
play_
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How To Add Dynamic Textbox (Row) And Save To Database Using Php
play_ replied to miyotz's topic in PHP Coding Help
He's just about ready to sue every software maker that uses a function called addRow- 5 replies
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Wouldn't CSS suffice by giving the div a height and overflow:scroll; ? moving this to CSS forum as it's really client sided.
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You are using the form name in your $_POST check. Use the name of your button. So instead of if(isset($_POST['search'])) {echo "Welcome" . $_POST["fname"];} else {echo "post not set for fname ";} do: if(isset($_POST['submit'])) {echo "Welcome" . $_POST["fname"];} else {echo "post not set for fname ";} --edit-- beaten by someone else. for the second part of your script, you forgot an 'else', so you get "request method post not set" as well. if($_SERVER['REQUEST_METHOD'] == "POST") { echo "form submitted";}ELSE{echo "request method post not set ";}
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This is now how this is typically done: Ideally you would have one page. say, user.php you would link to that page with a variable, like site.com/user.php?id=135 or site.com/user.php?u=wait you would then use $_GET['id'] and query a database for that members info. whichever way, you'll still need mod rewrite to do what you want
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Right. So when they submit the form and you detect errors, filled out input fields will have a value. So if user filled out the 'name' input field, but left out the 'email' or 'password' field, $_POST['name'] will hold a value when you redirect them to the same page. Your HTML form fields should look like this <textarea name="message" > <?php if(isset($_POST['message'])) echo $_POST['message'];?> </textarea>
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How To Add Dynamic Textbox (Row) And Save To Database Using Php
play_ replied to miyotz's topic in PHP Coding Help
few things. 1. Use code tags to markup code 2. Use jQuery 3. "function addRow®{" what?- 5 replies
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You just simply echo out the variables. It depends where you store them. Database, $_POST or $_SESSION.
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As mrMarcus said. user_id is probably an auto increment field, so you can delete the line `user_id` , if it still doesn't work, uncomment "//echo mysql_error(); //debugging purposes, uncomment when needed". and comeback with a decent error message. it even says right there. "debugging purposes. uncomment when needed".
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Array - Print The Table And Take Out The Values
play_ replied to dani33l_87's topic in PHP Coding Help
A bunch of syntax errors on that code <?php $rows = range(0, 9); $cols = range(0, 9); echo "<table border='1' cellpadding='10'cellspacing='5' align='center'>"; $r = 0; while ($r < count($rows)) { $c = 0; echo "<tr> "; while ($c < count($cols)) { echo "<td>"; echo $rows[$r] * $cols[$c]; echo "</td>"; $c++; } echo "</tr>"; $r++; } echo '</table>'; -
As of right now, there is none. I have tried all joins that I could. I am not too knowledgeable with complex queries, so i came here. One alternative is to use GROUP_CONCAT...but since it's for a pastebin site, i couldn't really risk using it since the separator could be in someone's paste where pastes.paste_id = $result['ids.paste_id'] <-- not syntax correct, but just to give the idea. alternative 2 is to run two queries. one to get the last 10 paste_id from 'ids'., and then for each id, do a select * from
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Not sure if what I am trying to do is possible. It's gonna be a bit hard to explain but it's actually simple. Ok so first off, here's what an example paste(it's a pastebin site): http://tabbit.org/9aEXPo http://tabbit.org/-pua What I need help with is the 'recent' link, where I would like to display the last 10 or so pastes. The complication arises with the fact the pastebin has 'tabs'. MySQL tables are set up as such. When you make a new paste, it's id gets created in the table 'ids' as 'paste_id'. Each tab in the paste gets inserted into 'pastes' table, and it connects to the 'ids' table via paste_id. So for the 'recent' page, I am trying to gather some of the latest pastes. Right now the recent just prints an array that the query returns. If you go there right now, you'll see Array ( [pastes] => Array ( [0] => Body of tab 1, paste 1 [1] => Body of tab 2, paste 1 [2] => Body of tab1, paste 2 [3] => Body of tab2, paste 2 ) [tabs] => Array ( [0] => Tab1 [1] => Tab2 [2] => Tab1 [3] => Tab2 ) ) Ideally, I would want MySQL to return an array(paste_id) that contains 2 inner arrays - one holding the tab names, and the other holding the body of the paste array => [paste_id (1)] [tabs] [0] tab1 [1] tab2 [paste] [0] <?php .... ?> [1] <? php code or anything ?> [paste_id (2)] [tabs] [0] tab1 [1] tab2 [paste] [0] import twisted [1] from some.module import * is it possible?
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What would be the simplest way? Do you use a method in the child class? Personally I use parent::$this->whatever; But I was wondering what you guys do.
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at the very minimum connect to a database and do basic queries like SELECT * FROM table WHERE something = value. maybe basic OOP concepts too.
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This should be in the javascript forum. Also, use jQuery.
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Interesting. If i replace the contents of words.txt with a number on each line, i get Words: 2 , 9 Words: 8 , 9 Words: 5 , 10 Words: 2 , 7 Words: 9 , 10 Words: 4 , 10 Words: 6 , 8 Words: 8 , 10 Words: 2 , 5 Words: 1 , 9 words.txt is just list of 5000+ words. @Gizmola - no. i don't see the problem there. Your results seem random.
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Although I found a way around it, I want to know, logically, why the behavior is so. // words.txt is a text file with dictionary words on each line $lines = file('words.txt'); // The goal is to pick two random words, 10 times. for($i = 0; $i < 10; $i++) { #shuffle($lines); <--- un-commenting this is the fix i found. $words = array_rand($lines, 2); echo "Words: " . $lines[$words[0]] . ", " . $lines[$words[1]] . "<br>"; } If i don't have shuffle() in there, I get two different set of words, not 10. ie (result from code above) Words: massacre , spear Words: frontiersman , kumquat Words: massacre , spear Words: frontiersman , kumquat Words: massacre , spear Words: frontiersman , kumquat Words: massacre , spear Words: frontiersman , kumquat Words: massacre , spear Words: frontiersman , kumquat Why is this?
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No, not yet. I read that "everyone should build their own MVC framework" to understand it best. So that's where I started. The comments on the 3rd post here (amongst others somehwere) indicate that the Model should be handling the form. http://stackoverflow.com/questions/6015040/how-are-forms-used-in-an-mvc-framework
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Ok but -how- would i handle the POST? Do i make the form action go to the controller? and if so, what happens then? the IF statement will be inside a method. I need a way to call that method.
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The query failed. probably selecting from a wrong table or selecting wrong column.... i think. You should look into PHP's PDO class http://php.net/manual/en/book.pdo.php
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Creating my own little MVC framework to understand it better. Question - When a view outputs a page with a form in it, how is the form handled? ie, what is the action of the form? Where does the IF statement that checks if the submit button was pressed, go? I was told inside a method in the Model...but I don't understand how a method can check if a form has been submitted or not. Any help greatly appreciated.