legohead6

im validating a form....i want it so if 1 or more of them is null then not to send the form....i have the rest of the code...just cant get that part

it wont work...heres the code [code]Code: if($first = NULL $last = NULL $gun = NULL $age = NULL $saying = NULL $email = NULL $phone = NULL $users = NULL $passs = NULL){ ......... [/code] how do i make it work?

[!--quoteo(post=360614:date=Apr 1 2006, 10:23 AM:name=jeliot)--][div class=\'quotetop\']QUOTE(jeliot @ Apr 1 2006, 10:23 AM) [snapback]360614[/snapback][/div][div class=\'quotemain\'][!--quotec--] Ok thanks for the info I'm a step closer i think........the query created this error to which I could not figure a solution. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '‘ )' at line 1 [/quote] you dont need the ! in your (!isset .... try it without that so "(isset"

ya i would like to be able to do that too....but if it did it would show your info like password and database stuff....that would lead to [u][i][b][!--coloro:#000099--][span style=\"color:#000099\"][!--/coloro--]MAJOR[!--colorc--][/span][!--/colorc--][/b][/i][/u] problems....lol...

how do i stop a form heading to a database from sending untill the user clicks submit? right know it sends whenever they enter or refresh the page! heres the code [code] <?php $host = "localhost"; $user = "--"; $pass = "--"; $db = "--"; $first=$_POST['first']; $last=$_POST['last']; $gun=$_POST['gun']; $age=$_POST['age']; $saying=$_POST['saying']; $email=$_POST['email']; $phone=$_POST['phone']; $users=$_POST['user']; $passs=$_POST['pass']; // open connection $connection = mysql_connect($host, $user,'$pass') or die ("Unable to connect!"); // select database mysql_select_db($db) or die ("Unable to select database!"); $query = "INSERT INTO members VALUES ('$first','$last','$gun','$age','$saying','$email','$phone','$users','$passs')"; mysql_query($query); ?></p> <p align="center">Player Info form!</p> <form method="POST" name="membership" action="Membership.php"> <p align="center">First name <input type="text" name="first" size="20"> Last Name:<input type="text" name="last" size="24"> <br><br> Phone#<input type="text" name="phone">(format= 000-0000) <p align="center"> Gun type:<input type="text" name="gun" size="36"><br> <br> Age:<input type="text" name="age" size="3"><br> <br> Saying:<br> <textarea rows="2" name="saying" cols="20"></textarea></p> <p align="center"> Current email address:<input type="text" name="email" size="36"> </p> <p align="center"> Desired Username:<input type="text" name="user" size="20"> </p> <p align="center"> Desired pass:<input type="password" name="pass" size="20"> </p> <p align="center"><input type="submit" value="Submit" name="B1"></p> </form> </body> </html>

how do i stop a form heading to a database from sending untill the user clicks submit? right know it sends whenever they enter or refresh the page! heres the code [code] <?php $host = "localhost"; $user = "--"; $pass = "--"; $db = "--"; $first=$_POST['first']; $last=$_POST['last']; $gun=$_POST['gun']; $age=$_POST['age']; $saying=$_POST['saying']; $email=$_POST['email']; $phone=$_POST['phone']; $users=$_POST['user']; $passs=$_POST['pass']; // open connection $connection = mysql_connect($host, $user,'$pass') or die ("Unable to connect!"); // select database mysql_select_db($db) or die ("Unable to select database!"); $query = "INSERT INTO members VALUES ('$first','$last','$gun','$age','$saying','$email','$phone','$users','$passs')"; mysql_query($query); ?></p> <p align="center">Player Info form!</p> <form method="POST" name="membership" action="Membership.php"> <p align="center">First name <input type="text" name="first" size="20"> Last Name:<input type="text" name="last" size="24"> <br><br> Phone#<input type="text" name="phone">(format= 000-0000) <p align="center"> Gun type:<input type="text" name="gun" size="36"><br> <br> Age:<input type="text" name="age" size="3"><br> <br> Saying:<br> <textarea rows="2" name="saying" cols="20"></textarea></p> <p align="center"> Current email address:<input type="text" name="email" size="36"> </p> <p align="center"> Desired Username:<input type="text" name="user" size="20"> </p> <p align="center"> Desired pass:<input type="password" name="pass" size="20"> </p> <p align="center"><input type="submit" value="Submit" name="B1"></p> </form> </body> </html>

[!--quoteo(post=359886:date=Mar 29 2006, 10:49 PM:name=warewolfe)--][div class=\'quotetop\']QUOTE(warewolfe @ Mar 29 2006, 10:49 PM) [snapback]359886[/snapback][/div][div class=\'quotemain\'][!--quotec--] Hej, try <?php $link = mysql_connect('localhost', 'user', 'pass); if (!$link) { die('Could not connect: ' . mysql_error()); } echo 'Connected successfully<br>'; mysql_select_db("test",$link"); $result = mysql_query(SELECT * FROM people",$link); while($row = mysql_fetch_array($result,MYSQL_NUM)) { foreach($row as $val) { echo'<p>$val</p>'; } } ?> [/quote] parse errors came up.....i dont really know the script so its hard for me to try to correct.... [!--quoteo(post=359890:date=Mar 29 2006, 11:00 PM:name=sambib)--][div class=\'quotetop\']QUOTE(sambib @ Mar 29 2006, 11:00 PM) [snapback]359890[/snapback][/div][div class=\'quotemain\'][!--quotec--] [code]<?php {     //attempt to connect to the database server     //if the attempt was successful     if (@mysql_connect('localhost', 'user', 'pass))) {              //attempt to select the mycms databse         //if the attempt was successful         if (@mysql_select_db("test")) {              //return true         return TRUE;                  //Or if the selection was unsuccessful         } else {                      //display error message             echo "<p>Unable to select the database .</p>";                          //Return False             return FALSE;         }              } else {              //Display the error message         echo "<p>Unable to connect to the database server</p>";              //return false         return FALSE;     } } $query = "SELECT * FROM people"; //put some other criteria in to refine your query $result = mysql_query ($query); // check to see how many rows we have. if we have 0 rows then nothing has returned if(mysql_num_rows($result) < 1) {     echo('<p>the is no data in the table!</p>'); } else {                   //run through the results of the query and put the result into an array called $row     while ($row = mysql_fetch_assoc($result)) { ?>//stop the while loop and display the records <p>here are the details of the field name<?= $row['fieldName'] ?></p> <!--change field name and fieldName for the correct names of the table fields. --> <?php      } //end the while loop ?> [/code] that should get you started [/quote] wow....umm this came up Parse error: parse error, unexpected T_STRING in /var/www/html/PHP/data.php on line 42 [!--quoteo(post=359887:date=Mar 29 2006, 10:49 PM:name=toplay)--][div class=\'quotetop\']QUOTE(toplay @ Mar 29 2006, 10:49 PM) [snapback]359887[/snapback][/div][div class=\'quotemain\'][!--quotec--] Please be more specific of what you need help with as it relates to databases. For basic connect, select, and fetch see tutorials and code example at the FAQ page link bellow. Look for my post there related to MySQL data retrieval. [a href=\"http://www.phpfreaks.com/forums/index.php?showtopic=31047\" target=\"_blank\"]http://www.phpfreaks.com/forums/index.php?showtopic=31047[/a] [/quote] Thanks i found the stuff...but how do i set up a query..(im new to databases and php)

ok so far heres my script <?php $link = mysql_connect('localhost', 'user', 'pass); if (!$link) { die('Could not connect: ' . mysql_error()); } echo 'Connected successfully<br>'; ?> know i want it to display information from the database "test" on table "people" please help me with the code!