WesL
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Posts posted by WesL
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Hi guys,
Does anyone have an idea of how I could write a script to automatically thumbnail a video file?
I'm not looking for someone to do it for me, just help point me in the right direction.
Any ideas would be helpful.
Thanks
Wes -
I did something similar with a sight that I'm working on right now. I was pasing the 'order number' on to the following page(s) and calling certain fields from the MySQL db.
I used a variable of $ID as the variable to track
I used a hyper link:
echo "<a href='phpscript.php?pid=$id'> Click here to continue with order # $id </a>";
Using a '?' after the *.php page name allows to you send variables to the next page and have those variables acted on.
Next, we need to receive the info:
$id = $_GET['pid']; $result=mysql_query("SELCT * FROM images WHERE id={$id}");Good Luck
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give the a try
</head> <body bgcolor="282828" leftmargin="0" topmargin="0" marginwidth="0" marginheight="0"> your code </body>
should give you a smokey gray/black background.
Cheers
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Have attempted to declare them as global variables prior to showing them on the page?
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Thank you...that solved the error problem that I was having. However, the end result is not what I expected. Rather than only the records that belong to that user, I'm getting a list of all records in the database regardless of who they belong to.
Any Suggestions would be appreciated.
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I have a log-in script that after loging in takes the user to a 'product page.' On that 'product page' it says "Welcome 'username' " and that part works fine.
What I'm trying to add to the page for a list of the users $rows in a MySQL db to show on the page also.
This is the code I'm using welcome or kick the user. (this one works fine)
<?php if(!$_SESSION['username'] && !$_SESSION['password']) { echo '<span style="border: #000 1px solid; background-color: #CCCCCC"> <center>Welcome, <b>'.$username.'</b> Redirecting you....</center></span> <meta http-equiv="refresh" content="2;URL=pass/index.php" />'; } else { echo 'Welcome '.$_SESSION['username'].''; }?>This is the code I trying to use that'll pull the info from the db
<?php $query = "SELECT * FROM images WHERE user="$_SESSION[.'username'.]" Order By id"; include("config.php"); $result = mysql_query($query) or die(mysql_error()); mysql_close(); $output = " <html> <body> <table> <thead> <td>Id/Order</td> <td>Address</td> </tr> </thead> ";I might mention that the 2nd bit of code works fine when I hard code in a User's ID...so I know that it's seeing the db, it just when I try to re-use the variable of username that I get this error.
Unknown column 'username' in 'where clauseAny suggestions would be great.
Copy image from site to site using URL
in PHP Coding Help
Posted
I'm trying to copy an image/file from one website to a directory in another, using the URL for the source image/file.
I'm not sure which PHP function to use. Does anyone have a suggestion?