == "POST") { if(isset($_POST['action']) == 'update') { $name = mysql_real_escape_string($_POST['myname']); mysql_query("UPDATE `users` SET `name` = '".$name."' WHERE `id` = '".$_SESSION['idnum']."'"); echo "1 record added"; } } ?> any ideas now you can see the full code?

Hi I'm really confused by an error I keep getting, my code is; <?php if($_SERVER['REQUEST_METHOD'] == "POST") { if(isset($_POST['action']) == 'update') { $name = mysql_real_escape_string($_POST['myname']); mysql_query("UPDATE `users` SET `name` = '".$name."' WHERE `id` = '".$_SESSION['idnum']."'"); echo "1 record added"; } } ?> it all works ok and records are updated, but when the form is submitted I keep getting the error Notice: Undefined index: myname in e:\www\site\info.php on line 12 I've looked around online but all the solutions i've tried have failed any suggestions? thanks

thanks, i've read the page but could you give me a simple example of how to extract and display it? i've looked around and finding it hard to find something straight forward and now banging my head against the wall thanks

Hi I wonder f you can help as i've been racking my brain all night and cannot find a solution I have the following JSON in a file { "user1": 'David', "user2": 'Julie', "user3": 'John' } and I output it with $.getJSON("files/json.txt", function(data) { var items = []; $.each(data, function(key, val) { items.push('<li>' + key + '<br>' + val + '</li>'); }); $('<ul/>', { 'class': 'my-new-list', html: items.join('') }).appendTo("#"+divname); }); all works fine, but I need to extend the JSON so that it looks like the following { "id": "14373", "name": 'David', "age": '25', "gender": 'm', "id": "14373", "name": 'Julie', "age": '31', "gender": 'f', "id": "65643", "name": 'John', "age": '42', "gender": 'm' } and then output it as something like; $.each(data, function(id_val, name_val, age_val, gender_val) { items.push('<li>' + id_val + '<br>' + name_val + '<br>' + age_val + '<br>' + gender_val + '</li>'); }); is this possible and if so, how can it be done as im really struggling to find a way thanks everyone

any idea?

Hi I have written a very simple online email script, which reads my mailbox and lists all emails in it. To do so i'm using imap_open() everything is working fine to output the body text of an email i'm using $bodytxt = imap_fetchbody($mbox, 100, "1"); echo $bodytxt; which correctly outputs the email text, apart from retaining of line breaks. so I applied echo nl2br($bodytxt); and line breaks were successfully added, but for some reason it is creating random line breaks at points where one didn't exist in the email. if I try sending an email which has no line breaks, such as then when I view that via my php script, it outputs and this happens if the email is sent as HTML or as Plain text any idea what could be going on? thanks

any idea why I might be getting that error?

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ok, sorry, misunderstood trying mkdir('uploads'); gives the error Warning: mkdir(uploads) [function.mkdir]: Permission denied

ok thanks, i'll give that a go is that solution practical when you might have 000's of files in the uploads folder, surely it's going to have some serious pressure on the server if uploads are constantly being done and it's being required to shift 000's of files also, what would you suggest if you have multiple users uploading files, surely if folders are being renamed, files being moved etc, then files are going to go missing. Or would it be the case of having 1 folder per user in the root?

the only problem is that the folder contains many files and it's the main folder for all the uploads, so it would mean I would have to copy hundreds of files each time someone uploads a new file basically all I need to do, is make a secure way of uploading a file to a folder, but from what I can see it looks like the only option is to create a new folder in the root each time my goal is just to have a script which files can be uploaded to a defined folder location, but the folder is secured with permissions to stop outsiders uploading anything such as scripts \ viruses etc any suggestions would be great

so if I already have a folder called "uploads", then surely I wouldn't run mkdir('uploads'); because the folder exists. but when I try and CHMOD that folder with chmod('uploads', 0755); then I get Warning: chmod() [function.chmod]: Operation not permitted in /home/web101/public_html/myadmin/upload.php on line 4

the problem is, the "uploads" folder is where I currently store and want to upload files to

thanks, so how can I set that?

Thanks, i'm going to use option 3 I have tried the code chmod("../files/", 0777); but I get the error Why would that be?

Hi I've got a file upload script i've written and I have set the folder to 777 to allow uploads With the permission set to 777 does this open me up to potential uploads from 3rd parties? (ie: viruses etc)? So I thought what I would do is 1: Set folder to 777 to allow uploads 2: Upload file 3: Set folder to 755 to disable uploads Would this be the best method to do it? Or is that a waste of time and am I safe just leaving it as 777 Thanks

ok, gulp, maybe not as easy as I thought any suggestions on a good php image crop tool like that example?

Hi I'm really new to php and could really do with some help. I am using the following script http://test.dpetroff.ru/jquery.iviewer.test/test/ which basically allows me to position an image within a DIV area My question is, how can I get PHP to save just the image within the DIV area, so it's almost acting like a crop tool I've tried a few things but so far not managed to get anything working

Hi Im working if someone can help me. I have a small form on my website which saves the data to a sql database. It seems like someone has been spamming it I need to write a query or script to try and pickup these spam entries, can someone advise me They seem to have used the format {letter} {word} {6digit number} {@ domain} for example [email protected] [email protected] [email protected] I believe these are spams as I have around 15,000 entries in this exact format I have since added something to stop these spammers, but I want to clean up all the old spam entries Thanks very much Dave

Thank you, worked great

Hello Wonder if you can help; I have an issue with sessions, I have stripped out a ton of code to give a more simple example below; Basically when I click the "Button 1" link, it should just display "Clicked button 1" and when I click the "Button 2" link, it should just display "Clicked button 2" But for some reason it's displaying "Clicked button 1" and "Clicked button 2" no matter what Any idea why? Thank you <?php session_start(); if(isset($_GET['1'])) { $_SESSION['result'] = 1; } if(isset($_GET['2'])) { $_SESSION['result'] = 2; } ?> <?php if(isset($_SESSION['result']) == 1) { echo "Clicked button 1<br>"; } ?> <a href="?1">Button 1</a> <br /> <br /> <?php if(isset($_SESSION['result']) == 2) { echo "Clicked button 2<br>"; } ?> <a href="?2">Button 2</a> <?php unset($_SESSION['result']); ?>