[MSSQL Connection]

Barand the dlls are in the correct dir

[MSSQL Connection]

I have a general question regarding this function and regarding php general

If i understand well, sqlsrv_connect() is a php function? The dll is the driver that perform a connection to an SQL server, when the specific function is called. Why when i type this function in a php editor, the php doesn't recognize it as a function? Logically php must understand this function and when i run the script, if  the driver is not installed and is not placed in the correct folder, in runtime to get an error.

Thank you

[MSSQL Connection]

Thank you for your responce

It is not a warning, but error in my script. The php_sqlsrv_80_ts_x64.dll is in htdocs folder.

I copied the dlls to the ext subfolder but it did not work.

[MSSQL Connection]

Hello all,

I am using php 8.0.8 and when i use the sqlsrv_connect(  $serverName, $connectionInfo ) function i get "undefined function". I use as an editor the Visual Studio Code.

I have modified the php.ini with extension= D:\PROGRAMS\XAMPP\htdocs\php_sqlsrv_80_ts_x64.dll ( i thing this is the mssql server driver)

Any help?

[Session Problem]

i changed the   error_reporting(E_ALL); to   error_reporting(E_ERROR); and the error message disappeared. Thank you

[Session Problem]

Thanks you for your answer

When i place the session_start() at the begining of the script, then the following error occurred ( Notice: session_start(): Ignoring session_start() because a session is already active in Pel_Rv.php on line 5 ), but the code runs correctly. My code is

<? php

 $seqno_pel='';   

    session_start();

    error_reporting(E_ALL);

    ini_set('display_errors', '1');

[Session Problem]

Hello,

I have developed a page selecting and displaying data from a DataBase(mysql), as following

$result = mysqli_query($conn, $sql);

$fetch = mysqli_fetch_row($result);  

$row_code = $fetch[0];

session_start();

$_SESSION['pel_seqno'] = $row_code; 

The above page has tabs. In the second tab i access the $_SESSION['pel_seqno'] as following

<?php

    $seqno_pel='';

    $seqno_pel = $_SESSION['pel_seqno']; 

I use $seqno_pel variable to retrieve some other data from another table in the DataBase. So far so good, Inside the tab i have a button redirecting in another page and i want to use the value of $_SESSION['pel_seqno']; and i can not.

The code which i am trying to access again the $_SESSION['pel_seqno'];  is the following

<?php    

    $seqno_pel = $_SESSION['pel_seqno'];  

When the button is pressed i get the following error message

Warning: Undefined variable $_SESSION in D:\PROGRAMS\XAMPP\htdocs\CARDIO\Pel_Rv.php on line 5
Warning: Trying to access array offset on value of type null in D:\PROGRAMS\XAMPP\htdocs\CARDIO\Pel_Rv.php on line 5

Is it possible someone to help me with this.

Thank you in advance