[PHP coding help .. ? query and if statements playing up]

when i echo it out it comes up with this 

 

Warning: mysql_query() expects parameter 1 to be string, resource given in C:\xampp\htdocs\PhpProject1\New Review.php on line 27
error inserting new record

 

and when i switch them about all it says is 

 

'error inserting new record' but no warning codes.. whats the next thing i could do as it not inserting it into the database which i am trying to achieve

[PHP coding help .. ? query and if statements playing up]

so im connecting my netbeans php to phpmyadmin (database).. now in this i am trying to create a php code  statement which will take the inserted data into the html fields and insert them into my database successful.. anybody know what im doing wrong here is the error message:

 

Warning: mysql_query() expects parameter 1 to be string, resource given in C:\xampp\htdocs\PhpProject1\New Review.php on line 27

error inserting new record

 

 

 

 

 

<?php

if (isset($_REQUEST['submitted'])) {

    

    include('connect database.php');

    

    

    $showtitle = $_POST['SHOWTITLE'];

    $showreview =$_POST['SHOWREVIEW'];

    $sqlinsert = "INSERT INTO reviews (SHOWTITLE,SHOWREVIEW) VALUES('$showtitle', '$showreview')";

    

    if (!mysql_query($dbConn,$sqlinsert)) {

        die('error inserting new record'); 

        

        

        

    }

 

here is my html coding with it

 

<form method="post" action="New Review.php">

<input type="hidden" name="submitted" value="true" />

<fieldset> 

    <legend> New Reviews</legend> 

    <label> Enter show title:<input type ="text" name="SHOWTITLE" /></label>

    <label> Enter Review: <input type ="text" name="SHOWREVIEW" /></label>

</fieldset> 

<br /> 

<input type ="submit" value ="add new review" />

</form>

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[error message help? :((]

i have tried that part of changing and now it comes up with this Notice: Undefined variable: INSERT INTO reviews (SHOWTITLE,SHOWREVIEW) VALUES('Match Of The Day', 'amazing') in C:\xampp\htdocs\PhpProject1\New Review.php on line 27

error inserting new record

 

 

 

<?php

if (isset($_POST['submitted'])) {

    

    include('connect database.php');

    

    

    $showtitle = $_POST['SHOWTITLE'];

    $showreview =$_POST['SHOWREVIEW'];

    $sqlinsert = "INSERT INTO reviews (SHOWTITLE,SHOWREVIEW) VALUES('$showtitle', '$showreview')";

    

    if (!mysql_query($$sqlinsert)) {

        die('error inserting new record'); 

        

        

        

    }

[error message help? :((]

so all i do is replace 

 

if (!mysql_query($dbConn,$sqlinsert)) {

 

to your code? am i correct in saying that and thats the only issue involved??

[error message help? :((]

so im connecting my netbeans php to phpmyadmin (database).. now in this i am trying to create a php code  statement which will take the inserted data into the html fields and insert them into my database successful.. anybody know what im doing wrong here is the error message:

 

Warning: mysql_query() expects parameter 1 to be string, resource given in C:\xampp\htdocs\PhpProject1\New Review.php on line 27

error inserting new record

 

 

 

 

 

<?php
if (isset($_REQUEST['submitted'])) {
    
    include('connect database.php');
    
    
    $showtitle = $_POST['SHOWTITLE'];
    $showreview =$_POST['SHOWREVIEW'];
    $sqlinsert = "INSERT INTO reviews (SHOWTITLE,SHOWREVIEW) VALUES('$showtitle', '$showreview')";
    
    if (!mysql_query($dbConn,$sqlinsert)) {
        die('error inserting new record'); 
        
        
        
    }

 

here is my html coding with it

 

<form method="post" action="New Review.php">

<input type="hidden" name="submitted" value="true" />

<fieldset> 

    <legend> New Reviews</legend> 

    <label> Enter show title:<input type ="text" name="SHOWTITLE" /></label>

    <label> Enter Review: <input type ="text" name="SHOWREVIEW" /></label>

</fieldset> 

<br /> 

<input type ="submit" value ="add new review" />

</form>