uppalakishore
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Everything posted by uppalakishore
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I want to display the image when i use the tag <img src="image.php?f=f3.jpg" alt="Image" /> Any help Wil be Appreciable...
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Thank u @ trq and l0gic... But i slightly confused... I found a link http://michael.theirwinfamily.net/articles/csshtml/protecting-images-using-php-and-htaccess I added the following .ht access files to Image directory and to main directory .htaccess in main folder: RewriteEngine on RewriteCond %{HTTP_REFERER} ^$ RewriteCond %{SCRIPT_FILENAME} image\.php RewriteRule (.*) image.php?onlyHappensFromHTACCESS=denied [QSA,L] .htaccess in Images folder: #Prevent directory listing Options -Indexes #Prevent images from being viewed <Files *> deny from all </Files> image.php: <?php if (!isset($_GET['onlyHappensFromHTACCESS'])) { $_GET['f'] = "./Images/" . $_GET['f']; //my folder name="Images"; $type = getFileType($_GET['f']); if (acceptableType($type)) { if (goodTiming()) { header("Content-type: $type"); echo file_get_contents($_GET['f']); exit; } } header('HTTP/1.1 403 Forbidden'); exit; } function getFileType($file) { if (function_exists("mime_content_type")) return mime_content_type($file); else if (function_exists("finfo_open")) { $finfo = finfo_open(FILEINFO_MIME_TYPE); $type = finfo_file($finfo, $file); finfo_close($finfo); return $type; } else { $types = array( 'jpg' => 'image/jpeg', 'jpeg' => 'image/jpeg', 'png' => 'image/png', 'gif' => 'image/gif', 'bmp' => 'image/bmp' ); $ext = substr($file, strrpos($file, '.') + 1); if (key_exists($ext, $types)) return $types[$ext]; return "unknown"; } } function acceptableType($type) { $array = array("image/jpeg", "image/jpg", "image/png", "image/png", "image/gif"); if (in_array($type, $array)) return true; return false; } function goodTiming() { $n = time(); session_start(); if ($n - $_SESSION['lastcheck'] > 2 ) return false; return true; } ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <html> <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <title>Image Denied</title> <style type="text/css" media="screen"> body { background-color: #ccc; font-family: Helvetica, Arial; } #wrapper { margin: 30px auto; background-color: #ffffff; -moz-border-radius: 15px; -webkit-border-radius: 15px; border-radius: 15px; width: 800px; padding: 20px; } </style> </head> <div id="wrapper"> <h3>Access Denied!</h3> You have tried to access an image, but due to security reasons, you cannot view the image. If you wish to use the image you requested, please contact me. </div> </html> index1.php: <?php session_start(); $_SESSION['lastcheck'] = time(); ?> <html> <head> <title>Page Title</title> <style type="text/css"> .image { overflow: hidden; position: relative; float: left; } .image .cover, .image .cover img { position: absolute; top: 0px; left: 0px; width: 100%; height: 100%; } </style> </head> <body> <div class="image"> <img src="image.php?f=f3.jpg" alt="Image" /> <div class="cover"><img src="Transparent.gif" alt="" /></div> </div> </body> </html> I got the output as "Image"(Means alt will be loaded)... when i right click on it,and select View Image "Transparent.gif" will be displaying normally. I can't understant what is the problem here...
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The above code is working fine in case of a particular image like freak_test.php?image=f3.jpg (The code is saved in a page "freak_test.php") In case of, <img src="freak_test.php?image=f3.jpg" width=200 height=300 /> It will not displaying the image And when Right click on the image and click "View Image" it displays the following error Deprecated: Function eregi() is deprecated in F:\xampp\htdocs\photo_gallery\User_data\User_details\freak_test.php any Suggestions?
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@ haku.... I tried and rename the directory as "Images" but i found it displaying the image path as it is and it will randomize the images in the directory when i refresh the page... What i want is I want to hide the location/path of the image... sum where i got some code i will try it... <?php $imagedir = "Images/" ; $validprefixes = array ( "http://localhost/photo_gallery/index.com", "localhost/photo_gallery/" ) ; $homepage = "index.php" ; function isreferrerokay ( $referrer, $validprefixes ) { $validreferrer = 0 ; $authreferrer = current( $validprefixes ); while ($authreferrer) { if (eregi( "^https?://$authreferrer/", $referrer )) { $validreferrer = 1 ; break ; } $authreferrer = next( $validprefixes ); } return $validreferrer ; } //----------------------- main program ----------------------- $image = $_GET['image'] ; $referrer = getenv( "HTTP_REFERER" ); if (isset($_GET['image'])) { if (empty($referrer) || isreferrerokay( $referrer, $validprefixes )) { $imagepath = $imagedir . $image ; $imageinfo = getimagesize( $imagepath ); if ($imageinfo[2] == 1) { $imagetype = "gif" ; } elseif ($imageinfo[2] == 2) { $imagetype = "jpeg" ; } elseif ($imageinfo[2] == 3) { $imagetype = "png" ; } else { header( "HTTP/1.0 404 Not Found" ); exit ; } header( "Content-type: image/$imagetype" ); @readfile( $imagepath ); } else { if (isset($email)) { mail( $email, "Bandwidth Theft Alert", "WARNING:\n\n$referrer\ntried to access\n$image\n", "From: CHImageGuard <$email>" ); } header( "HTTP/1.0 404 Not Found" ); } } else { header( "Location: $homepage" ); } ?>
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Thank u @ haku.... I will try....
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First of All Thanks For Reading... I Want to hide Image/File path, mainly i want to hide the "image path" there by Logged in users only see the images. 1) My Problem is When a user Logged in and opend his personal photos, the image path will be "http://localhost/photo_gallery/User_data/Personal_photos/username/kicku.jpg" . 2)But when i entered the path in the browser without login the images keep displaying... 3)So i want to hide the image path for security purpose... Any help, Appreciable...
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Thanks For ur Reply @ Christian F... I Solved it...as follows: $mail=new PHPMailer(); $mail->IsSMTP(); //Important b'coz by this stmt we sent mail using smtp $mail->SMTPAuth = true; // enable SMTP authentication $mail->SMTPSecure = "ssl"; // sets the prefix to the servier $mail->Host = "smtp.gmail.com"; // sets GMAIL as the SMTP server $mail->Port = 465; // set the SMTP port for the GMAIL server $mail->Username = "yourmail@gmail.com"; // GMAIL username $mail->Password = "your mail password"; // GMAIL password $mail->FromName = "PhotoGallery:Admin"; $mail->From = "from address@gmail.com"; $mail->AddAddress($to,$to_name); $mail->Subject = $subject; $mail->Body ="body of the message"; $result=$mail->Send(); return $result;
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When i run the following code,it will shows the error... Mail error: The following From address failed: uppalakishore@hotmail.com : Called Mail() without being connected <?php require_once("./Includes/PHPMailer/class.phpmailer.php"); // require_once("./Includes/PHPMailer/class.smtp.php"); define('GUSER', 'myname@gmail.com'); // GMail username define('GPWD', 'mypassword'); // GMail password function smtpmailer($to, $from, $from_name, $subject, $body) { global $error; $mail = new PHPMailer(); // create a new object $mail->IsSMTP(); // enable SMTP $mail->SMTPDebug = 0; // debugging: 1 = errors and messages, 2 = messages only $mail->SMTPAuth = true; // authentication enabled $mail->SMTPSecure = 'ssl'; // secure transfer enabled REQUIRED for GMail $mail->Host = 'smtp.gmail.com'; $mail->Port = 465; $mail->Username = GUSER; $mail->Password = GPWD; $mail->SetFrom($from, $from_name); $mail->Subject = $subject; $mail->Body = $body; $mail->AddAddress($to); if(!$mail->Send()) { $error = 'Mail error: '.$mail->ErrorInfo; return false; } else { $error = 'Message sent!'; return true; } } if (smtpmailer('myname@gmail.com', 'uppalakishore@hotmail.com', 'PHotoGallery', 'test mail message', 'Hello World!')) { // do something } if (!empty($error)) echo $error; ?> Thanks in Advance For Watching...
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Insert & Retrieve data into/from MySql using sockets
uppalakishore replied to uppalakishore's topic in PHP Coding Help
OK Thanks... I Will Start Learning... -
Insert & Retrieve data into/from MySql using sockets
uppalakishore replied to uppalakishore's topic in PHP Coding Help
Thank You Christian F... I had simple client and server socket programs, the client sends a message to server, then the server reverses the string(sent by client) and send it to server. Client.php [bR] <?php $host = "127.0.0.1"; $port = 80; [color=#ff0000][b]$message ="Hello world";[/b][/color] echo "<br>\nMessage To server :".$message."\n"; // create socket $socket = socket_create(AF_INET, SOCK_STREAM, 0) or die("Could not create socket\n"); if($socket)echo "<br>Client Socket Created\n"; // //// connect to server $result = socket_connect($socket, $host, $port) or die("Could not connect to server\n"); if($result)echo "<br>Socket Connected to Server : $host on Port : $port\n"; // //while(1){ // send string to server echo "<br>Sending Data to the Server...\n"; sleep(1); socket_write($socket, $message, strlen($message)) or die("Could not send data to server\n"); // // get server response echo "<br>Getting Responce From the Server...\n"; sleep(1); $result = socket_read ($socket, 1024) or die("Could //not read server response\n"); echo "Reply From Server :".$result; //} // close socket socket_close($socket); ?> Server.php [bR] <?php // set some variables $host = "127.0.0.1"; $port = 80; // don't timeout! set_time_limit(0); // create socket $socket = socket_create(AF_INET, SOCK_STREAM, 0) or die("Could not create socket\n"); if($socket)echo "<br>Socket Created\n"; // bind socket to port $result = socket_bind($socket, $host, $port) or die("Could not bind to socket\n"); if($result)echo "<br>Socket Binded\n"; // start listening for connections $result = socket_listen($socket, 3) or die("Could not set up socket listener\n"); if($result)echo "<br>Socket Listening Connections....\n"; // accept incoming connections // spawn another socket to handle communication $spawn = socket_accept($socket) or die("Could not accept incoming connection\n"); if($spawn)echo "<br>Socket Accepted Incoming Connections...\n"; //while(1){ // read client input echo "<br>\nReading Input...\n"; sleep(1); $input = socket_read($spawn, 2048) or die("Could not read input\n"); // clean up input string $input = trim($input); echo "<br>Client Message : ".$input; // reverse client input and send back $output = strrev($input) . "\n"; echo "<br>\nResponce...\n"; sleep(1); socket_write($spawn, $output, strlen ($output)) or die("Could not write output\n"); //} // close sockets socket_close($spawn); socket_close($socket); ?> The program is executed, the problem is i want to enter that message into database using server program...I can't get any idea how to do that... Thanks in Advance... -
Insert & Retrieve data into/from MySql using sockets
uppalakishore replied to uppalakishore's topic in PHP Coding Help
Thank you @Christian F. for your responce... The person is my Teacher...even i told the complexity u explained here to him...he didn't convinced... any way Thanks For your Preceious Responce... -
Insert & Retrieve data into/from MySql using sockets
uppalakishore replied to uppalakishore's topic in PHP Coding Help
Thanq @trq for your responce... But i need Socket programming in php that will enter the Form Field Values(entered Values) into database... Means as follows: $val=$_GET['name']; Then how can i enter '$val' value into database using socket,that is my problem... anyway THANKS... -
Insert & Retrieve data into/from MySql using sockets
uppalakishore replied to uppalakishore's topic in PHP Coding Help
ofcourse @trq... but somebody asked insert and retrieve data by using sockets.....that's why... -
Insert & Retrieve data into/from MySql using sockets
uppalakishore posted a topic in PHP Coding Help
Suppose i had a Registration Form with multiple fileds(like first name,last name etc).And i want to enter the entered values into MySql using Sockets... I need the example showing inserting data into Mysql using sockets.Bcoz i learned something about php sockets but i don't have the basic idea how to implement them...Even i tried so many examples but i tired of having so many complexities like socket_bind,socket_accept,socket_listen errors... THANKS IN ADVANCE... -
PHP Pagination Error while using "Where" clause
uppalakishore replied to uppalakishore's topic in Third Party Scripts
CTRL + Q to Enable/Disable GoPhoto.it I think, the Problem might be here: session_start(); if (isset($_POST['disciplines'])) $_SESSION['dis']=$_POST['disciplines']; [code] <html> <body> <a href="home.php" align="left" style="text-decoration:none;font:verdana;color:red;padding: 5px;margin-left:40px;"><button class="btn" onclick="javascript:location.href='home.php'" class="btn" style="font-weight: bold;">Home Page</button></a> <button class="btn" onclick="history.go(-1);return true;">Go Back</button> <?php // // Make sure that PATH_INFO is set, and not ORIG_PATH_INFO as some hosts seem to use. // if (isset ($_SERVER['ORIG_PATH_INFO']) && $_SERVER['ORIG_PATH_INFO'] != $_SERVER['PHP_SELF']) { // $_SERVER['PATH_INFO'] = $_SERVER['ORIG_PATH_INFO']; // } // // // Security measure, to avoid XSS exploit. // if (!empty ($_SERVER['PATH_INFO']) && strrpos ($_SERVER['PHP_SELF'], $_SERVER['PATH_INFO'])) { // // // // $_SERVER['PHP_SELF'] = substr ($_SERVER['PHP_SELF'], 0, -(strlen ($_SERVER['PATH_INFO']))); // } session_start(); if (isset($_POST['disciplines'])) $_SESSION['dis']=$_POST['disciplines']; include('db_connect.php'); // how many rows to show per page $rowsPerPage = 4; // by default we show first page $pageNum = 1; // if $_GET['page'] defined, use it as page number if(isset($_GET['page'])) { $pageNum = $_GET['page']; } // counting the offset,example we want 5 rows per page,offset=(1-1)*5=0(means 0 to 5 rows on first page,(2-1)*5=5(5 to 5 on second page) $offset = ($pageNum - 1) * $rowsPerPage; $result=mysql_query("select * from student_master where Disciplines='" . mysql_real_escape_string($_SESSION['dis']) . "' LIMIT $offset,$rowsPerPage") or die('Error : '. mysql_error()); $result2=mysql_query("select count(*) from student_master where Disciplines='".mysql_real_escape_string($_SESSION['dis'])."'"); echo "<table align='right'><tr><td><fieldset border='1' class='fieldmoz'>Total ".mysql_real_escape_string($_SESSION['dis'])." Students = <font color='red' ><b>".mysql_result($result2,0)."</fieldset></b></font></td></tr></table> <center><h2 align='center' class='spl_heading'><font color=green>".mysql_real_escape_string($_SESSION['dis'])."</font> Students Details : </h2></center> <table width='70%' cellpadding='2' cellspacing='2' border='1' align='center'> <tr class='fade_bg' align='center'> <td class='spl_bgcolor'>Enrollment No</td> <td>Name</td> <td>Discipline</td> <td>Year</td> <td>Photo</td> </tr>"; while($row=mysql_fetch_row($result)) { echo " <tr class='sp_table_row'> <td class='span' width='16%' align='center'><a class='underline' href='all_click_details.php?En_no=$row[0]'>$row[0]</a></td> <td width='20%'>$row[1]</td> <td align='center' width='10%'>$row[4]</td> <td width='10%' align='center'>$row[7]</td> <td width='6%' align='center'><img src='upload/$row[9]' alt='$row[1]' title='$row[1]' align='center' style='-moz-border-radius:4px;' class='magnify' data-magnifyduration='800' width='90' height='110'></td> </tr>"; } echo "<tfoot><tr><td colspan=10><marquee behavior='alternate' scrollamount='3' align='center' class='yellow'>Click on Image to Enlarge & Resize</marquee></td></tr></tfoot> </table><br> "; // how many rows we have in database $result1=mysql_query("select count(Disciplines) from student_master where Disciplines='".mysql_real_escape_string($_SESSION['dis'])."'"); $row=mysql_fetch_row($result1); $numrows=$row[0]; // how many pages we have when using paging? $maxPage = ceil($numrows/$rowsPerPage); // print the link to access each page $self = $_SERVER['PHP_SELF']; $nav = ''; for($page = 1; $page <= $maxPage; $page++) { if ($page == $pageNum) { $nav .= " <span class='bgc'><b> $page </span> |</b>"; // no need to create a link to current page } else { $nav .= " <a href=\"$self?page=$page\">$page</a> <b>|</b>"; } } // ... still more code coming if ($pageNum > 1) { $page = $pageNum - 1; $prev = " <a href=\"$self?page=$page\">[Prev]</a> <b>|</b>"; $first = " <a href=\"$self?page=1\">[First Page]</a>"; } else { $prev = ' '; // we're on page one, don't print previous link $first = ' '; // nor the first page link } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " <a href=\"$self?page=$page\">[Next]</a> <b>|</b>"; $last = " <a href=\"$self?page=$maxPage\">[Last Page]</a>"; } else { $next = ' '; // we're on the last page, don't print next link $last = ' '; // nor the last page link } // print the navigation link echo "<div class='pager'><center>".$first . $prev . $nav . $next . $last."</center></div>"; echo "<center><br><button onclick='javascript:window.print()' value=''class='btn' style='width:100;height:25;'>Print</button></center>"; // and close the database connection mysql_close(); ?> </body> </html> When i run the above code it will give correct results in one system,when i run it on my laptop it won't produce the same result....i think there might be an error in passing SESSION VARIABLES to the next page.(B'Coz when i click on next page it will display empty page with table headers ony... I can't understand whether it is coding problem or my Laptop OS Problem(b'coz it will run correctly on other system).... -
PHP Pagination Error while using "Where" clause
uppalakishore replied to uppalakishore's topic in Third Party Scripts
I tried the following code by applying SESSION (Some times working properly) but i got the Error,Means it will executed in one system and it won't work in other system session_start(); if (isset($_POST['disciplines'])) $_SESSION['dis']=$_POST['disciplines']; include('db_connect.php'); $rowsPerPage =4; // by default we show first page $pageNum = 1; // if $_GET['page'] defined, use it as page number if(isset($_GET['page'])) { $pageNum = $_GET['page']; } // counting the offset $offset = ($pageNum - 1) * $rowsPerPage; $result=mysql_query("select * from student_master where Disciplines='" . mysql_real_escape_string($_SESSION['dis']) . "' LIMIT $offset,$rowsPerPage"); if(mysql_num_rows($result)>0) { echo " ".mysql_real_escape_string($_SESSION['dis'])." Students Details : "; while($row=mysql_fetch_row($result)) { echo " "; } echo " Enrollment No Name Father's Nname Address Discipline Semester Year Email Mobile Number Photo $row[0] $row[1] $row[2] $row[3] $row[4] $row[5] $row[7] $row[6] $row[8] Upload Image Click on Image to Enlarge & Resize "; // how many rows we have in database $query = "SELECT COUNT(En_no) AS numrows FROM student_master where Disciplines='".mysql_real_escape_string($_SESSION['dis'])."'"; $result1 = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result1, MYSQL_ASSOC); $numrows = $row['numrows']; // how many pages we have when using paging? $maxPage = ceil($numrows/$rowsPerPage); // print the link to access each page $self = $_SERVER['PHP_SELF']; $nav = ''; for($page = 1; $page <= $maxPage; $page++) { if ($page == $pageNum) { $nav .= " $page "; // no need to create a link to current page } else { $nav .= " $page "; } } // ... still more code coming if ($pageNum > 1) { $page = $pageNum - 1; $prev = " [Prev] "; $first = " [First Page]"; } else { $prev = ' '; // we're on page one, don't print previous link $first = ' '; // nor the first page link } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " [Next] "; $last = " [Last Page]"; } else { $next = ' '; // we're on the last page, don't print next link $last = ' '; // nor the last page link } // print the navigation link echo " ".$first . $prev . $nav . $next . $last." "; echo " To search again,Click here . . . "; } else { echo " Error Occured. Try Again . . . "; } ?> When i Run the above code i got that the error was in the following line.... "select * from student_master where Disciplines='" . mysql_real_escape_string($_SESSION['dis']) . "' LIMIT $offset,$rowsPerPage" And Thanks In Advance... -
PHP Pagination Error while using "Where" clause
uppalakishore replied to uppalakishore's topic in Third Party Scripts
I'm sory to say this...i don't know how to avoid $_SERVER['PHP_SELF'],and it is linked with Overall pages..... // print the link to access each page $self = $_SERVER['PHP_SELF']; $nav = ''; for($page = 1; $page <= $maxPage; $page++) { if ($page == $pageNum) { $nav .= " <span class='bgc'><b> $page </b></span> "; // no need to create a link to current page } else { $nav .= " <a href=\"$self?page=$page\">$page</a> "; } } // ... still more code coming if ($pageNum > 1) { $page = $pageNum - 1; $prev = " <a href=\"$self?page=$page\">[Prev]</a> "; $first = " <a href=\"$self?page=1\">[First Page]</a>"; } else { $prev = ' '; // we're on page one, don't print previous link $first = ' '; // nor the first page link } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " <a href=\"$self?page=$page\">[Next]</a> "; $last = " <a href=\"$self?page=$maxPage\">[Last Page]</a>"; } else { $next = ' '; // we're on the last page, don't print next link $last = ' '; // nor the last page link } // print the navigation link echo "<div class='pager'><center>".$first . $prev . $nav . $next . $last."</center></div>"; Will Please tell me how to do it......There by pagination will work fine......////////First page works fine but when i click on next page nothing will come..... when i use session_start(), it shows error headers already sent... Thanks For Your Reply.... -
PHP Pagination Error while using "Where" clause
uppalakishore replied to uppalakishore's topic in Third Party Scripts
Actually i'm New here... And i think the error might be here(following): ////////////// Main Query to get Students belongs to a Particular Department(discipline) ///////// $dis=$_POST['disciplines']; @session_start(); $_SESSION['dis']=$_POST['disciplines']; $result=mysql_query("select * from student_master where Disciplines='".$_SESSION['dis']."' LIMIT $offset,$rowsPerPage"); if(mysql_num_rows($result)>0) { //print some table headings while($row=mysql_fetch_row($result)) { //print some table rows } // how many rows we have in database to print for PAGINATION include('db_connect.php'); //to establish database connection $query = "select COUNT(Disciplines) AS numrows FROM student_master where Disciplines='".$_SESSION['dis']."'"; $result2 = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result2,MYSQL_ASSOC); $numrows = $row['numrows']; //place some pagination links } else { echo "Error Occurd" } When i run the program first page working fine...when i click on next page it will show msg "Error Occurd"(which is showd in blue color as a else stmt)...i think it may be a session variable problem but i don't know how to rectify it... THANKS FOR UR REPLY -
I want to display 4 records per page by using pagination on clicking "showdetails2.php"...Everything will be working fine but when i click on next page...it shows error..... Simply what i want is i want to display 4 records per page(menas 4 students of each department) /////////////////////////////////////////////// <?php include('db_connect.php'); $rowsPerPage =4; // by default we show first page $pageNum = 1; // if $_GET['page'] defined, use it as page number if(isset($_GET['page'])) { $pageNum = $_GET['page']; } // counting the offset $offset = ($pageNum - 1) * $rowsPerPage; @session_start(); $_SESSION['dis']=$_POST['disciplines']; $result=mysql_query("select * from student_master where Disciplines='".$_SESSION['dis']."' LIMIT $offset,$rowsPerPage "); if(mysql_num_rows($result)>0) { echo " <h2 align='center' class='spl_heading'><font color=green>".$_SESSION['dis']."</font> Students Details : </h2> <table width='98%' cellpadding='2' cellspacing='2' border='1' align='center'> <tr class='fade_bg' align='center'> <td class='spl_bgcolor'>Enrollment No</td> <td>Name</td> <td>Father's Nname</td> <td>Address</td> <td>Discipline</td> <td>Semester</td> <td>Year</td> <td>Email</td> <td>Mobile Number</td> <td>Photo</td></tr>"; while($row=mysql_fetch_row($result)) { echo " <tr class='sp_table_row'> <td class='spl_bgcolor'style='color:fcc;' width='16%' align='center'>$row[0]</td> <td width='30%'>$row[1]</td> <td width='25%'>$row[2]</td> <td width='25%'>$row[3]</td> <td width='10%'>$row[4]</td> <td width='15%'>$row[5]</td> <td width='10%'>$row[7]</td> <td width='35%'>$row[6]</td> <td width='20%'>$row[8]</td> <td><img src='upload/$row[9]' alt='Upload Image' align='center' style='-moz-border-radius:4px;' class='magnify' data-magnifyduration='800' width=80 height=110></td> </tr>"; } echo "<tfoot><tr><td colspan=10><marquee behavior='alternate' scrollamount='3' class='yellow'>Click on Image to Enlarge & Resize</marquee></td></tr></tfoot> </table><br> "; // how many rows we have in database $query = "SELECT COUNT(En_no) AS numrows FROM student_master where Disciplines='".$_SESSION['dis']."'"; $result1 = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result1, MYSQL_ASSOC); $numrows = $row['numrows']; // how many pages we have when using paging? $maxPage = ceil($numrows/$rowsPerPage); // print the link to access each page $self = $_SERVER['PHP_SELF']; $nav = ''; for($page = 1; $page <= $maxPage; $page++) { if ($page == $pageNum) { $nav .= " <span class='bgc'><b> $page </b></span> "; // no need to create a link to current page } else { $nav .= " <a href=\"$self?page=$page\">$page</a> "; } } // ... still more code coming if ($pageNum > 1) { $page = $pageNum - 1; $prev = " <a href=\"$self?page=$page\">[Prev]</a> "; $first = " <a href=\"$self?page=1\">[First Page]</a>"; } else { $prev = ' '; // we're on page one, don't print previous link $first = ' '; // nor the first page link } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " <a href=\"$self?page=$page\">[Next]</a> "; $last = " <a href=\"$self?page=$maxPage\">[Last Page]</a>"; } else { $next = ' '; // we're on the last page, don't print next link $last = ' '; // nor the last page link } // print the navigation link echo "<div class='pager'><center>".$first . $prev . $nav . $next . $last."</center></div>"; echo "<center>To search again,Click <a href='search_decipline.php' class='btn'><blink><b>here</b></blink></a> . . .</center>"; } else { echo "<br><center>Error Occured. <a href='search_decipline.php' class='btn'><blink>Try Again</blink></a> . . . </center>"; } ?> Solve it For me And THANKS IN ADVANCE .... 19038_.php 19039_.php