StevenJacobs

sure. well i used ur original code matched with love2code and its working nice. if i add the section you gave me with the echo it doesnt work, but this is what it gives me: SELECT `EMAIL` FROM `subscribers` WHERE `EMAIL` = ''art.stevenjacobs@yahoo.com''

Nevermind! i solved it buy doing what you said in your edit, heres what worked: $Result1 = mysql_query($insertSQL,$subscribers); $insert = mysql_affected_rows(); if(!$Result1) { echo "Username and/or password already in use."; } else { echo "You have successfully registered."; } Its working perfectly now! Again thank you everybody! i cant thank you enough for all the help!

yea i just tried it, unless if im doing something wrong it is not working. Its now giving this error if i type in a new email or a email already in the database. Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/steven/public_html/testing.php on line 63 Username and/or password already in use. Line 63 would be this part of the code you gave me: $rows = mysql_num_rows($Result1);

yeah no problem.. i used one of the first codes that jazzman gave me. and its working like a charm now. <?php include ('Connections/subscribers.php'); date_default_timezone_set('America/Chicago'); if (isset($_POST['Submit'])) { if ($_POST['email'] != "") { $email = filter_var($_POST['email'], FILTER_SANITIZE_EMAIL); if (!filter_var($email, FILTER_VALIDATE_EMAIL)) { $errors = "$email is <strong>NOT</strong> a valid email address.<br/><br/>"; } } else { $errors .= 'Please enter your email address.<br/>'; } if (isset($errors)) { echo '<div style="color: red">' . $errors . '<br/></div>'; return false; } if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) { $insertSQL = sprintf("INSERT INTO subscribers (EMAIL) VALUES (%s)", GetSQLValueString($_POST['email'], "text")); mysql_select_db($database_subscribers, $subscribers); $Result1 = mysql_query($insertSQL, $subscribers) or die(mysql_error()); } } else { ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" name="form1" method="POST"> Email Address: <br/> <input type="text" name="email" value="<?php echo $_POST['email']; ?>" size="50"/> <br/><br/> <input type="submit" name="Submit" /> <input type="hidden" name="MM_insert" value="form1" /> </form> <?php } ?>

awesome! that worked!.. lol i feel so stupid, that was very simple.. one question tho, how do i change the message that comes up? its saying: Duplicate entry 'art.stevenacobs@yahoo.com' for key 'EMAIL' Thank everybody again for all the help, i really appreciate it!

ok well when i comment that section it stops giving any errors. it also enters valid emails into the database now, but back to the problem, it allows same emails to keep being entered.

I used his last one (reply #17) modified with reply # 27

Still no luck, didnt change anything.. just saw your edit a few replys ago. not sure what you mean by what action im getting. but after i hit submit, its going to a blank page with the following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'art.stevenacobs@yahoo.com'')' at line 1

Ok i just saw it, but im not to sure what exactly your saying i should change.

Sure. <?php include ('Connections/subscribers.php'); date_default_timezone_set('America/Chicago'); if (isset($_POST['Submit'])) { if ($_POST['email'] != "") { $email = filter_var($_POST['email'], FILTER_SANITIZE_EMAIL); if (!filter_var($email, FILTER_VALIDATE_EMAIL)) { $errors = "$email is <strong>NOT</strong> a valid email address.<br/><br/>"; } } else { $errors .= 'Please enter your email address.<br/>'; } if (isset($errors)) { echo '<div style="color: red">' . $errors . '<br/></div>'; return false; } if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) { mysql_select_db($database_subscribers, $subscribers); $check_email = sprintf("SELECT `EMAIL` FROM `subscribers` WHERE `EMAIL` = '%s'", GetSQLValueString($_POST['email'], "text")); $result = mysql_query($check_email, $subscribers) or die(mysql_error()); if(mysql_num_rows($result) > 0) { echo 'Sorry, but this email has beed already taken'; return false; } $insertSQL = sprintf("INSERT INTO subscribers (`EMAIL`) VALUES ('%s')", GetSQLValueString($_POST['email'], "text")); echo $insertSQL; exit; $Result1 = mysql_query($insertSQL, $subscribers) or die(mysql_error()); } } else { $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" name="form1" method="POST"> Email Address: <br/> <input type="text" name="email" onfocus="if (this.value == 'Email...') {this.value = '';}" onblur="if (this.value == '') {this.value = 'Email...';}" value="<?php echo $_POST['email']; ?>Email..." size="50"/> <br/><br/> <input type="submit" name="Submit" /> <input type="hidden" name="MM_insert" value="form1" /> </form> <?php } ?>

still didnt change anything. and i only have two columns. ID and EMAIL.

it didnt change anything

well that took away the first error, but still not inserting valid emails. now its just saying: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'art.stevenacobs@yahoo.com''' at line 1

oh thats no problem-oh man. thats exactly what i was trying to work with early. but its giving an error code and not inserting valid emails. Notice: Undefined variable: editFormAction in /home/steven/public_html/testing.php on line 59 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'art.stevenjacobs@yahoo.com''' at line 1 58 if (isset($_SERVER['QUERY_STRING'])) { 59 $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); 60 }

Sorry to bug you, u have already helped me out tremendously. but i have one last question. how can i validate that the email isn't in the database, to prevent multiple same emails being entered?