kopman

Thank you for that, makes sense now. :)

I have inherited a website that has 40 pages each with the code for the menu in it. I want to remove that to it's own function in a separate file to make management easier. I have created the file and added the function which builds a $menu variable which is returned to the main file. The function adds line similar to below $menu .= "<img border='0' id='img70' src='images/nav_buttons/home_link.gif' height='20' width='156' alt='Home' onmouseover='FP_swapImg(1,0,/*id*/'img70',/*url*/'images/nav_buttons/home_active.gif')' onmouseout='FP_swapImg(0,0,/*id*/'img70',/*url*/'images/nav_buttons/home_link.gif')' onmousedown='FP_swapImg(1,0,/*id*/'img70',/*url*/'images/nav_buttons/home_hover.gif')' onmouseup='FP_swapImg(0,0,/*id*/'img70',/*url*/'images/nav_buttons/home_link.gif')' fp-style='fp-btn: Glass Capsule 1; fp-font-color-normal: #D82D01; fp-font-color-hover: #D82D01; fp-font-color-press: #D82D01; fp-justify-horiz: 0; fp-proportional: 0' fp-title='Home'></a></TD></tr>"; As you can see it includes calls to a javascript function to replace images when the cursor moves in and out of the menu button and the picture should change as you do it. These calls aren't working. Should I be approaching this differently or are the js functions not going to work when called in this way? Thanks. Peter