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stockdalep

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  1. Thanks for your time, God knows why it did not work for me first time around
  2. Hi I have a HTML email and inside this I need to use a PHP variable that contains a string with html line breaks inside it. Can this be done. Thanks for any help. $message =' <html> <body bgcolor="#FFFFCC" text="#000000"> <div align="center"> <h1>Thank you for registering</h1> <br> <table width="385" border="0" cellspacing="2" cellpadding="2" height="74"> <tr bgcolor="#CC9900"> <td>"$items"</td> </tr> </table> </div> </body> </html> ';
  3. Hi I have a while loop that just prints outsome values from a database like this I need to put this into an email. I know the basics of php mail but cannot figure out how to get this into the body of the email. Thaks for any help. while($row = @mysql_fetch_array($order)) { // Increment the total cost of all items $totalCost += ($row["qty"] * $row["itemPrice"]); ?> <tr> <td width="15%" height="25"> <font face="verdana" size="1" color="black"> <?php echo $row["qty"]; ?> </font> </td> <td width="55%" height="25"> <b><font face="verdana" size="1" color="black"> <?php echo $row["itemName"]; ?> </font> </td> <td width="20%" height="25"> <b><font face="verdana" size="1" color="black"> £<?php echo number_format($row["itemPrice"], 2, ".", ","); ?> </font> </td> <td width="10%" height="25"> </td> </tr> <?php } // Display the total ?> <tr> <td width="100%" colspan="4"> <hr size="2" color="#FF6600" NOSHADE> </td> </tr> <tr> <td width="70%" colspan="2"> <td width="30%" colspan="2"> <font face="verdana" size="2" color="black"> <b>Total: £<?php echo number_format($totalCost, 2, ".", ","); ?></b> <p>
  4. I have three pages page1.php has a radio button so has page2.php. I need to get the values of both buttons to display.php. I can get page2.php to the display.php page using the echo $_POST['myradio']; but this will not work for the radio button value in page1.php This is the order in which the pages are selected. page1.php page2.php display.php Thanks for any help
  5. sameday and tuesday still conflict with one another in Mozzila Firefox.
  6. I have this small piece of code inside a form it works fine in IE6 but inside Mozzila Firefox sameday and tuesday seem to become one. Example if I select tuesay sameday gets selected. Thanks for any ideas/help Form Address www.linfordfc.com/delivery_pickup_form.php <?php $timenow=date("Hi"); if($timenow < 1200) { ?> <input type="radio" name="delivery_day" value="sameday" /> <?php echo("Same Day"); } ?> <input type="radio" name="delivery_day" value="tuesday" /> <?php echo date('l jS F Y', strtotime('+2 days'))?></label> <label> <input type="radio" name="delivery_day" value="wednesday" /> <?php echo date('l jS F Y', strtotime('+3 days'))?></label> <label></label> </span></strong></div></td> </tr> <tr> <td><div align="center"><span class="style27"><strong><span class="style2"> <label> <input type="radio" name="delivery_day" value="thursday" /> <?php echo date('l jS F Y', strtotime('+4 days'))?></label> <label> <input type="radio" name="delivery_day" value="friday" /> <?php echo date('l jS F Y', strtotime('+5 days'))?></label> <label> <input type="radio" name="delivery_day" value="saturday" /> <?php echo date('l jS F Y', strtotime('+6 days'))?></label> </span></strong></span></div></td> </tr> <tr> <td bgcolor="#FFFFFF"> </td> </tr>
  7. Hi I have a site that requires it users to select a delivery time. But I need to ensure that if the time has gone past 10 am they cannot select this day. I cannot figure out the question marks. if(strtotime("now") > ???????){ echo("no"); } else { echo("yes"); Thanks for any help.
  8. Hi I have a database and shopping cart, the items are selected by using the session_id in a cookie. So if you log out your cart stays intact. select * from cart inner join household on cart.itemName = household.itemName where cart.cookieId = '" . GetCartId() . "'"); GetCartId() runs at first to check if the cookie exists or not, if not create a new one. But when the cookie has expired it writes another one which I have checked and it is a different session_id inside so in theory the last order in the database can now not be selected because the session_id that the SELECT statement uses has changed. But it still appears in the cart. I have echoed out the GetCartId() and it is different from the database cookieId field so I have no idea how this is happening. The only way of getting rid of the last order is to delete it from the database. Thanks for any help.
  9. Thanks a lot worked great cheers.
  10. Hi I am trying to populate a list\menu from a database with php if I run the code below it works fine. Except if I want to run it inside the table where I need it then I get the List\menu but its empty ?. <?php include "config.php"; $conn = mysql_connect("$db_host", "$db_user", "$db_pass") or die(mysql_error()); $result = mysql_query("SELECT * FROM area"); //start the select box echo '<select name="select">'; while ($row=mysql_fetch_assoc($result)){ //iterate through outputting options echo '<option value="'.$row['area'].'">'; } //close the select box echo '</select>'; ?> +++++++++++++++++++++++++++++++++++++++++++++++++++++ Inside the table its run as <tr> <th scope="row"><div align="right">Collection Area </div></th> <td> <?php include "config.php"; $conn = mysql_connect("$db_host", "$db_user", "$db_pass") or die(mysql_error()); $result = mysql_query("SELECT * FROM area"); //start the select box echo '<select name="select">'; while ($row=mysql_fetch_assoc($result)){ //iterate through outputting options echo '<option value="'.$row['area'].'">'; } //close the select box echo '</select>'; ?> </td> </tr> Thanks for any help
  11. Solved it with select from * cart inner join mensdc on cart.itemId = mensdc.itemId union all select from * cart inner join items on cart.itemId = items.itemId
  12. If I run it with just one join I get Resource id #4 With both we get nothing in the variable Resource id #3
  13. Hi I have 3 Tables as below I am trying to join both mens_dc and items tables to cart. If I use this sql ========================================================= $result = mysql_query("select * from cart inner join items on cart.itemId = items.itemId where cart.cookieId = '" . GetCartId() . "' order by items.itemName asc"); ========================================================= We get the records from the items table but I cannot get both tables if I try ========================================================= select * from cart inner join items on cart.itemId = items.itemId inner join items on cart.itemId = items.itemId where cart.cookieId = '" . GetCartId() . "' order by items.itemName asc ===================================================== We then get nothing any ideas would be gratefully received Thanks. ====================================== Table Cart |cartId | cookieId | itemId | qty | Data 18 12344 2 1 19 12344 15 3 ====================================== Table items |itemId |itemName | itemDesc | itemPrice | Data 2 Trouser Trouser 5.50 ====================================== Table mens_dc |itemId |itemName | itemDesc | itemPrice | Data 15 Curtain Curtain 26.00 ======================================
  14. This is what we have now but it still does not work. $result = mysql_query("SELECT * FROM cart inner JOIN items ON cart.itemId = items.itemId inner JOIN mens_dc ON mens_dc.itemId = mens_dc.itemId WHERE cart.cookieId = GetCartId()"); Original code $result = mysql_query("select * from cart inner join items on cart.itemId = items.itemId where cart.cookieId = '" . GetCartId() . "' order by items.itemName asc");
  15. Hi Could anyone help me with this I need to join one more table to this query named mens_dc I have tried various syntex but to no avail. $result = mysql_query("select * from cart inner join items on cart.itemId = items.itemId where cart.cookieId = '" . GetCartId() . "' order by items.itemName asc"); Thanks for any help
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