Jump to content

NathanLedet

Members
 View Profile  See their activity

  • Posts

    102

  • Joined

  • Last visited

    Never

 Content Type 

Posts posted by NathanLedet

    Private....from what?

    in PHP Coding Help

    Posted

    When you're working in OOP and you have a private function, what exactly is "private" about it?

     

    It can't be invoked by the client code.  Example:

    class PrivateExample
{
   private $msg = "Hello!";

   public function __construct() {}

   private function getMsg()
   {
      return $this->msg;
   }
}

$example = new PrivateExample();
$msg = $example->getMsg(); // WON'T WORK

     

    Private functions are typically used as bookkeeping functions for the objects in which they reside.  That, or in breaking down a complex public function into smaller parts that shouldn't be accessed directly by the world at large.

     

    OK I think I'm following you on this.

     

    In other words, private functions are functions only someone running Administrator codes can access - meaning, if I'm logged into my admin panel, then I have access to those Private functions?

     

    er am I off base here?

    Thanks :)

    Need help with setting a position

    in PHP Coding Help

    Posted

    OK... tinkered around with the code a little bit and this code here works.  I appreciate you help F1Fan, and I apologize for not being clear.  My original code in my first post had nothing to do with the result, and therefore $sel_page makes no difference

     

    for($count=1; $count <= $page_count+1; $count++){
echo "<option value=\"{$count}\" ";
if ($count == $page_count+1){
		echo " selected=\"selected\"";
		}
		echo ">{$count}</option>";
}

    Need help with setting a position

    in PHP Coding Help

    Posted

    functions.php

    function get_all_pages(){
global $conn;
$query = "SELECT * FROM pages ORDER BY position ASC";
$page_set = mysql_query($query, $conn);
confirm_query($page_set);
return $page_set;	
}

     

    add_page.php - Form

    $page_set = get_all_pages();
$page_count = mysql_num_rows($page_set);
for($count=1; $count <= $page_count+1; $count++){
echo "<option value=\"{$count}\">{$count}</option>";
}

     

    Need help with setting a position

    in PHP Coding Help

    Posted

    Yes let me gather it up. 

     

    but I don't think I was clear enough - sorry about that. 

     

    The code I posted does work.  It works whenever I EDIT the page.  It properly displays the selected position.

     

    What I am trying to do is re-structure that code that I already have and make it so that when I'm ADDING a page, it automatically chooses the last available position.  So, if I have 3 pages, I want that script to display and have already selected "4" in the drop down menu.

     

     

    Need help with setting a position

    in PHP Coding Help

    Posted

    Where is your $sel_page['position'] variable being set?

    It's set elsewhere in the page and returns a number from the database. that number is the position: 1, 2, 3 etc.

     

     

    Also, why not just do this:

    	

if (($page_count+1) == $count){
echo " selected";
}

     

     

    I dunno... Ask Kevin Skoglund...I'm following his lessons.  :)

     

     

    Need help with setting a position

    in PHP Coding Help

    Posted

    I'm working on a small CMS and I've been following the tutorials at Lynda.com.

     

    When I'm on the page to Add a Page, I want to set its position (the order), so I have a drop down list which counts the number of records inside the database, and then adds 1 (if I have 3 entries, I want "4" to be highlighted so it will automatically be put in the last position)

     

    The code I currently have will count the rows, and then select the position it's currently in:

     

    $page_count = mysql_num_rows($page_set);

for($count=1; $count <= $page_count+1; $count++){
echo "<option value=\"{$count}\"";
	if ($sel_page['position'] == $count){
		echo " selected";
		}
			echo ">{$count}</option>";
	}

     

    I want to modify that code so that when I'm adding a new entry, it automatically chooses the last available option.

     

    Thanks for the help :)

    [SOLVED] E-mail problems

    in PHP Coding Help

    Posted

    I have a script written where people can add addresses to their address book, and then when they are sending an e-mail, they go through the list of e-mail addresses and check each e-mail they want to send the e-mail to.  When they click "Send", it sends them to another page, which dispatches the e-mail and gives confirmation.

     

    The problem is if it sends to more than one person, the person that is #3 on the list will receive the message 3 times (one right under the other, not 3 different e-mails)

     

    I was sent an e-mail the other day, and I was 1 of 6 people the message was sent to, and I received the message 6 times...so something funky is going on with my loop.

     

    $message = $_POST['message'];
$emails = $_POST['emails'];

foreach ($emails as $e => $value){
  $str_emails .= $e . "<br />";

  $to = $e;

$subject = "You have a message";
$body .= $message . "<br /><br />";
$headers = "From: Nate <nate@email.com>\r\n" . "X-Mailer: php\r\n";
$headers .= "Content-type: text/html\r\n"; 

if (mail($to, $subject, $body, $headers)) {
  echo "<p>Message sent to " . $e . "</p>";
}//end if
else {
  echo("<p>Message delivery failed...</p>");
}//end else
}//end foreach loop

    Foreign Key

    in MySQL Help

    Posted

    Is it necessary to have a Foreign Key when performing Joins?

     

    From my understanding, a foreign key is the relationship between two tables.  But performing Joins creates the relationship as well.  Am i on the right rack?

    Insecure Login

    in PHP Coding Help

    Posted

    Well alright then. I learned something :)

     

    The script is not complex at all. the only purpose is to have only one admin with the ability to log in.  I agree, yes, it's impractical and I would do it in some other way...

    Insecure Login

    in PHP Coding Help

    Posted

    brute force, possibly add if 5 incorrect login attempts block IP for 30 mins

     

    what if user went straight to admin.php would that ask them to log in?

    yes it looks for the "loggedin" session.  If it doesn't exist, it redirects you to login.php

    Insecure Login

    in PHP Coding Help

    Posted

    I have this little script that another web designer set up and I am looking over it on a friend of mine's web site.  From what little I know about hacking (none, to be honest), I am pretty sure this is an insecure way of logging in. What I would like to know is how insecure and easy it is to crack.

     

    login.php:

    if(isset($_POST['Submit'])){	

$username = "admin"; //Set username here
$password = "admin"; // Set Password here

$username1 = $_POST['username'];
$password1= $_POST['password'];

if($username==$username1 && $password==$password1){

session_start();

session_register('loggedin');

header( "Location: admin.php" );
}else{
echo "<p align='center'><font color='red'>Wrong Username/Password !!</font></p>";
}
}
?>

     

     

     

     

    [SOLVED] Contact form - Keeping structure

    in PHP Coding Help

    Posted

    Having a little issue with my contact form, where the text field that gets filled out gets all of the extra space stripped out.

     

    My code uses htmlentities and strip slashes:

     

    $message = htmlentities(stripslashes($_POST['message']));

     

    and a message that has paragraph breaks does not keep the extra space. How can I keep the hard returns? 

     

    Thanks,

    -Nate

    [SOLVED] Uknown error:

    in PHP Coding Help

    Posted

    <input type='hidden' name='idz' value='". $_GET['user'] ."'>

     

    can you echo that out and tell us what that says?

     

    I'm thinking, if you switch up your quotes for the value, that may help.

     

     <input type='hidden' name='idz' value="'. $_GET['user'] .'">;

    [SOLVED] two drop down.

    in Javascript Help

    Posted

    I use this script, although I wish I knew where I got it from so I could give proper credit...I'm thinking w3schools may have had something to do with it :)

     

    Inside my main page, I have a form.

     

    <select name="clients" onchange="showProject(this.value)">
<option value="">Select a Client</option>
<?php
   			include('includes/mysql_connect.php');
      			$query = 'SELECT id, clientName FROM client';
		while ($row = mysql_fetch_array($result, MYSQL_NUM)){
				echo "<option value=\"$row['id']\">$row['clientName']</option>\r";
			}			
			?>
</select>

     

    This is our script that populates the first "select" field.

     

    But then, based on your selection, I needed it to bring up another "select" field, with projects that belong to that specific client.

     

    Below </select>, I have a div with the ID of getProject

    <div id="getProject"></div>

     

    In my header, I have my JS:

    <script language="javascript" src="selectedclient.js"></script>

     

    var xmlHttp

function showProject(str)
{ 
xmlHttp=GetXmlHttpObject()
if (xmlHttp==null)
{
alert ("Browser does not support HTTP Request")
return
}
var url="getProject.php"
url=url+"?q="+str
url=url+"&sid="+Math.random()
xmlHttp.onreadystatechange=stateChanged 
xmlHttp.open("GET",url,true)
xmlHttp.send(null)
}

function stateChanged() 
{ 
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
{ 
document.getElementById("getProject").innerHTML=xmlHttp.responseText 
} 
}

function GetXmlHttpObject()
{
var xmlHttp=null;
try
{
// Firefox, Opera 8.0+, Safari
xmlHttp=new XMLHttpRequest();
}
catch (e)
{
//Internet Explorer
try
  {
  xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
  }
catch (e)
  {
  xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
}
return xmlHttp;
}

     

    and then I have one more file, getProject.php

    <?php
$q=$_GET["q"];

$con = mysql_connect('localhost', 'username', 'password');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("dbname", $con);

$sql="SELECT  projectID, projectName FROM project WHERE clientID = '".$q."'";

$result = mysql_query($sql) or die('Error, query failed');


echo 'Select a Project:';
echo '<select name="optproject">';
echo '<option>Select a Project</option>';

			while ($row = mysql_fetch_array($result)){
				echo "<option name=\"projects\" value=\"" . $row['projectID'] . "\">" . $row['projectName'] . "</option>";
			}


			echo '</select>';


mysql_close($con);
?>

     

    I made a bunch of modifications and changes to this script that I've posted, so you may need to make your own modifications to get it properly working.

     

    But you should be able to understand what's going on and learn from it.

     

    Getting information from mysql

    in PHP Coding Help

    Posted

    Just off the top of my head...I can't test this so lemme know if this helps:

     

    In your form, I added a "value" attribute to the input field:

    <input name="lastname" type="text" id="get_lastname" value="lastname">

     

    in variables.php, change it to:

    $get_lastname = trim(stripslashes($_POST['lastname']));

     

    I was going to write out a loop that would retrieve the data from the database, but I just realized you're using mysqli, which I am not familiar with...so I'll stop here and let someone else answer...

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.