marcus
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Posts posted by marcus
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Yep, works perfectly now, thanks!
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i am making a shoutbox, and when i want to echo/print off the rows in the table it keeps printing thousands of commas
code:
[code]
<?php
include('mysql.php');
$sql = "SELECT * FROM shoutbox";
$res1 = mysql_query($sql);
echo "<tr><td>";
echo "<div style='border:0px solid black; height:200px; width:130px; overflow:auto; font-family:verdana;font-size:10pt;color:black;'>";
while("$res2 = mysql_fetch_assoc($res1), MYSQL BOTH"){
printf ("<a href='$res2[website]'>$res2[name]</a><br>$res2[message]");
};
mysql_free_result($res1);
?>
[/code]
help? -
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If you do not have MIME Types set up, go into your cPanel (i assume you have one)
go down to MIME Types
in the first text box (MIME Type) type: application/x-httpd-php
then in the second box type: php,php3,phtml,php4 and hit add -
Make a new file and make the contents
<?php
phpinfo();
?>
If not, you may not have the MIME Types set up correctly. -
[code]
mysql_connect("localhost","root","root");
mysql_select_db("dbname");
$query = mysql_query("SELECT * FROM tablename");
$fi = "test.xml";
echo "<?xml version=\"1.0\" encoding=\"ISO-8859-1\" ?>
<rss version=\"2.0\">
<channel>";
while ($row1 = mysql_fetch_array($query, MYSQL_BOTH)) {
echo " ";
printf ("
<title>Test XML File</title>
<link>yeah</link>
<description>yeah</description>
<item>
<title>%s</title>
<link>%s</link>
<description>Added on %s at %s.</description>
</item>",$row1[title],$row1[url],$row1[date],$row1[time]);
};
mysql_free_result($query);
echo "</channel>
</rss>";
[/code]
you can try that -
Haha, no problem!
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You might aswell just leave the mysql error out, or just use or die();
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[code]
if(!$Email){
$Email = "defaultemail@email.tld";
};
[/code] -
don't bother putting the or die(); part, just to test.
and you have two ;'s on that line -
[code]
$sql = "INSERT INTO usesrs (group, user_name, password, first_name, last_name, gender, email_address) VALUES ('2', 'user', 'pass', 'isaac', 'meals', 'male', 'email')";
$result = mysql_query($sql);
if($result){
echo "successful in registering you an account";
}
else
{
echo "couldn't submit";
echo "
";
echo $group;
echo "
";
echo $first_name;
echo "
";
echo $last_name;
echo "
";
echo $user_name;
echo "
";
echo $email_address;
echo "
";
echo $password;
echo "
";
echo $gender;
}
[/code] -
Easy error.
just make it all one line
[code]
$connection = mysql_connect(host,dbuser,dbpass);
$db = mysql_select_db(dbname,$connection);
[/code] -
Post the script.
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First file:
[code]
<?php
$connection = mysql_connect(localhost,zack_rpg,omfgg212);
$db = mysql_select_db(zack_rpg,$connection);
$sql111 = "SELECT * FROM stats WHERE id=$_COOKIE[id]";
$res454 = mysql_query($sql111);
$res1 = mysql_fetch_array($result454, MYSQL_BOTH);
$mana = $res1[mana];
$level = $res1[level];
$ladd = $level * 20;
if($mana < $ladd){
$sql = "UPDATE stats SET mana = $mana + 2";
$result = mysql_query($sql);
}else{
die();
};
?>
[/code]
Second file:
[code]
<?php
$connection = mysql_connect(localhost,zack_rpg,omfgg212);
$db = mysql_select_db(zack_rpg,$connection);
$sql111 = "SELECT * FROM stats WHERE id=$_COOKIE[id]";
$res454 = mysql_query($sql111);
$res1 = mysql_fetch_array($result454, MYSQL_BOTH);
$health = $res1[health];
$level = $res1[level];
$ladd = $level * 100;
if($health < $ladd){
$sql = "UPDATE stats SET health = $health + 10";
$result = mysql_query($sql);
}else{
die();
}
?>
[/code]
Errors:
[code]
X-Powered-By: PHP/4.4.4
Content-type: text/html
<br />
<b>Warning</b>: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in <b>/home/zack/public_html/rpg/cron/update_mana.php</b> on line <b>6</b><br />
[/code]
[code]
X-Powered-By: PHP/4.4.4
Content-type: text/html
<br />
<b>Warning</b>: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in <b>/home/zack/public_html/rpg/cron/update_health.php</b> on line <b>6</b><br />
[/code] -
nevermind, got it working -locks-
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Didn't do anything but keep the error the same.
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Ok, I get the normal
[code]
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/zack/public_html/rpg/inc/addxp.php on line 6
[/code]
Code:
[code]
<?php
$connection = mysql_connect(localhost,zack_rpg,passwordhere);
$db = mysql_select_db(zack_rpg,$connection);
$sql = "SELECT * stats WHERE stats.id=$_COOKIE[id]";
$res = mysql_query($sql);
$res2 = mysql_fetch_assoc($res);
$xp = $res2[xp];
$rand = rand(0,10);
$xpadd = "$xp + $rand";
$sql2 = "UPDATE stats SET xp = `$xpadd` WHERE stats.id=$_COOKIE[id]";
$res3 = mysql_query($sql2);
?>
[/code] -
form:
[code]
<form name=fn action=page.php method=post>
<table border=0 cellspacing=0 cellpadding=3>
<tr><td>
Your Name:<td><input type=text name=name value="<?=$_COOKIE[name]?>">
<tr><td>
Next Field:<td><input type=text name=field1 value="<?=$_COOKIE[field1]?>">
<tr><td colspan=2>
<input type=submit value="Send">
</table>
</form>
[code]
then page.php
[code]
<?php
$name = $_POST[name];
$field1= $_POST[field1];
setcookie(name,$name);
setcookie(field1,$field1);
echo "info set";
?>
[/code]
then once you go back to the other page (not page.php) it should echo off the information in the text fields[/code][/code] -
you could always just do
on your form make like the date:
[code]
$date = date("d/m/y");
[/code]
then when grabbing it
[code]
$date = $_POST[date]; //getting posted
[/code]
then to get each field
[code]
$d1 = explode("/",$date);
//or explode("/",$_POST[date]);
[/code]
then:
[code]
$day = $d1[1];
$month = $d1[2];
$year = $d1[3];
[/code]
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Like to store multiple item ids in like a database table for the users and stuff
like
[code]
$sql = "SELECT items FROM userdb WHERE userdb.id=$_COOKIE[id]";
$result = mysql_query($sql);
$result2 = mysql_fetch_assoc($result);
$items = explode(",",$result2);
while($row == $items){
echo $fc_array[array_rand($fc_array)];
};
mysql_free_result($result);
[/code]
would something like that work? -
It says...
Why would I need to print it?
I mean it's finding it inc/$page.inc -
You can just use mysql_fetch_array
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Ok, what I'm trying to do is, if the file does not exist it will echo off like This file does not exist, or whatever.
Here is my code:
[code]
<?php
$page = $_GET[page];
$ref1 = $_GET[ref];
$ref = $_SERVER[REQUEST_URI];
include('refs.php');
if($page == false){
//$number = "7";
include('news/show_news.php');
}else
//if(!file_exists($page)){
//echo "This page does not exist, sorry :(";
//}else
if($page == $page){
include("inc/$page.inc");
};
?>
[/code]
But each time I use that, I go to a page does exist it says it doesn't (when uncommented). How can I fix this? -
Thanks Ken, works beautifully!
mysql help needed (again)
in PHP Coding Help
Posted
[code=php:0]
if($act == edit)
{
$q = "SELECT * FROM `shoutbox` WHERE `id`=$id";
$query = mysql_query($q);
$shout = mysql_fetch_array($query);
echo"
<table border=0 cellspacing=0 cellpadding=1>
<tr><td>
<form action=shoutadmin.php method=post>Name:<td><input type=text name=mname value=$shout[name]>
<tr><td>
Website:<td><input type=text name=mwebsite value=$shout[website]>
<tr><td>
Message:<td><input type=text name=mmessage value=$shout[message]>
<input type=hidden name=messid value=$shout[id]>
<input type=hidden name=action value=doedit>
<tr><td colspan=2>
<input type=submit value='Edit'>
</table>
";
}
if($act == doedit)
{
$mname = $_POST[mname];
$mwebsite = $_POST[mwebsite];
$mmessage = $_POST[mmessage];
$messid = $_POST[messid];
$sqll = "UPDATE `shoutbox` SET `name` = '$name',
`website` = '$website',
`message` = '$message' WHERE `id` =$messid LIMIT 1 ";
$ress = mysql_query($sqll);
echo"Shout Edited";
}
[/code]
alright, the first part where it shows everything works, but when i update it, it doesnt work. it just stays the same, any ideas?