deezerd

problem solved file_put_contents('filename.ext', $GLOBALS["HTTP_RAW_POST_DATA"]);

Hi here is the thing: I have a flash application that creates a jpeg file and then call a php file to send the jpeg to the client with a classic browser download window The jpeg file is sent on the fly with the variable $GLOBALS["HTTP_RAW_POST_DATA"] I would like to copy this file in a directory before it is sent to the web browser with the header() function but I have no idea of how to do this I tried it doing something like copy('myphpfile.php','foo.jpg') but I get this warning error: Warning: copy(jpg_encoder_download.php?name=sketch.jpg) [function.copy]: failed to open stream Here is the content of the php file called by the flash application: how can I copy the content of $GLOBALS["HTTP_RAW_POST_DATA"] on my server before to send it on the fly? <?php if ( isset ( $GLOBALS["HTTP_RAW_POST_DATA"] )) { $im = $GLOBALS["HTTP_RAW_POST_DATA"]; header('Content-Type: image/jpeg'); header("Content-Disposition: attachment; filename=".$_GET['name']); echo $im; } else echo 'An error occured.'; ?> many thanks for your help

Hi I'm using the SimpleXMLElement class to get some info of an rss feed The thing is I get nothing about the info included in the namespaces (<media:title> <media:content> <media:credit>) when I write print_r($xml) For example in this code, what should I do to the info in the media node: [code]<media:player url="http://youtube.com/?v=hjlQfMECSdA"/> <media:thumbnail url="http://sjl-static10.sjl.youtube.com/vi/hjlQfMECSdA/2.jpg" width="120" height="90"/>[/code] thanks!