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balkan7

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Posts posted by balkan7

    Jquery Image Hover

    in Javascript Help

    Posted

    Hello

    I'm trying to make jquery hover images but show me nothing, where is my mistake ?

     

    gallery.html

    <html>
<head>
<title>Test</title>
<link rel="stylesheet" href="style.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script src="js/default.js"></script>
</head>
<body>
<div class="gallery">
	 	 <ul class="items">
	 	 	<ul>
     	 <li><span class="img_frame"><a href="img/s6300159.jpg"><img src="img/test1.jpg" /></a></span><div class="img_desc"><span>22</span></div></li>
     	 <li><span class="img_frame"><a href="img/s6300159.jpg"><img src="img/test1.jpg" /></a></span><div class="img_desc"><span>23</span></div></li>
     	 <li><span class="img_frame"><a href="img/s6300159.jpg"><img src="img/test1.jpg" /></a></span><div class="img_desc"><span>24</span></div></li>
      </ul>
      </ul>
</div>
</body>
</html>

     

    style.css

    /*
GALLERY STYLES
*/

.gallery {overflow:hidden; width:1000px;}
.gallery .items { margin-bottom:50px; height:320px; }
.gallery .items li { position:relative; float:left;  width:290px; height:180px; margin-right:38px; margin-bottom: 30px; }
.gallery .items li img { width:277px; height:165px; }

.img_desc {
position: absolute;
  display: block;
  top: 10px; 
text-shadow: 1px 1px 0 #ffffff;
color: #262626;  
background: url(img/benefits_on.png) repeat;
width: 36px;
right: 5px;
text-align: center;
}


.img_frame {
  margin-top:3px;
    padding:1px;
    display:inline-block;
    line-height:0px;
    background:#fff;
    border:1px solid #ccc;
}

.img_frame img {
    padding:1px;
    border:4px solid #f2f1f0;
}
.img_frame a { display:block; }

.hover_image { background:url("img/preview_image.png") center center no-repeat; }

     

    default.js

    <!-- Image hover effect -->
function image_hover(frame){
    var link_content = jQuery(frame).find('a[href^=http], a[href*=www], a[href=#], a[href$=html], a[href$=php], a[href$=asp], a[href$=htm], a[href$=shtml], a[href$=aspx]');
    var image_content = jQuery(frame).find('a[href$=jpg], a[href$=png], a[href$=gif], a[href$=jpeg]');
    var video_content = jQuery(frame).find('a[href*=vimeo], a[href*=youtube], a[href*=swf], a[href*=flv], a[href*=avi], a[href*=mov], a[href*=mpg]');
    
    link_content.addClass("hover_link");
    image_content.removeClass("hover_link").addClass("hover_image");
    video_content.removeClass("hover_link").addClass("hover_video");
    
jQuery(frame).find("a > img").hover(
	function() {
	    if(!jQuery(this).parent().hasClass("no_hover")){
			jQuery(this).stop().animate({"opacity": ".6"}, "400");
		}
	},
	function() {
		jQuery(this).stop().animate({"opacity": "1"}, "400");
});
    
    jQuery(frame).children("a.no_hover").removeClass("hover_image");
    return false;
}

jQuery(function(){

    image_hover('.img_frame');
});

    Function Add Code to HEAD

    in PHP Coding Help

    Posted

    Maybe my mistake, i review my code but here no errors, why show me empty delimiter :confused:

     

    header_includes.php

    <?php
$page_head_tags = "";

function add_to_head($tag=""){
global $page_head_tags;

if(!stristr($page_head_tags, $tag)){
	$page_head_tags .= $tag."\n";
}
}?>

     

    header.php

    <?php
include("header_includes.php");
?>
<html>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<head>
<meta http-equiv="Content-Language" content="en-us">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title><?php echo EMS_CAD; ?></title>
<meta name="description" content="EMS-CAD, Arhitektura">
<meta name="keywords" content="EMS-CAD, Arhitektura">
<link rel="stylesheet" href="stil.css" type="text/css" media="screen" />
<?php if (function_exists("add_to_head")) { echo add_to_head(); } ?>
</head>

<body>

<table class="table" cellspacing="0" cellpadding="0" align="center">
    <tr>
        <td valign="top" nowrap>        
<table class="table" cellspacing="0" cellpadding="0">
	<tr>
		<td>
		<img border="0" src="sliki/header1.jpg" width="400" height="200"></td>
		<td class="header"><div class="top">
		<a href="index.php" title="<?php echo HOME;?>" class="prozirnost"><img src="sliki/naslovna.gif" border="0" alt="<?php echo HOME;?>"></a> <img src="sliki/tocki.gif"> <a href="kontakt.php" title="<?php echo MSG;?>" class="prozirnost"><img src="sliki/mail.gif" border="0" alt="<?php echo MSG;?>"></a> <img src="sliki/tocki.gif">
		<a href="#" title="<?php echo MAP;?>" class="prozirnost"><img src="sliki/mapa.gif" border="0" alt="<?php echo MAP;?>"></a></div></td>
	</tr>
</table>

     

    index.php

    <?php
include_once("header.php");
add_to_head("<link rel='stylesheet' href='blue.css' type='text/css' media='screen' />");?>

    Function Add Code to HEAD

    in PHP Coding Help

    Posted

    Hi, i need help for add custom code like javascript or css to head, i have function for it but i'm confused  :confused:, here is code:

     

    header.php

    <?php
<html>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<head>
<meta http-equiv="Content-Language" content="en-us">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title><?php echo EMS_CAD; ?></title>
<link rel="stylesheet" href="style.css" type="text/css" media="screen" />
<?php if (function_exists("add_to_head")) { echo add_to_head(); } ?>
</head>?>

    includes.php

    <?php
$page_head_tags = "";
function add_to_head($tag=""){
global $page_head_tags;

if(!stristr($page_head_tags, $tag)){
	$page_head_tags .= $tag."\n";
}
}
?>

    index.php

    <?php add_to_head("<link rel='stylesheet' href='blue.css" type='text/css' media='screen' />");?>

    Chat Messages

    in Javascript Help

    Posted

    Here is explame, when user send msg status in datebase is 0, when i confirm msg for show it then status is 1, and ajax check in datebase messages with status 1, if find show it but if we havent new messages ajax do not show nothing ...

    like:

     

    msg 10

    msg 9

    msg 8

     

    i hope undestand me ...

    Chat Messages

    in Javascript Help

    Posted

    Hi,

    Does someone can help me with this code to get the results that the messages is displayed one time and do not duplicate it, if it be shown whether it is possible to change the status, for example, if status of message in datebase is 1 after it is shown to change the status of the 2?

     

    ajax.js

    function display_msg(){
doc_id("new_msg").innerHTML="<br />";
makeHttpRequest(siteurl+"/ajax.php?a=new_msg",function(response){doc_id("new_msg").innerHTML+=response;},false);

  setInterval("display_msg()", 10000);
}

     

    php

    <?php
$result = mysql_query("SELECT * FROM ".DB_CHAT." WHERE status='1' ORDER BY date LIMIT 0,1");
while($data = mysql_fetch_array($result)){
  $user = $data['user'];
          $msg = $data['msg'];
          echo $user." - ".$msg;
}
?>

    JQuery question

    in Javascript Help

    Posted

    i use jquery message ticker to display the message, but whether it is possible that the new messages to display without refresh with jQuery?

     

    jquery.js

    (function($) {
$.fn.SmS = $.fn.sms = function(delay)
{
delay = delay || 4000;
initTicker = function(el)
{
	stopTicker(el);
	el.items = $("li", el);
	// hide all items (except first one)
	el.items.not(":eq(0)").hide().end();
	// current item
	el.currentitem = 0;
	startTicker(el);
};
startTicker = function(el)
{
	el.tickfn = setInterval(function() { doTick(el) }, delay)
};
stopTicker = function(el)
{
	clearInterval(el.tickfn);
};
pauseTicker = function(el)
{
	el.pause = true;
};
resumeTicker = function(el)
{
	el.pause = false;
};
doTick = function(el)
{
	// don't run if paused
	if(el.pause) return;
	// pause until animation has finished
	el.pause = true;
	// hide current item
	$(el.items[el.currentitem]).fadeOut("slow",
		function()
		{
			$(this).hide();
			// move to next item and show
			el.currentitem = ++el.currentitem % (el.items.size());
			$(el.items[el.currentitem]).fadeIn("slow",
				function()
				{
					el.pause = false;
				}
			);
		}
	);
};
this.each(
	function()
	{
		if(this.nodeName.toLowerCase()!= "ul") return;
		initTicker(this);
	}
)
.addClass("sms")
.hover(
	function()
	{
		// pause if hovered over
		pauseTicker(this);
	},
	function()
	{
		// resume when not hovered over
		resumeTicker(this);
	}
);
return this;
};

})(jQuery);

     

    test.html

    <script type='text/javascript'>
$(document).ready(
	function() {
		$('#sms').SmS();
		$('#sms').show('fast');
     });
	}
);
</script>
<div id='sms'></div>

    Parsing Help

    in PHP Coding Help

    Posted

    thank you this is working, but whether this can be sorted by ID or by <exch>

     

    <exchange>

    <id>978</id>

    <expr>MKD</expr>

    <exch>EUR</exch>

    <amount>1</amount>

    <value>61.4106</value>

    </exchange>

    Parsing Help

    in PHP Coding Help

    Posted

    need help with displaying only those who have the amount 1

     

    explame:

     

    AUD - 1 - 31.0390

    CAD - 1 - 37.3090

    DKK - 100 - 824.0158

    JPY - 100 - 49.4051

     

    code:

    <?php // displays all the file nodes
if(!$curencyexchange=simplexml_load_file('http://www.xxxx.com/xxxxx.asp')){
    trigger_error('Error reading XML file',E_USER_ERROR);
}
foreach ($curencyexchange->exchange as $exchange) {
echo "".$exchange->exch." - ".$exchange->amount." - ".$exchange->value."<br />";
} ?>

    [SOLVED] Order by top rated

    in MySQL Help

    Posted

    i have to try whit this one but again whiout result:

    SELECT tp.*, ta.*, SUM(tr.rating_vote) AS sum_rating, COUNT(tr.rating_item_id) AS count_votes
	FROM ".DB_PHOTOS." tp
	LEFT JOIN ".DB_PHOTO_ALBUMS." ta USING (album_id)
	LEFT JOIN ".DB_RATINGS." tr ON tr.rating_item_id = tp.photo_id AND tr.rating_type='P'
	GROUP BY tp.photo_id ORDER BY count_votes DESC LIMIT ".$_GET['rowstart'].",".$settings['thumbs_per_page']

    [SOLVED] Order by top rated

    in MySQL Help

    Posted

    Thanks for your post,

    but forgot that I pasted my query that should be little to be changed because not show me toprated.

     

    SELECT tp.*, SUM(tr.rating_vote) AS sum_rating, COUNT(tr.rating_item_id) AS count_votes
				FROM ".DB_PHOTOS." tp
				LEFT JOIN ".DB_RATINGS." tr ON tr.rating_item_id = tp.photo_id AND tr.rating_type='P'
				GROUP BY photo_id ORDER BY count_votes DESC LIMIT ".$_GET['rowstart'].",".$settings['thumbs_per_page']

    Hi

     

    Looks like you need to do a join of the 2 tables, and count the number of resulting rows grouped by the entries on the photos table.

     

    Something like this:-

     

    SELECT photo_id, photo_name, photo_thumb, photo_file, photo_date, COUNT(*) AS RatingCount
FROM photos a JOIN ratings b ON a.photo_id = b.rating_item_id
GROUP BY photo_id, photo_name, photo_thumb, photo_file, photo_date
ORDER BY RatingCount

     

    All the best

     

    Keith

    [SOLVED] Order by top rated

    in MySQL Help

    Posted

    hi guys, i need help to sort pictures with top rated.

     

    datebase: photos

    photo_id

    photo_name

    photo_thumb

    photo_file

    photo_date

     

    datebase: ratings

    rating_id

    rating_item_id

    rating_type

    rating_user

    rating_vote

    rating_datestamp

    [SOLVED] Working with SESSIONS

    in PHP Coding Help

    Posted

    hi guys,

    I tested the code on my localhost and it works, but when I tested on my site that will not show me $_SESSION[ 'username'];

     

    login.php

    <?php 
session_start();
session_destroy();

$show = "";

if (isset($_POST['login'])) { 
$username = $_POST['username'];
$md5_password = md5($_POST['password']); 

$result = mysql_query("SELECT * FROM admin WHERE username='$username' AND password='$md5_password'");
  if(dbrows($rezultat) != 0){
    session_register("username"); 
    header("location:admin/index.php"); 
   exit;
  } else {
  $show = $lang['login-005'];
  }
} ?>

     

    admin/index.php

    <?php 
session_start(); 
if (!session_is_registered("username")) {
header("location:../index.php");
}
echo $_SESSION[ 'username'];
?>

    Function not working on IE

    in PHP Coding Help

    Posted

    this function i use for YouTube videos only works in FF and IE shows me the errors and not to open the popup, how can I fix this error.

     

    <?php
function displayVideos($Videos, $maxVideos=NULL,$columns=4,$rows=NULL){
  	global $locale;
  	// Popup
      echo "<script type='text/javascript'>
	  function open(url, title,w,h) {
       var left = (screen.width/2)-(w/2);
       var top = (screen.height/2)-(h/2);
       var targetWin = window.open (url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=yes, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
      } </script>";
       // End
    if($maxVideos==Null){
      $maxVideos=count($Videos);
    }
    if(!is_int($maxVideos)){
      trigger_error("Maximum number of videos to show must be an integer, not ".$maxVideos,E_USER_WARNING);
      return 1;
    }
    if($rows==NULL){
      $rows=ceil($maxVideos/$columns);
    }

    echo '<table align="center" width="100%" border="0" cellspacing="5" cellpadding="5" style="font-family:Verdana, Arial, Helvetica, sans-serif; font-size:10px;">';
    $i = 0;
    //print_r($Videos[0]);
    $video=$Videos[$i];

    for($r=0; $r < $rows; $r++) {
      $video=$Videos[$i];
      echo '<tr>';
      for($c=0; $c < $columns; $c++) {
echo '<td valign="top" width="130">';
if($i < $maxVideos && $Videos[$i]){
  $video=$Videos[$i];
  if (isset($_GET['s']) == "mr") {
  	
    echo "<a href=\"javascript: void(0);\" onClick=\"open('pogledni.php?video=".$video->url."', '".$video->title."', '620', '480');\"><img src='http://i.ytimg.com/vi/".$video->url."/default.jpg' border='0' width='130' height='97' /><br />".$video->title."</a><br />".$locale['yt-012']." ".$video->postdate."<br />".$locale['yt-013']." ".$video->views."";
  }
  else {
    echo "<a href=\"javascript: void(0);\" onClick=\"open('pogledni.php?video=".$video->url."', '".$video->title."', '620', '480');\"><img src='http://i.ytimg.com/vi/".$video->url."/default.jpg' border='0' width='130' height='97' /><br />".$video->title."</a><br />".$locale['yt-012']." ".$video->postdate."<br />".$locale['yt-013']." ".$video->views."<br />";
    if ($video->star1!=""){
      echo $locale['yt-014'].'<img src="'.$video->star1.'" /><img src="'.$video->star2.'" /><img src="'.$video->star3.'" /><img src="'.$video->star4.'" /><img src="'.$video->star5.'" />';
    }
    else{
      echo '<br/>';
    }
    echo '<br /> ';
  }
}
echo '</td>';
$i++;

      }
    }
    echo '</table><div align="right" style="padding-right: 25px">';
  }
?>

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