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nickivz

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  1. I have used the example (and some others) program but for some reason i don't seem to be able to read data from my database. Can someone help me to find out what is wrong. The database is located at www(.)canary(.)co(.)za, database name = canaryco_codes table = towns password = Lechwe01 fields = town-id, town, province, street, box, area If you run www(.)canary(.)co(.)za/codes3 the result is: "; echo " town-id " " town " " province " " street"; while(list($town-id,$town,$province,$street)= mysql_fetch_array($val)) { echo ""; echo "".$town-id.""; echo "".$town.""; echo "".$province.""; echo "".$street.""; echo ""; } echo ""; echo " Done n"; ?> This is the sample program: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Database</title> </head> <body> <?php //connect database $con=mysql_connect("localhost","**********","********") or die(mysql_error()); // select database mysql_select_db("canaryco_codes",$con); //select values from towns table $data="SELECT * FROM towns"; $val=mysql_query($data); echo "<table border='1'>"; echo " <p>town-id " " <p>town " " <p>province " " <p>street"; while(list($town-id,$town,$province,$street)= mysql_fetch_array($val)) { echo "<tr>"; echo "<td>".$town-id."</td>"; echo "<td>".$town."</td>"; echo "<td>".$province."</td>"; echo "<td>".$street."</td>"; echo "</tr>"; } echo "</table>"; echo "<p>Done </p>n"; ?> </body> </html> Thanks a lot.
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