groston

Not sure if this is PHP or just basic HTML, but is there some way to show, on a web page, the default file download directory? For example, in Firefox, if you go to Tools->Settings->General and look for 'Downloads: Save files to', can this directory be displayed (as text)? If so, how?

Not sure what is going on, please help me. I have written a PHP file that generates a CSV file that is drawn from a MySQL database. This works just fine because I used this https://stackoverflow.com/questions/15769732/write-to-php-output-buffer-and-then-download-csv-from-buffer as a guideline. The problem is this: After the CSV file is downloaded, I want the site to go to another page. Using the code in the reply from DigiLive on 12 Jan 2016 as the basis, after the line ob_end_flush(); I have the lines echo "<script type='text/javascript'> document.location = 'OtherPage.php'; </script>"; exit; These lines work perfectly elsewhere, but here they do nothing. What am I missing?

Yeah, I figured this out. I simply put the upload code inside a if that checks to see if the button was pushed. Sorry to have wasted everyone's time - some more thinking and I figured it out. Thanks.

I have created a simple web site that is used to enter data into a database. Each page essentially has: <form role="form" method="post"> ... </form> The site works without issue. However, I want to add to the form the ability to upload an image file. I wrote a small test page that does this and it works without issue. However, the problem is this: The test page has the following: <form action="fileUploadScript.php" method="post" enctype="multipart/form-data"> The first <form> uses code on the page itself to do the database insertion, whereas the second <form> uses an external php file to upload the file. In terms of executing the code, I suspect that I could make this work with two mouse clicks: one to upload the file and the other to enter the data. Is there a way to achieve this with one mouse click? Note that there are a dozen fields or so, and identifying all of them to have the external php file handle them might be a pain... Thanks.

I am beyond confused and am hoping that you can help! I have a database and one table looks like this: dbTable { RowID int(10) unsigned <this value is created automatically> Str varchar(100) Val int(10) unsigned } In my html/php, I have the following test code: $sql = "SELECT * FROM dbTable WHERE RowID = 5"; $entityData = $mysqli->query($sql); $EntityInfo = $entityData->fetch_assoc(); $dStr = $EntityInfo[Str]; $dVal = $EntityInfo[Val]; echo “first line”; echo "str: " . $dStr; echo "val: " . $dVal; $sum = $dVal +5; echo "sum: " . $sum; if ($dVal > 0) { echo "if Val: " . $dVal; } The first four echo statements work, however, I cannot get the code to enter the if loop. It seems that the code knows that $dVal is an integer because the sum shown is correct. What must I do to make the if statement work?