Jump to content

weboz

New Members
  • Posts

    3
  • Joined

  • Last visited

    Never

Everything posted by weboz

  1. Yeah i know, looks like i skipped a line when i copied the code snip. As for better information, i do not have any more information, because the system provider for this system will not let me see more of the codes. So this is what i have to work with. Going to insert a drop-out menu, and for this i need <ul> to be printet correctly. {foreach $categories_array as $category} {if $category.spacing == '1'} <li class="cat1 {$class}" style="margin-left:10px;"><a href="{$category.href}">{$category.name}</a></li> {elseif $category.spacing == '2'} <li class="cat2 {$class}" style="margin-left:{0+$category.spacing*10}px;" ><a href="{$category.href}">{$category.name}</a></li> {else} <li class="cat0-sub {$class}" style="margin-left:{0+$category.spacing*10}px;" ><a href="{$category.href}">{$category.name}</a></li> {/if} {/foreach}
  2. I'm pretty sure this will loop. Need to find a method to stop <ul> from looping for each <li>.
  3. Hallo, i'm desperate.. I have tried 5 forums without anyone to answer me, so trying this as last tryout Please read the note in the code <!-- -->, need to echo <ul> without looping. Need help with this code: {foreach $categories_array as $category} <!-- need a code to print <ul class="cat1" without looping--> <li class="cat1 {$class}" style="margin-left:10px;"><a href="{$category.href}">{$category.name}</a></li> {elseif $category.spacing == '2'} <!-- need a code to print<ul class="ul-cat2" without looping --> <li class="cat2 {$class}" style="margin-left:{0+$category.spacing*10}px;" ><a href="{$category.href}">{$category.name}</a></li> {else} <li class="cat0-sub {$class}" style="margin-left:{0+$category.spacing*10}px;" ><a href="{$category.href}">{$category.name}</a></li> {/if} {/foreach}
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.